482. License Key Formatting

Easy

You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes.

Given a number K, we would want to reformat the strings such that each group contains exactly K characters, except for the first group which could be shorter than K, but still must contain at least one character. Furthermore, there must be a dash inserted between two groups and all lowercase letters should be converted to uppercase.

Given a non-empty string S and a number K, format the string according to the rules described above.

Example 1:

Input: S = "5F3Z-2e-9-w", K = 4

Output: "5F3Z-2E9W"

Explanation: The string S has been split into two parts, each part has 4 characters.
Note that the two extra dashes are not needed and can be removed.

Example 2:

Input: S = "2-5g-3-J", K = 2

Output: "2-5G-3J"

Explanation: The string S has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.

Note:

  1. The length of string S will not exceed 12,000, and K is a positive integer.
  2. String S consists only of alphanumerical characters (a-z and/or A-Z and/or 0-9) and dashes(-).
  3. String S is non-empty.
package leetcode.easy;

public class LicenseKeyFormatting {
public String licenseKeyFormatting(String S, int K) {
StringBuffer sb = new StringBuffer();
int count = 0;
for (int i = S.length() - 1; i >= 0; i--) {
char c = S.charAt(i);
if (c != '-') {
if (count > 0 && count % K == 0) {
sb.append('-');
}
sb.append(c);
count++;
}
}
return sb.reverse().toString().toUpperCase();
} @org.junit.Test
public void test() {
System.out.println(licenseKeyFormatting("5F3Z-2e-9-w", 4));
System.out.println(licenseKeyFormatting("2-5g-3-J", 2));
}
}

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