package com.code;

import java.util.Arrays;

public class Test04_2 {
public static int solution(int[] A) {
int size = A.length;
if(size == 1){
return A[0]==1?1:0;
}
Arrays.sort(A);
for(int i=0;i<size;i++){
if(A[i]!=i+1){
return 0;
}
}
return 1;
}
public static void main(String[] args) {
int [] a = {1,1,3,4};
System.out.println(solution(a));
}
} /**
1. PermCheck 桃花顺检验
Check whether array A is a permutation.
A non-empty zero-indexed array A consisting of N integers is given. A permutation is a sequence containing each element from 1 to N once, and only once. For example, array A such that: A[0] = 4
A[1] = 1
A[2] = 3
A[3] = 2
is a permutation, but array A such that: A[0] = 4
A[1] = 1
A[2] = 3
is not a permutation, because value 2 is missing. The goal is to check whether array A is a permutation. Write a function: class Solution { public int solution(int[] A); } that, given a zero-indexed array A, returns 1 if array A is a permutation and 0 if it is not. For example, given array A such that: A[0] = 4
A[1] = 1
A[2] = 3
A[3] = 2
the function should return 1. Given array A such that: A[0] = 4
A[1] = 1
A[2] = 3
the function should return 0. Assume that: N is an integer within the range [1..100,000];
each element of array A is an integer within the range [1..1,000,000,000].
Complexity: expected worst-case time complexity is O(N);
expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.
*/

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