一、结构

For example, you can map a class hierarchy to a single table, but, for a particular subclass, switch to a separate table with a foreign key–mapping strategy, just as with table-per-subclass.

二、代码

1.

 package org.jpwh.model.inheritance.mixed;

 import org.jpwh.model.Constants;

 import javax.persistence.DiscriminatorColumn;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Inheritance;
import javax.persistence.InheritanceType;
import javax.validation.constraints.NotNull; @Entity
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name = "BD_TYPE")
public abstract class BillingDetails { @Id
@GeneratedValue(generator = Constants.ID_GENERATOR)
protected Long id; @NotNull
protected String owner; protected BillingDetails() {
} protected BillingDetails(String owner) {
this.owner = owner;
} public Long getId() {
return id;
} public String getOwner() {
return owner;
} public void setOwner(String owner) {
this.owner = owner;
}
}

2.

 package org.jpwh.model.inheritance.mixed;

 import javax.persistence.Column;
import javax.persistence.DiscriminatorValue;
import javax.persistence.Entity;
import javax.persistence.PrimaryKeyJoinColumn;
import javax.persistence.SecondaryTable;
import javax.validation.constraints.NotNull; @Entity
@DiscriminatorValue("CC")
@SecondaryTable(
name = "CREDITCARD",
pkJoinColumns = @PrimaryKeyJoinColumn(name = "CREDITCARD_ID")
)
public class CreditCard extends BillingDetails { @NotNull // Ignored by JPA for DDL, strategy is SINGLE_TABLE!
@Column(table = "CREDITCARD", nullable = false) // Override the primary table
protected String cardNumber; @Column(table = "CREDITCARD", nullable = false)
protected String expMonth; @Column(table = "CREDITCARD", nullable = false)
protected String expYear; // ...
public CreditCard() {
super();
} public CreditCard(String owner, String cardNumber, String expMonth, String expYear) {
super(owner);
this.cardNumber = cardNumber;
this.expMonth = expMonth;
this.expYear = expYear;
} public String getCardNumber() {
return cardNumber;
} public void setCardNumber(String cardNumber) {
this.cardNumber = cardNumber;
} public String getExpMonth() {
return expMonth;
} public void setExpMonth(String expMonth) {
this.expMonth = expMonth;
} public String getExpYear() {
return expYear;
} public void setExpYear(String expYear) {
this.expYear = expYear;
}
}

3.

 package org.jpwh.model.inheritance.mixed;

 import javax.persistence.DiscriminatorValue;
import javax.persistence.Entity;
import javax.validation.constraints.NotNull; @Entity
@DiscriminatorValue("BA")
public class BankAccount extends BillingDetails { @NotNull
protected String account; @NotNull
protected String bankname; @NotNull
protected String swift; public BankAccount() {
super();
} public BankAccount(String owner, String account, String bankname, String swift) {
super(owner);
this.account = account;
this.bankname = bankname;
this.swift = swift;
} public String getAccount() {
return account;
} public void setAccount(String account) {
this.account = account;
} public String getBankname() {
return bankname;
} public void setBankname(String bankname) {
this.bankname = bankname;
} public String getSwift() {
return swift;
} public void setSwift(String swift) {
this.swift = swift;
}
}

4.At runtime, Hibernate executes an outer join to fetch BillingDetails and all sub-class instances polymorphically:

 select
ID, OWNER, ACCOUNT, BANKNAME, SWIFT,
EXPMONTH, EXPYEAR, CARDNUMBER,
BD_TYPE
from
BILLINGDETAILS
left outer join CREDITCARD on ID=CREDITCARD_ID

5. If you have an exceptionally wide class hierarchy, the outer join can become a problem. Some data-base systems (Oracle, for example) limit the number of tables in an outer join operation. For a wide hierarchy, you may want to switch to a different fetching strategy that executes an immediate second SQL select instead of an outer join.

Switching the fetching strategy for this mapping isn’t available in JPA or Hibernate annotations at the time of writing, so you have to map the class in a native Hibernate XML file:

FetchSelect.hbm.xml

 <?xml version="1.0"?>
<hibernate-mapping xmlns="http://www.hibernate.org/xsd/orm/hbm"
package="org.jpwh.model.inheritance.mixed"
default-access="field"> <class name="BillingDetails"
abstract="true">
<id name="id">
<generator class="native"/>
</id>
<discriminator column="BD_TYPE" type="string"/>
<property name="owner"
not-null="true"/> <subclass name="CreditCard"
discriminator-value="CC">
<join table="CREDITCARD" fetch="select">
<key column="CREDITCARD_ID"/>
<property name="cardNumber"
column="CARDNUMBER"
not-null="true"/> <property name="expMonth"
column="EXPMONTH"
not-null="true"/>
<property name="expYear"
column="EXPYEAR"
not-null="true"/>
</join>
</subclass> <subclass name="BankAccount"
discriminator-value="BA">
<property name="account"
not-null="false"/>
<property name="bankname"
not-null="false"/>
<property name="swift"
not-null="false"/>
</subclass>
</class> </hibernate-mapping>

三、优点

1.Remember that InheritanceType.SINGLE_TABLE enforces all columns of sub-classes to be nullable. One of the benefits of this mapping is that you can now declare columns of the CREDITCARD table as NOT NULL , guaranteeing data integrity.

四、缺点

代码中的第5点

JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-006Mixing inheritance strategies(@SecondaryTable、@PrimaryKeyJoinColumn、<join fetch="select">)的更多相关文章

  1. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-005Table per subclass with joins(@Inheritance(strategy = InheritanceType.JOINED)、@PrimaryKeyJoinColumn、)

    一.结构 The fourth option is to represent inheritance relationships as SQL foreign key associations. Ev ...

  2. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-003Table per concrete class with unions(@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)、<union-subclass>)

    一.代码 1. package org.jpwh.model.inheritance.tableperclass; import org.jpwh.model.Constants; import ja ...

  3. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-002Table per concrete class with implicit polymorphism(@MappedSuperclass、@AttributeOverride)

    一.结构 二.代码 1. package org.jpwh.model.inheritance.mappedsuperclass; import javax.persistence.MappedSup ...

  4. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-004Table per class hierarchy(@Inheritance..SINGLE_TABLE)、@DiscriminatorColumn、@DiscriminatorValue、@DiscriminatorFormula)

    一.结构 You can map an entire class hierarchy to a single table. This table includes columns for all pr ...

  5. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-001Hibernate映射继承的方法

    There are four different strategies for representing an inheritance hierarchy: Use one table per co ...

  6. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-009Polymorphic collections(@OneToMany(mappedBy = "user")、@ManyToOne、)

    一.代码 1. package org.jpwh.model.inheritance.associations.onetomany; import org.jpwh.model.Constants; ...

  7. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-008Polymorphic many-to-one associations(@ManyToOne、@Inheritance、)

    一.结构 二.代码 1. package org.jpwh.model.inheritance.associations.manytoone; import org.jpwh.model.Consta ...

  8. JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-007Inheritance of embeddable classes(@MappedSuperclass、@Embeddable、@AttributeOverrides、、)

    一.结构 二.代码 1. package org.jpwh.model.inheritance.embeddable; import javax.persistence.MappedSuperclas ...

  9. JavaPersistenceWithHibernate第二版笔记-第五章-Mapping value types-007UserTypes的用法(@org.hibernate.annotations.Type、@org.hibernate.annotations.TypeDefs、CompositeUserType、DynamicParameterizedType、、、)

    一.结构 二.Hibernate支持的UserTypes接口  UserType —You can transform values by interacting with the plain JD ...

随机推荐

  1. Project://CRM

    初始化 考勤 录入成绩 查看成绩 待续...

  2. Requests 库

    Requests 库的两个重要的对象:(Request , Response) Response对象的属性: import requests r =requests.get('http://www.b ...

  3. 详解linux互斥锁 pthread_mutex和条件变量pthread_cond

    [cpp] view plaincopy ============================================================= int pthread_creat ...

  4. CF Round 542 Div1.

    B. Wrong Answer 构造一个长度为 2000 的数组,满足最大“子段和 $\times$ 子段长度”比最大子段和刚好大 k sol: 一个比较好的构造方法: 令数组总和为 $S$,然后构造 ...

  5. tableau-创建帕累托图

    参考文献:https://onlinehelp.tableau.com/current/pro/desktop/zh-cn/pareto.html 帕累托图是一种按发生频率排序的特殊直方图.在质量管理 ...

  6. 【LeetCode】075. Sort Colors

    Given an array with n objects colored red, white or blue, sort them so that objects of the same colo ...

  7. python的编解码问题

    http://blog.chinaunix.net/uid-27838438-id-4227131.html

  8. 2017/2/22怎么判断mongodb服务已经启动了?

    打开任务管理器,看看服务下面是否有个MongoDB,有就表示成功

  9. git之切换分支出现的问题

    当在其他分支,如test分支开发的时候,新增了文件夹等目录结构.开发完成后,切换会master分支. 如果出现“Deletion of directory '***' failed. Should I ...

  10. 蓝桥杯 算法训练 ALGO-152 8-2求完数

     算法训练 8-2求完数   时间限制:50.0s   内存限制:256.0MB 问题描述 如果一个自然数的所有小于自身的因子之和等于该数,则称为完数.设计算法,打印1-9999之间的所有完数. 样例 ...