HDOJ-三部曲-多重背包-1014-Cash Machine
通过这道题我基本了解了利用二进制对多重背包问题进行优化的思想。
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 24191 | Accepted: 8466 |
Description
N=3, n1=10, D1=100, n2=4, D2=50, n3=5, D3=10
means the machine has a supply of 10 bills of @100 each, 4 bills of @50 each, and 5 bills of @10 each.
Call cash the requested amount of cash the machine should deliver and write a program that computes the maximum amount of cash less than or equal to cash that can be effectively delivered according to the available bill supply of the machine.
Notes: @ is the symbol of the currency delivered by the machine. For instance, @ may stand for dollar, euro, pound etc.
Input
cash N n1 D1 n2 D2 ... nN DN
where 0 <= cash <= 100000 is the amount of cash requested, 0 <=N <= 10 is the number of bill denominations and 0 <= nk <= 1000 is the number of available bills for the Dk denomination, 1 <= Dk <= 1000, k=1,N. White spaces can occur freely between the numbers in the input. The input data are correct.
Output
Sample Input
735 3 4 125 6 5 3 350
633 4 500 30 6 100 1 5 0 1
735 0
0 3 10 100 10 50 10 10
Sample Output
735
630
0
0
Hint
In the second case the bill supply of the machine does not fit the exact amount of cash requested. The maximum cash that can be delivered is @630. Notice that there can be several possibilities to combine the bills in the machine for matching the delivered cash.
In the third case the machine is empty and no cash is delivered. In the fourth case the amount of cash requested is @0 and, therefore, the machine delivers no cash.
Source
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
int cash,n;
while(cin>>cash>>n)
{
int i,j,k=0,num[11],den[11],sc[10000];
int *dp=new int[100001];
memset(dp,0,(cash+1)*sizeof(int));
for(i=1;i<=n;i++)
{
cin>>num[i]>>den[i];
int t=1,amount=num[i];
while(amount>0) //用二进制思想进行优化,化为01背包问题
{
if(amount>=t)
{
sc[k++]=t*den[i];
amount-=t;
t*=2;
}
else
t=1;
}
}
/* for(i=0;i<k;i++)
cout<<sc[i]<<' ';
cout<<endl;*/
for(i=0 ;i<k;i++)
for(j=cash;j>=sc[i];j--)
dp[j]=max(dp[j],dp[j-sc[i]]+sc[i]);
cout<<dp[cash]<<endl;
delete dp;
}
}
HDOJ-三部曲-多重背包-1014-Cash Machine的更多相关文章
- hdoj 2191(多重背包)
悼念512汶川大地震遇难同胞——珍惜现在,感恩生活 Time Limit : 1000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/ ...
- hdu 2191 (多重背包+二进制优化)
Problem Description 急!灾区的食物依然短缺!为了挽救灾区同胞的生命,心系灾区同胞的你准备自己采购一些粮食支援灾区,现在假设你一共有资金n元,而市场有m种大米,每种大米都是袋装产品, ...
- Poj 1276 Cash Machine 多重背包
Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 26172 Accepted: 9238 Des ...
- poj 1276 Cash Machine(多重背包)
Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 33444 Accepted: 12106 De ...
- POJ1276:Cash Machine(多重背包)
Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver ap ...
- Cash Machine(多重背包二进制转换)
个人心得:多重背包,自己根据转换方程写总是TLE,后面去网上看了二进制转换,不太理解: 后面仔细想了下,用自己的思想理解下把,就是将对应number,cash总和用二进制拆分, 然后全部装入到一个数组 ...
- POJ 1276 Cash Machine(单调队列优化多重背包)
Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 38986 Accepted: 14186 De ...
- POJ 1276:Cash Machine 多重背包
Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 30006 Accepted: 10811 De ...
- POJ1276 - Cash Machine(多重背包)
题目大意 给定一个容量为M的背包以及n种物品,每种物品有一个体积和数量,要求你用这些物品尽量的装满背包 题解 就是多重背包~~~~用二进制优化了一下,就是把每种物品的数量cnt拆成由几个数组成,1,2 ...
- 【转载】poj 1276 Cash Machine 【凑钱数的问题】【枚举思路 或者 多重背包解决】
转载地址:http://m.blog.csdn.net/blog/u010489766/9229011 题目链接:http://poj.org/problem?id=1276 题意:机器里面共有n种面 ...
随机推荐
- Ubuntu配置Open BlockChain
/* 以前只是听说过BlockChain,没怎么了解过,最近导师在搞Blockchain,让我配一下Open BlockChain的环境,于是就硬着头皮配了一下,还挺顺利的. 由于没接触过BlockC ...
- (15)odoo配置文件详解
openerp-server.conf ---------------- [options]; addons模块的查找路径addons_path = E:\GreenOdoo8.0\source\op ...
- hdu-----(1113)Word Amalgamation(字符串排序)
Word Amalgamation Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others ...
- IDEA 创建Java Web项目
发现项目目录没有classes和lib目录,所以自己创建 点击OK,选中"Jar Directroy"-->点击"OK" 然后直接把jar复制到这个目录下 ...
- Play framework 2.0 -应用程序全局设置(转)
转载自: http://shenbai.iteye.com/blog/1517366 1.全局对象 在工程中定义全局对象可以允许你操作你的应用程序的全局设置.这个全局对象必须定义在根包下. impor ...
- YanYan Self Introduction
My Website: http://finehappy.com/
- 一步一步配置NLB
废话不说,配置NLB需要准备以下环境: 1. 至少两个服务器,我的是windows server 2008 R2; 我的两个服务器名分别为NLB3和NLB2,其中NLB3是主,为什么呢?后面会谈到,在 ...
- VS2010 winform程序发布步骤
1.右键单击解决方案,点击“添加”---“新建项目”,如下图: 2.选择“其他项目类型”--“安装和部署”--“Visual Studio Installer”---"安装项目", ...
- [原创]checkstyle下载与安装
checkstyle是一款功能很强的java静态代码检查工具,为eclipse的插件.在网上看了,大致有两种安装方法.第一种 为联网,在eclipse里输入URL下载:另一种为下载好插件后,离线安装. ...
- js基础之动画(二)
一.多物体同时运动 栗子一:多个Div,鼠标移入变高,动态下拉菜单 function startMove(obj,iTarget){ clearInterval(obj.timer); obj.ti ...