s5_day11作业

# 1 文件内容如下,标题为:姓名,性别,年纪,薪资
#
# egon male 18 3000
# alex male 38 30000
# wupeiqi female 28 20000
# yuanhao female 28 10000
#
# 要求:
# 1 从文件中取出每一条记录放入列表中,
# 列表的每个元素都是{'name':'egon','sex':'male','age':18,'salary':3000}的形式
# 第一种
# l=[]
# with open('1',encoding='utf-8')as f:
#     for line in f:
#         l1=line.split()
#         l.append({'name':l1[0],'sex':l1[1],'age':l1[2],'salary':l1[3]})
# print(l)
# 第二种列表解析
# with open('1',encoding='utf-8')as f:
#     l=[{'name':line.split()[0],'sex':line.split()[1],'age':line.split()[2],'salary':line.split()[3]} for line in f]
# print(l)
# 2 根据1得到的列表,取出薪资最高的人的信息
# with open('1',encoding='utf-8')as f:
#     l=[{'name':line.split()[0],'sex':line.split()[1],'age':line.split()[2],'salary':line.split()[3]} for line in f]
# print(max(l,key=lambda x:x['salary']))
# print([i for i in list if i['salary'] == max(i['salary'] for i in list)])
# 3 根据1到的列表,取出最年轻的人的信息
# with open('1',encoding='utf-8')as f:
#     l=[{'name':line.split()[0],'sex':line.split()[1],'age':line.split()[2],'salary':line.split()[3]} for line in f]
# print(min(l,key=lambda x:x['age']))
# print([i for i in list if i['age']==min(i['age'] for i in list)])
# 4 根据1得到的列表,将每个人的信息中的名字映射成首字母大写的形式
# with open('1',encoding='utf-8')as f:
    # l=[{'name':line.split()[0],'sex':line.split()[1],'age':line.split()[2],'salary':line.split()[3]} for line in f]
    # print(list(map(lambda x:x['name'].capitalize(),l)))
    # print([i['name'].capitalize() for i in l])
    # print(list(map(lambda x:x['name'].title(),l)))
# 5 根据1得到的列表,过滤掉名字以a开头的人的信息
# with open ('1',encoding='utf-8') as f:
#     list=([{'name':line.split()[0],'sex':line.split()[1],'age':int(line.split()[2]),'salary':int(line.split()[3]),} for line in f])
    # print([i for i in list if i['name'].startswith('a')])
    # print(next(filter(lambda x:x['name'].startswith('a'),list)))
# 6 使用递归打印斐波那契数列(前两个数的和得到第三个数)
#     0 1 1 2 3 4 7...
# def recur_fibo(n):
#    if n <= 1:
#        return n
#    else:
#        return(recur_fibo(n-1) + recur_fibo(n-2))
# nterms = int(input("您要输出几项? "))
# # 检查输入的数字是否正确
# if nterms <= 0:
#    print("输入正数")
# else:
#    for i in range(nterms):
#        print(recur_fibo(i),end=' ')