Talent wins games, but teamwork and intelligence wins championships.

才华让你赢得比赛,团队及智慧让你赢得冠军。

But the most talented guys can help his team win the triumphs even if his teammates may be infeiror to his oppenents, and of course, I mean that his teammates can't be the undercover of  the opposing team.

If you are not the one who can hold the whip land easily all the time, it would be better to make good use of the abilities of your teammates, at least you should make sure they can help you in defence and let you worry-free when you launch your attacks.

Some so-called  life-mentors always try to tell us that nothing is impossible and it all depends on man, that is, you would win through if you can persist in your current understakings.

Just bull-shit. Most often your personal capabilities are not the decisive factors on the results.

Just as you want to make it plain in an interview that you are not too timid to speak up, you want to make it clear you are not over-confident or intent on dominating the process.

One should count each day a separate life.

要把每天都过成新生活。

From Seneca.

You can't live each day as a separate life, because each day is based on the day of yesterday and is the foundation for the day of tomorrow as well.

There are close relationships among them and we can't easily separate them from one another.

So, I would rather to live every day a little better than the yesterday of it.

That is the very dream I have pursued these years, but it is quite hard to be realized, even just a petty part of it.

October 08th 2017 Week 41st Sunday的更多相关文章

  1. October 9th 2016 Week 41st Sunday

    No matter how resourceful you are, you can't fight fate. 人纵有万般能耐,终也敌不过天命. I find that I gradually be ...

  2. October 2nd 2016 Week 41st Sunday

    The road to success is lined with many tempting parking spaces. 通往成功的路边充斥着许多诱人的休息区. Exhausted, I thi ...

  3. October 29th, 2017 Week 44th Sunday

    There was another life that I might have had, but I am having this one. 我明明可以过另一种生活,但我却选择了这一种. Be re ...

  4. October 22nd, 2017 Week 43rd Sunday

    Yesterday is not ours to recover, but tomorrwo is ours to win or lose. 我们无法重拾昨天,但我们可以选择赢得或者输掉明天. Eve ...

  5. October 15th 2017 Week 42nd Sunday

    Excellence is a continuous process and not an accident. 卓越是一个持续的过程而不是一个偶然事件. It is said that ten tho ...

  6. October 14th 2017 Week 41st Saturday

    I was well beaten myself, and I am beffer for it. 我自己也被打败过,但我因此变得更好. For most of us, the life road c ...

  7. October 13th 2017 Week 41st Friday

    The shortest distance between two people is a smile. 人与人之间最短的距离是微笑. I find a smiling face can bring ...

  8. October 12th 2017 Week 41st Thursday

    Be happy for this moment. This moment is your life. 为这一刻感到高兴,这一刻是你的人生. Yesterday Tencent became Asia ...

  9. October 11th 2017 Week 41st Wednesday

    If you don't know where you are going, you might not get there. 如果你不知道自己要去哪里,你可能永远到不了那里. The reward ...

随机推荐

  1. 从weblogic的一个教训

    部署后一定要检查解压后的文件是否修改了.常常出现部署中存在缓存的情况. weblogic8.1可能出现没有删除缓存情况.血的教训.

  2. Rails 建立一个资源

    在blog 应用程序中.你可以通过脚手架(scaffolded)开始建立一个资源. 这将是单一的blog 提交.请输入以下命令 $ rails generate scaffold Post name: ...

  3. Codeforces 960G. Bandit Blues

    Description 你需要构造一个长度为 \(n\) 的排列 , 使得一个数作为前缀最大值的次数为 \(A\) , 作为后缀最大值的次数为 \(B\) , 求满足要求的排列个数 . 题面 Solu ...

  4. for in可遍历原型链上扩展的属性,Object.keys() 只遍历自身属性

    一.for in 1.使用 for in 循环遍历对象的属性时,原型链上的所有属性都将被访问: Object.prototype.say="cgl"; // 修改Object.pr ...

  5. Ionic开发之如何修改Cordova插件

    由于大多数的Cordova plugin都是国外的,一些提示信息通常都是英文, 这就需要我们自己修改成中文信息. 除此之外,还有可能插件的样式,皮肤等和整体项目的风格不一致,这个时候也是要修改的. 可 ...

  6. 前端(十):使用redux管理数据

    react本身能够完成动态数据的监听和更新,如果不是必要可以不适用redux. 安装redux: cnpm install redux --save,或者yarn add redux. 一.react ...

  7. linux总结之find搜索文件(times 3)

    个人原创,转自请在文章头部显眼位置注明出处:https://www.cnblogs.com/sunshine5683/p/10091341.html find命令的各种搜索 一.根据文件名进行查找 命 ...

  8. Highchar.js插件提示框千分位显示为空格而不是逗号 --(2018 08/06-08/12周总结)

    1.Oracle在已经存在主键的表中插入复合主键的SQL语句 如已有一个表test_key,其中a1列为主键. CREATE TABLE TEST_KEY( A1 VARCHAR2(3) NOT NU ...

  9. sum() 求和用法

    def func(*args): # sum = 0 # for el in args: # sum += el # return sum return sum(args) # sum() 求和 de ...

  10. Python3 笔记01:求两数之和

    这是来自于leetcode的题目: 给定一个整数数组 nums 和一个目标值 target,请你在该数组中找出和为目标值的 两个 整数. 你可以假设每种输入只会对应一个答案.但是,你不能重复利用这个数 ...