HDU 4716 A Computer Graphics Problem (水题)
A Computer Graphics Problem
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 43 Accepted Submission(s): 40
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use '.' as empty grids.
When the battery is empty, the interface will look like this:
*------------*
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
*------------*
When the battery is 60% full, the interface will look like this:
*------------*
|............|
|............|
|............|
|............|
|------------|
|------------|
|------------|
|------------|
|------------|
|------------|
*------------*
Each line there are 14 characters.
Given the battery power the mobile phone left, say x%, your task is to output the corresponding interface. Here x will always be a multiple of 10, and never exceeds 100.
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)
See sample output for more details.
0
60
*------------*
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
*------------*
Case #2:
*------------*
|............|
|............|
|............|
|............|
|------------|
|------------|
|------------|
|------------|
|------------|
|------------|
*------------*
大水题一发
就是拼手速
/* ***********************************************
Author :kuangbin
Created Time :2013-9-11 12:01:07
File Name :2013-9-11\1001.cpp
************************************************ */ #include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
int iCase = ;
int T;
int n;
scanf("%d",&T);
while(T--)
{
iCase++;
printf("Case #%d:\n",iCase);
scanf("%d",&n);
printf("*");
for(int i = ;i < ;i++)printf("-");
printf("*\n");
int t = n/;
for(int i = ;i < -t;i++)
{
printf("|");
for(int j = ;j < ;j++)printf(".");
printf("|\n");
}
for(int i = ;i < t;i++)
{
printf("|");
for(int j = ;j < ;j++)printf("-");
printf("|\n");
}
printf("*");
for(int i = ;i < ;i++)printf("-");
printf("*\n"); }
return ;
}
HDU 4716 A Computer Graphics Problem (水题)的更多相关文章
- HDU 4716 A Computer Graphics Problem
A Computer Graphics Problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (J ...
- HDU 4716 A Computer Graphics Problem 2013年四川省赛题
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4716 题目大意不用解释了吧,看案例就能明白 #include<cstdio> #inclu ...
- HDU-4716 A Computer Graphics Problem 水题
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4716 直接搞.. //STATUS:C++_AC_0MS_288KB #include <fun ...
- 水题 HDOJ 4716 A Computer Graphics Problem
题目传送门 /* 水题:看见x是十的倍数就简单了 */ #include <cstdio> #include <iostream> #include <algorithm ...
- HDU 5170 GTY's math problem 水题
题目链接: hdu:http://acm.hdu.edu.cn/showproblem.php?pid=5170 bc(中文):http://bestcoder.hdu.edu.cn/contests ...
- HDUOJ----A Computer Graphics Problem
A Computer Graphics Problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (J ...
- HDU 2096 小明A+B --- 水题
HDU 2096 /* HDU 2096 小明A+B --- 水题 */ #include <cstdio> int main() { #ifdef _LOCAL freopen(&quo ...
- hdu 2117:Just a Numble(水题,模拟除法运算)
Just a Numble Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Tot ...
- hdu 2050:折线分割平面(水题,递归)
折线分割平面 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Subm ...
随机推荐
- vue总结 08状态管理vuex
状态管理 类 Flux 状态管理的官方实现 由于状态零散地分布在许多组件和组件之间的交互中,大型应用复杂度也经常逐渐增长.为了解决这个问题,Vue 提供 vuex:我们有受到 Elm 启发的状态管 ...
- 【小程序开发】上拉加载更多demo
wxml: <scroll-view class='swiper-scroll' scroll-y="{{true}}" bindscrolltolower="lo ...
- 窗口启用/禁用功能函数EnableWindow的使用
在非MFC环境中如何使控件或者窗口禁用呢?起初是想通过发送消息来实现,但找来找去都木有找到控件禁用的消息(也是是博主木有找到的缘故),所以只能另辟蹊径,使用 EnableWindow这个函数, 该函数 ...
- 使用dos命令创建多模块Maven项目
好吧,咱们接着上一篇博客继续用另一种方式来创建Maven项目.不过在创建之前我们应该先熟悉一些相关dos命令. 创建web项目命令: mvn archetype:generate -DgroupId= ...
- Unix IPC之互斥锁与条件变量
互斥锁 1.函数声明 #include <pthread.h> /* Mutex handling. */ /* Initialize a mutex. */ extern int pth ...
- OnClickListener接口
package com.example.wang.testapp2; import android.support.v7.app.AppCompatActivity; import android.o ...
- RelativeLayout
<?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android=&q ...
- jquery图片延迟加载方案解决图片太多加载缓慢问题
当在做一个图片展示站的时候,一个页面加载的图片过多会,如果服务器的带宽跟不上,明显会感觉到页面很卡,严重的浏览器也会崩溃,所以我推荐采用即看即所得的模式,当滚动到下一屏时才进行加载图片. 注意:即便如 ...
- 手动安装pydev
在网上下载pydev.zip,解压后有两个文件夹,features和plugins.把这两个文件夹复制到eclipse目录下的dropins文件夹下.
- wampserver的安装和使用
首先想说一下通常搭建WAMP平台的时候主要分为散装包搭建和集成包搭建过程. 散装包搭建就是把PHP,Apache,MySQL等下载下来,一个个的安装,其过程灰常的复杂,而且需要配置的系统变量和修改的文 ...