Wolf and Rabbit

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 7646    Accepted Submission(s): 3844

Problem Description
There is a hill with n holes around. The holes are signed from 0 to n-1.



A
rabbit must hide in one of the holes. A wolf searches the rabbit in
anticlockwise order. The first hole he get into is the one signed with
0. Then he will get into the hole every m holes. For example, m=2 and
n=6, the wolf will get into the holes which are signed 0,2,4,0. If the
rabbit hides in the hole which signed 1,3 or 5, she will survive. So we
call these holes the safe holes.
 
Input
The
input starts with a positive integer P which indicates the number of
test cases. Then on the following P lines,each line consists 2 positive
integer m and n(0<m,n<2147483648).
 
Output
For each input m n, if safe holes exist, you should output "YES", else output "NO" in a single line.
 
Sample Input
2
1 2
2 2
 
Sample Output
NO
YES
 
Author
weigang Lee
 
Source
判断n能否整除m(m!=1)。

The 3n + 1 problem

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 35393    Accepted Submission(s): 12830

Problem Description
Problems
in Computer Science are often classified as belonging to a certain
class of problems (e.g., NP, Unsolvable, Recursive). In this problem you
will be analyzing a property of an algorithm whose classification is
not known for all possible inputs.

Consider the following algorithm:


    1.      input n

    2.      print n

    3.      if n = 1 then STOP

    4.           if n is odd then n <- 3n + 1

    5.           else n <- n / 2

    6.      GOTO 2

Given the input 22, the following sequence of numbers will be printed 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

It
is conjectured that the algorithm above will terminate (when a 1 is
printed) for any integral input value. Despite the simplicity of the
algorithm, it is unknown whether this conjecture is true. It has been
verified, however, for all integers n such that 0 < n < 1,000,000
(and, in fact, for many more numbers than this.)

Given an input
n, it is possible to determine the number of numbers printed (including
the 1). For a given n this is called the cycle-length of n. In the
example above, the cycle length of 22 is 16.

For any two numbers i and j you are to determine the maximum cycle length over all numbers between i and j.
 
Input
The
input will consist of a series of pairs of integers i and j, one pair
of integers per line. All integers will be less than 1,000,000 and
greater than 0.

You should process all pairs of integers and for
each pair determine the maximum cycle length over all integers between
and including i and j.

You can assume that no opperation overflows a 32-bit integer.
 
Output
For
each pair of input integers i and j you should output i, j, and the
maximum cycle length for integers between and including i and j. These
three numbers should be separated by at least one space with all three
numbers on one line and with one line of output for each line of input.
The integers i and j must appear in the output in the same order in
which they appeared in the input and should be followed by the maximum
cycle length (on the same line).
 
Sample Input
1 10
100 200
201 210
900 1000
 
Sample Output
1 10 20
100 200 125
201 210 89
900 1000 174
 
Source
UVA
暴力。
注意:像这种会给出两个数范围的题,前一个数可能比后一个数大!
代码略。

HDU1222,HDU1032 水题的更多相关文章

  1. HDU-1032 The 3n+1 problem 模拟问题(水题)

    题目链接:https://cn.vjudge.net/problem/HDU-1032 水题 代码 #include <cstdio> #include <algorithm> ...

  2. HDOJ 2317. Nasty Hacks 模拟水题

    Nasty Hacks Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Tota ...

  3. ACM :漫漫上学路 -DP -水题

    CSU 1772 漫漫上学路 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Submit ...

  4. ytu 1050:写一个函数,使给定的一个二维数组(3×3)转置,即行列互换(水题)

    1050: 写一个函数,使给定的一个二维数组(3×3)转置,即行列互换 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 154  Solved: 112[ ...

  5. [poj2247] Humble Numbers (DP水题)

    DP 水题 Description A number whose only prime factors are 2,3,5 or 7 is called a humble number. The se ...

  6. gdutcode 1195: 相信我这是水题 GDUT中有个风云人物pigofzhou,是冰点奇迹队的主代码手,

    1195: 相信我这是水题 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 821  Solved: 219 Description GDUT中有个风云人 ...

  7. BZOJ 1303 CQOI2009 中位数图 水题

    1303: [CQOI2009]中位数图 Time Limit: 1 Sec  Memory Limit: 162 MBSubmit: 2340  Solved: 1464[Submit][Statu ...

  8. 第十一届“蓝狐网络杯”湖南省大学生计算机程序设计竞赛 B - 大还是小? 字符串水题

    B - 大还是小? Time Limit:5000MS     Memory Limit:65535KB     64bit IO Format: Description 输入两个实数,判断第一个数大 ...

  9. ACM水题

    ACM小白...非常费劲儿的学习中,我觉得目前我能做出来的都可以划分在水题的范围中...不断做,不断总结,随时更新 POJ: 1004 Financial Management 求平均值 杭电OJ: ...

随机推荐

  1. 初探Docker

    本文旨在让大家了解什么是Docker,并带领大家体验Docker使用的整个流程. 开启Docker学习之旅前,我们简单描述几个场景,应该很多人都有碰到过: 小凹同学开发了一个web应用,服务器环境是: ...

  2. thinkphp几个表的数据合并,并用数组分页

    控制器: //金币扣除 public function jbkc(){ $map['UG_dataType']= 'xtkc'; $list1 = M ( 'userget' )->where ...

  3. JavaScript设计模式——单体模式

    一:单体模式简介: 是什么:将代码组织为一个逻辑单元,这个单元中的代码通过单一的变量进行访问.只要单体对象存在一份实例,就可以确信自己的所有代码使用的是同样的全局资源. 用途:1.用来划分命名空间,减 ...

  4. 《DSP using MATLAB》示例Example4.8

    代码: b = [0,1]; a = [3, -4, 1]; % polynomials coefficients [R,p,c] = residuez(b,a) [b,a] = residuez(R ...

  5. SQL初级第三课(上)

    先建立一个表 create table Student                 --学生(Sno          char(3) primary key ,  --学生学号Sname     ...

  6. codefroces 589A

    time limit per testsecondsmemory limit per testmegabytesinputstandard inputoutputstandard outputPoly ...

  7. wpf 触发器,属性触发器,事件触发器,事件触发器。

    <EventTrigger RoutedEvent="Mouse.MouseEnter"/> <DataTrigger Binding="{Bindin ...

  8. VS链接过程中与MSVCRT.lib冲突

    vs代码生成有/MT,/MTd,/Md,/MDd四个编译选项,分别代表多线程.多线程调试.多线程DLL.多线程调试DLL. 编译时引用的lib分别为libcmt.li.libcmtd.lib.msvc ...

  9. 持续集成基础-Jenkins(二)-搭建Jenkins环境和配置第一个Job

    安装方式一(直接启动): 1.下载最新的版本(一个 WAR 文件).Jenkins官方网址: http://Jenkins-ci.org/ 2.运行 java -jar jenkins.war(需要运 ...

  10. linux tomcat配置https

    自己生成一个ssl证书,因为是自己生成的所以该证书,不被浏览器信任(具体表现https前面有个X) [root@centos apache-tomcat-]# keytool -genkey -ali ...