两个整数相加不能用加减

用位运算

假设两整数a=2和b=6,它们的二进制表示分别为010和110

sum=a^b表示两个二进制数相加不考虑进位:

010

^  110

=  100

carry=(a&b)<<1表示两个二进数相加的进位

010

& 110

= 010

<<1

=100

递归地做sum^carry直到carry=0

代码(一行反而比较好理解):

int getSum(int a, int b) {
return b == 0 ? a : getSum(a ^ b, (a & b) << 1);
}

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