UVALive 3882.And Then There Was One-约瑟夫问题(递推)
Time limit: 3.000 seconds
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1,...,n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k −1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.

Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times.
For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000,1 ≤ k ≤ 10000,1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Sample Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Sample Output
1
93
题意就是约瑟夫问题,看人家的博客吧。
传送门1:http://www.cnblogs.com/shanyr/p/5213631.html
传送门2:http://blog.csdn.net/hyczms/article/details/43817799
公式写上就可以A了。
代码:
#include<bits/stdc++.h>
using namespace std;
const int N=1e5+;
int a[N];
int main(){
int n,k,m,cnt;
while(~scanf("%d%d%d",&n,&k,&m)&&n){
a[]=;
for(int i=;i<=n;i++)
a[i]=(a[i-]+k)%i;
cnt=(a[n]+m-k+)%n;
if(cnt<=) cnt+=n;
printf("%d\n",cnt);
}
return ;
}
UVALive 3882.And Then There Was One-约瑟夫问题(递推)的更多相关文章
- Joseph POJ - 1012 约瑟夫环递推
题意:约瑟夫环 初始前k个人后k个人 问m等于多少的时候 后k个先出去 题解:因为前k个位置是不动的,所以只要考虑每次递推后的位置在不在前面k个就行 有递推式 ans[i]=(ans[i-1]+m ...
- UVALive 3882 - And Then There Was One【约瑟夫问题】
题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_ ...
- UVA 1394 And Then There Was One / Gym 101415A And Then There Was One / UVAlive 3882 And Then There Was One / POJ 3517 And Then There Was One / Aizu 1275 And Then There Was One (动态规划,思维题)
UVA 1394 And Then There Was One / Gym 101415A And Then There Was One / UVAlive 3882 And Then There W ...
- LA 3882 And Then There Was One[约瑟夫问题的变形]
And Then There Was One UVALive - 3882 Sample Input Sample Output //设f[i]为(原约瑟夫问题)第i次要删除的标号 #includ ...
- LA 3882 经典约瑟夫环问题的数学递推解法
就是经典约瑟夫环问题的裸题 我一开始一直没理解这个递推是怎么来的,后来终于理解了 假设问题是从n个人编号分别为0...n-1,取第k个, 则第k个人编号为k-1的淘汰,剩下的编号为 0,1,2,3. ...
- 「模拟8.23」one递推,约瑟夫
前置芝士约瑟夫问题 这样大概就是板子问题了 考场的树状数组+二分的60分暴力??? 1 #include<bits/stdc++.h> 2 #define int long long 3 ...
- LA 3882 - And Then There Was One(约瑟夫 递归)
看题传送门 题目大意: N个数排成一圈,第一次删除m,以后每k个数删除一次,求最后一被删除的数. 如果这题用链表或者数组模拟整个过程的话,时间复杂度都将高达O(nk),而n<=10000,k&l ...
- UVALive - 3882:And Then There Was One
约瑟夫环 f[i]表示有i个人先处理第k个人,最后被处理的人是谁 #include<cstdio> #include<cstdlib> #include<algorith ...
- UVALive - 6577 Binary Tree 递推+找规律
题目链接: http://acm.hust.edu.cn/vjudge/problem/48421 Binary Tree Time Limit: 3000MS 问题描述 Binary Tree is ...
随机推荐
- Jprofiler分析WebSphere(配置WebSphereagent代理)
一. Windows+WebSphere+Jprofiler9 我们自己的windows机器监控本地的WebSphere,应该为服务器配置监控代理,供Jprofiler连接使用,具体步骤如下: 1 ...
- ASP.NET页面之间传值Session(2)
想必这个肯定是大家使用中最常见的用法了,其操作与Application类似,作用于用户个人,所以,过量的存储会导致服务器内存资源的耗尽. 优点:1.使用简单,不仅能传递简单数据类型,还能传递对象. 2 ...
- [洛谷P3377]【模板】左偏树(可并堆)
题目大意:有$n$个数,$m$个操作: $1\;x\;y:$把第$x$个数和第$y$个数所在的小根堆合并 $2\;x:$输出第$x$个数所在的堆的最小值 题解:左偏树,保证每个的左儿子的距离大于右儿子 ...
- python3初识selenium
第一步:安装与配置 1.电脑上需要有火狐浏览器(默认安装在C:\Program Files (x86)\Mozilla Firefox目录下). 2.使用pip install selenium安装好 ...
- Collection与Map的对比
Map:HashMap.HashTable 如何在它们之间选择 一.Array , Arrays Java所有“存储及随机访问一连串对象”的做法,array是最有效率的一种. 1. 效率高, ...
- Kafka自我学习2-Zookeeper cluster
Test enviroment : zoo1, zoo2, zoo3 cluster 1. Install zookeeper, package in kafka [root@zoo1 ~]# pwd ...
- 关于跨域策略文件crossdomain.xml文件--配置实例
转载自:http://bbs.phpchina.com/blog-52440-191623.html 我一直不太明白crossdomain.xml文件是干嘛用的,今天总算比较清楚的知道了一下. 这是F ...
- (转)HTTP请求中URL地址的编码和解码
HTTP请求中,类似 http%3A%2F%2Fwww.baidu.com%2Fcache%2Fuser%2Fhtml%2Fv3Jump.html 的地址 如何解码成 http://www ...
- Spring--环境配置
目录 1.1 Spring jar包下载 1.2 Hello World 参考资料 1.1 Spring jar包下载 (1)进入官网http://repo.spring.io(或者 http://m ...
- 关于ora-12154:TNS:could not resolve the connect identifier specified
一:前言 刚刚出来实习,在公司配的电脑里面装的oracle和PL SQL时一次性就搞定,但是在自己的电脑上装了就出现这个问题,刚刚在网上看了下,所以自己就写份记载吧! 二: 在打开PLSQL Deve ...