Til the Cows Come Home (最短路模板题)
个人心得:模板题,不过还是找到了很多问题,真的是头痛,为什么用dijkstra算法book【1】=1就错了.....
纠结中....
Farmer John's field has N (2 <= N <= 1000) landmarks in it, uniquely numbered 1..N. Landmark 1 is the barn; the apple tree grove in which Bessie stands all day is landmark N. Cows travel in the field using T (1 <= T <= 2000) bidirectional cow-trails of various lengths between the landmarks. Bessie is not confident of her navigation ability, so she always stays on a trail from its start to its end once she starts it.
Given the trails between the landmarks, determine the minimum distance Bessie must walk to get back to the barn. It is guaranteed that some such route exists.
Input
* Lines 2..T+1: Each line describes a trail as three space-separated integers. The first two integers are the landmarks between which the trail travels. The third integer is the length of the trail, range 1..100.
Output
Sample Input
5 5
1 2 20
2 3 30
3 4 20
4 5 20
1 5 100
Sample Output
90
Hint
There are five landmarks.
OUTPUT DETAILS:
Bessie can get home by following trails 4, 3, 2, and 1.
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<iomanip>
#include<algorithm>
using namespace std;
#define inf 1<<29
int t,n;
int cow[][];
int dis[];
int book[];
void dijkstra()
{
memset(book,,sizeof(book));
for(int i=;i<=n;i++) dis[i]=cow[][i];
dis[]=;
book[]=;
for(int i=;i<=n;i++)
{
int mina=inf;
int k;
for(int j=;j<=n;j++)
{
if(book[j]==&&mina>dis[j])
{
mina=dis[j];
k=j;
}
}
book[k]=;
for(int j=;j<=n;j++)
{
if(book[j]==&&dis[j]>dis[k]+cow[k][j])
dis[j]=dis[k]+cow[k][j];
}
}
}
int main()
{
while(cin>>t>>n){
int x,y,z;
for(int i=;i<=n;i++)
for(int j=;j<=n;j++)
if(i==j) cow[i][j]=;
else cow[i][j]=inf;
for(int i=;i<=t;i++){
cin>>x>>y>>z;
if(cow[x][y]>z)
cow[x][y]=cow[y][x]=z; }
dijkstra();
cout<<dis[n]<<endl;}
return ;
}
Bellman-Ford算法
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<iomanip>
#include<algorithm>
using namespace std;
#define inf 1<<29
int t,n;
int u[],v[],w[];
int dis[];
int book[];
int main()
{
while(cin>>t>>n)
{
for(int i=;i<=t;i++)
cin>>u[i]>>v[i]>>w[i];
for(int i=;i<=n;i++)
dis[i]=inf;
dis[]=;
for(int i=;i<=n;i++)
for(int j=;j<=t;j++){
if(dis[v[j]]>dis[u[j]]+w[j])
dis[v[j]]=dis[u[j]]+w[j];
if(dis[u[j]]>dis[v[j]]+w[j])
dis[u[j]]=dis[v[j]]+w[j]; }
cout<<dis[n]<<endl; }
return ;
}
Queue
/*
spfa
Memory 256K
Time 32MS
*/
#include <iostream>
#include <queue>
using namespace std;
#define inf 1<<29
#define MAXM 4005
#define MAXV 1005 typedef struct{
int a,b,w,next;
}Edge; Edge edge[MAXM];
int n,m,headlist[MAXV]; void spfa(){
int i,d[MAXV],v,vis[MAXV];
queue <int>q;
for(i=;i<=n;i++){
d[i]=inf;
vis[i]=;
}
d[]=;
vis[]=;
q.push();
while(!q.empty()){
v=q.front();q.pop();
vis[v]=; for(i=headlist[v];i!=-;i=edge[i].next)
if(d[v]+edge[i].w<d[edge[i].b]){
d[edge[i].b]=d[v]+edge[i].w;
if(!vis[edge[i].b]){
vis[edge[i].b]=;
q.push(edge[i].b);
}
}
}
printf("%d\n",d[n]);
} int main(){
int i,a,b,c;
while(~scanf("%d%d",&m,&n)){
for(i=;i<=n;i++) headlist[i]=-;
for(i=;i<=*m;i+=){
scanf("%d%d%d",&a,&b,&c);
edge[i].a=a;
edge[i].b=b;
edge[i].w=c;
edge[i].next=headlist[a];
headlist[a]=i;
edge[i+].a=b;
edge[i+].b=a;
edge[i+].w=c;
edge[i+].next=headlist[b];
headlist[b]=i+;
}
spfa();
}
return ;
}
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