In English, we have a concept called root, which can be followed by some other words to form another longer word - let's call this word successor. For example, the root an, followed by other, which can form another word another.

Now, given a dictionary consisting of many roots and a sentence. You need to replace all the successor in the sentence with the root forming it. If a successor has many roots can form it, replace it with the root with the shortest length.

You need to output the sentence after the replacement.

Example 1:

Input: dict = ["cat", "bat", "rat"]
sentence = "the cattle was rattled by the battery"
Output: "the cat was rat by the bat"

Note:

  1. The input will only have lower-case letters.
  2. 1 <= dict words number <= 1000
  3. 1 <= sentence words number <= 1000
  4. 1 <= root length <= 100
  5. 1 <= sentence words length <= 1000

Runtime: 64 ms, faster than 45.77% of C++ online submissions for Replace Words.

#include <vector>
#include <string>
using namespace std; class TrieNode{
public:
string word;
TrieNode* children[];
TrieNode(){
for(int i=; i<; i++) children[i] = nullptr;
word = "";
}
};
class Trie{
public:
TrieNode* root;
Trie() {
root = new TrieNode();
}
void buildtrie(vector<string>& words){
for(int i=; i<words.size(); i++){
TrieNode* tmp = root;
for(int j=; j<words[i].size(); j++){
int idx = words[i][j] - 'a';
if(!tmp->children[idx]) tmp->children[idx] = new TrieNode();
tmp = tmp->children[idx];
}
tmp->word = words[i];
}
} string hasprefix(string word){
TrieNode* tmp = root;
string prefix = "";
//cout << word << endl;
for(int i=; i<word.size(); i++){
int idx = word[i] - 'a';
//cout << word << " " << idx << endl;
if(!tmp->children[idx]) return prefix;
tmp = tmp->children[idx];
if(tmp->word != ""){
//cout << prefix << endl;
prefix = tmp->word;
break;
}
}
return prefix;
} }; class Solution {
public:
string replaceWords(vector<string>& dict, string sentence) {
Trie trie = Trie();
trie.buildtrie(dict);
vector<int> spaceidx;
for(int i=; i<sentence.size(); i++){
if(sentence[i] == ' ') spaceidx.push_back(i);
}
vector<string> sent_vec;
int idx = ;
if(spaceidx.size() == ){
sent_vec.push_back(sentence);
}else{
for(int i=; i<spaceidx.size(); i++){
sent_vec.push_back(sentence.substr(idx, spaceidx[i] - idx));
idx = spaceidx[i] + ;
}
}
//for(auto x : spaceidx) cout << x << endl;
sent_vec.push_back(sentence.substr(idx));
//cout << sent_vec.size() << endl;
//for(auto s : sent_vec) cout << s << endl;
vector<string> retvec; for(int i=; i<sent_vec.size(); i++){
string tmpstr = trie.hasprefix(sent_vec[i]);
//cout << sent_vec[i] << endl;
if(tmpstr == "") retvec.push_back(sent_vec[i]);
else retvec.push_back(tmpstr);
}
string ret = "";
for(auto s : retvec) ret += s + " ";
return ret.substr(,ret.size()-);
}
};

LC 648. Replace Words的更多相关文章

  1. 648. Replace Words 替换成为原来的单词

    [抄题]: In English, we have a concept called root, which can be followed by some other words to form a ...

  2. 648. Replace Words

    Problem statement In English, we have a concept called root, which can be followed by some other wor ...

  3. 【LeetCode】648. Replace Words 解题报告(Python & C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 set 字典 前缀树 日期 题目地址:https:/ ...

  4. LeetCode 648. Replace Words (单词替换)

    题目标签:HashMap 题目给了我们一个array 的 root, 让我们把sentence 里面得每一个word 去掉它得 successor. 把每一个root 存入hash set,然后遍历s ...

  5. LeetCode All in One题解汇总(持续更新中...)

    突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对 ...

  6. 算法与数据结构基础 - 字典树(Trie)

    Trie基础 Trie字典树又叫前缀树(prefix tree),用以较快速地进行单词或前缀查询,Trie节点结构如下: //208. Implement Trie (Prefix Tree)clas ...

  7. leetcode 学习心得 (4)

    645. Set Mismatch The set S originally contains numbers from 1 to n. But unfortunately, due to the d ...

  8. pt-online-schema-change 最佳实践(转)

    pt的详细步骤 Step 1: Create the new table. Step 2: Alter the new, empty table. This should be very quick, ...

  9. All LeetCode Questions List 题目汇总

    All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems clas ...

随机推荐

  1. another-redis-desktop-manager

    brew cask install another-redis-desktop-manager

  2. Centos网卡名称命名

    1. vim /etc/sysconfig/grub     编辑/etc/sysconfig/grub文件 添加  net.ifnames=0 biosname=0 GRUB_TIMEOUT= GR ...

  3. bootstap 表格自动换行 截取超长数据

    <table class="table" style="TABLE-LAYOUT:fixed;WORD-WRAP:break_word">

  4. 手机 简易浏览器 WebView的基本使用 返回 缓存 进度条

    public class MainActivity extends AppCompatActivity { private WebView webView; private String url = ...

  5. js去掉url后某参数【函数封装】

    function delParam(paramKey) { var url = window.location.href; //页面url var urlParam = window.location ...

  6. QT一个最简单的openGL例子

    创建一个基类为widget的工程 把文件夹glut64放到代码目录下,文件夹包含以下文件 freeglut.dll freeglut.lib glut.h freeglut.h freeglut_ex ...

  7. 第一天Beta冲刺

    这个作业属于哪个课程 <课程的链接> 这个作业要求在哪里 <作业要求的链接> 团队名称 <做个一亿的小项目> 这个作业的目标 完成第一天Beta冲刺 作业正文 .. ...

  8. PAM安全认证模块

  9. Word:不显示图片 + 清空“最近使用的文档”列表

     造冰箱的大熊猫,本文适用于Microsoft Office 2007@cnblogs 2019/3/4 1.Word突然不显示嵌在文本中的图片,只能看到一个空的图片框 解决办法: 1)点击Word左 ...

  10. jupyter工具

    国内源安装: pip install jupyter -i http://pypi.douban.com/simple --trusted-host pypi.douban.com pip --def ...