【leetcode】1281. Subtract the Product and Sum of Digits of an Integer

题目如下：

Given an integer number n, return the difference between the product of its digits and the sum of its digits.

Example 1:

Input: n = 234
Output: 15
Explanation:
Product of digits = 2 * 3 * 4 = 24
Sum of digits = 2 + 3 + 4 = 9
Result = 24 - 9 = 15

Example 2:

Input: n = 4421
Output: 21
Explanation:
Product of digits = 4 * 4 * 2 * 1 = 32
Sum of digits = 4 + 4 + 2 + 1 = 11
Result = 32 - 11 = 21

Constraints:

• 1 <= n <= 10^5

解题思路：送分题。

代码如下：

class Solution(object):
    def subtractProductAndSum(self, n):
        """
        :type n: int
        :rtype: int
        """
        total = 0
        multi = 1
        for i in str(n):
            total += int(i)
            multi *= int(i)
        return multi - total