hdu2897 巴什博奕

n%(q+p)==0,也就是说先手必胜;

n%(q+p)<=p,先手必输;

n%(q+p)==k

if(k>p&&k<=q)先手必胜;

if(k>p&&k<(p+q))当然必胜;

#include<stdio.h>
#include<string.h>
int main()
{
    int i,n,p,q;
    while(scanf("%d%d%d",&n,&p,&q)!=EOF)
    {
        if(n%(q+p)==)
            printf("WIN\n");
        else if(n%(q+p)<=p)
            printf("LOST\n");
        else printf("WIN\n");
    }
}