Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

求链表是否有环的问题,要考虑链表为空的情况,定义一个快指针和一个慢指针,如果快指针和慢指针重合就表明有环

bool hasCycle(ListNode *head){
if(head == NULL || head->next == NULL) return false;
ListNode* first = head, *second = head;
while(second->next!=NULL && second->next->next!=NULL){
first = first->next;
second = second->next->next;
if(first == second) return true;
}
return false;
}

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