HDU 3420 Bus Fair [补]

今天玩魔灵玩多了，耽误了时间，回去宿舍又没电。

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Bus Fair

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 900    Accepted Submission(s): 444

Problem Description

You
are now in Foolish Land. Once moving in Foolish Land you found that
there is a strange Bus fair system. The fair of moving one kilometer by
bus in that country is one coin. If you want to go to X km and your
friend wants to go to Y km then you can buy a ticket of X+Y coins (you
are also allowed to buy two or more tickets for you two).
  
Now
as a programmer, you want to show your creativity in buying tickets!
Suppose, your friend wants to go 1 km and you want to go 2 km. Then it’s
enough for you to buy a 2coin ticket! Because both of you are valid
passengers before crossing the first km. and when your bus cross the
first km your friend gets down from the bus. So you have the ticket of
2km! And you can safely reach to your destination, 2km using that
ticket.
  
Now, you have a large group of friends and they want to
reach to different distance. You think that you are smart enough that
you can buy tickets that should manage all to reach their destination
spending the minimum amount of coins. Then tell us how much we should at
least pay to reach our destination.

 

Input

There
are multiple test cases. Each case start with a integer n, the total
number of people in that group. 0<=n<=1000. Then comes n integers,
each of them stands for a distance one of the men of the group wants to
go to. You can assume that the distance a man wants to go is always
less than 10000.

 

Output

Your
program should print a single integer for a single case, the minimum
amount of coins the group should spend to reach to the destination of
all the members of that group.

 

Sample Input

2
1
2
2
2
3

 

Sample Output

2
4

 

Author

Muhammed Hedayet

 

Source

HDOJ Monthly Contest – 2010.06.05

 

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 #include<math.h>
 #include<stdio.h>
 #include<string.h>
 #include<iostream>
 #include<algorithm>
 using namespace std;
 #define N 1234567

 int n;
 int a[N];
 int b[N];

 int main()
 {
     while(~scanf("%d",&n))
     {
         int ma=;
         for(int i=;i<n;i++)
         {
             scanf("%d",&a[i]);
         }
         sort(a,a+n);
         for(int i=;i<n;i++)
         {
             b[i]=a[i]*(n-i);
             ma=max(ma,b[i]);
         }
         cout<<ma<<endl;
     }
     return ;
 }