python 核心编程课后练习(chapter 5)
5-2
#5-2
def mul(x, y):
return x * y print mul(4,5)
5-3
#5-3
def value_score(num):
if 90<=num<=100:
return 'A'
elif 80<=num<=89:
return 'B'
elif 70<=num<=79:
return 'C'
elif 60<=num<=69:
return 'D'
elif 0<=num<=59:
return 'F'
else:
print "invalid value" print value_score(90)
print value_score(1000)
print value_score(0)
5-4
#5-4
def Leap_year(year):
if year%4 == 0 and year%100 == 0 :
return True
elif year%4 == 0 and year%100 != 0 :
return True
else:
return False if Leap_year(2004):
print "leap year"
else:
print "common year"
5-5
#5-5
import random def least_cents(cts):
left = 0
sum = 0
#get the coins of 25cents
sum = cts/25
left = cts%25
#get the coins of 10cents
sum += left/10
left = left%10
#get the coins of 5cents
sum += left/5
left = left%5
#get the coins of 1cents
sum += left return sum cents = random.randint(1, 100) print "%d cents will have at least: %d coins" % (cents, least_cents(cents))
5-6
#5-6 def add(x, y):
return x + y def sub(x, y):
return x - y def mul(x, y):
return x * y def div(x, y):
return float(x)/float(y) def mod(x, y):
return x % y def pow(x, y):
return x ** y def cal(str):
a = []
if(len(str.split('**')) == 2):
a = str.split('**')
return pow(int(a[0]), int(a[1]))
elif (len(str.split('*')) == 2):
a = str.split('*')
return mul(int(a[0]), int(a[1]))
elif (len(str.split('%')) == 2):
a = str.split('%')
return mod(int(a[0]), int(a[1]))
elif (len(str.split('+')) == 2):
a = str.split('+')
return add(int(a[0]), int(a[1]))
elif (len(str.split('-')) == 2):
a = str.split('-')
return sub(int(a[0]), int(a[1]))
else:
print "Not support" print "enter the formula:"
formula_str = raw_input()
print cal(formula_str)
5-7
#5-7
def tax(num):
return num * 0.03 turnover = raw_input("enter the turnover:")
print"the tax you need to turn over to the state: %f" %(tax(int(turnover)))
5-8
#5-8
import math
def suqare_area(len):
return float(len) * float(len) def suqare_volume(len):
return float(len) ** 3 def circle_area(r):
return math.pi * float(r) * float(r) def spere_volum(r):
return 4 * math.pi * float(r) * float(r) * float(r)/ 3.0 len = raw_input("enter the len:") print "the area of suqare is: %f" % suqare_area(len)
print "the volume of square is: %f" % suqare_volume(len) r = raw_input("enter the r:")
print "the area of the circle is: %f" % circle_area(r)
print "the volume of spere is: %f" % spere_volum(r)
5-10
#5-10
def fah_to_centi(c):
return (c - 32)*(5/float(9)) c = raw_input("enter the fahrenheit:") print "the centi degrees is: %f" % fah_to_centi(float(c))
5-11
#5-11
def odd_num(num):
return num %2 == 1 def aliquant(n1, n2):
return n1 % n2 == 0 for e in range(0, 20):
if not odd_num(e):
print "even number:%d" % e for e in range(0, 20):
if odd_num(e):
print "odd number: %d" % e n1 = raw_input("enter the first number:")
n2 = raw_input("enter the second number:")
if aliquant(int(n1), int(n2)):
print"aliquant"
else:
print"not aliquant"
5-12
#5-12
import sys print sys.maxint
print -sys.maxint - 1 print sys.float_info.max
print sys.float_info.min
5-13
#5-13 def hm_to_m(str):
a = str.split(':')
return int(a[0])* 60 + int(a[1]) hm = raw_input("enter the time:") print "the currents mins is: %d" % hm_to_m(hm)
5-14
#5-14
def year_rate():
return (1+0.0385)** 365 - 1.0 print year_rate()
5-15
#5-15
def GCD(m,n):
if m%n == 0:
return n
else:
return GCD(n, m%n) def LCM(m, n):
return m*n/GCD(m, n) m = int(raw_input("enter m:"))
n = int(raw_input("enter n:")) print"the GCD of %d, %d is: %d" % (m, n, GCD(m, n))
print"the LCM of %d, %d is: %d" % (m, n, LCM(m, n))
5-17
#5-17
import random N = random.randint(2, 100)
a = [] def show_all(a):
for i in range(len(a)):
print a[i] for i in range(0, N-1):
tmp = random.randint(2, 2**31)
a.append(tmp)
print "Original:"
show_all(a) for i in range(0, N-1):
for j in range(i, N-1):
if a[i] > a[j]:
a[i], a[j] = a[j], a[i] print"New arrary:"
show_all(a)
python 核心编程课后练习(chapter 5)的更多相关文章
- python 核心编程课后练习(chapter 6)
6-1 #6-1 #help(string) import string str = "helloworld" substr = "h1e" if string ...
- python 核心编程课后练习(chapter 3)
3-8 #3-8 "makeTextFile.py -- create text file" import os ls = os.linesep #get filename fna ...
- python 核心编程课后练习(chapter 2)
2-4 #2-4(a) print "enter a string" inputstring = raw_input() print"the string is: &qu ...
- Python核心编程课后习题-第六章
1. 字符串, string模块中是否有一种字符串方法或者函数可以帮我鉴定一下一个字符串是否是另一个大字符串的一部分? str1 = 'abcdefghijklmnopqrstuv' print st ...
- Python 核心编程 课后习题 第五章
2. 操作符. (a) 写一个函数, 计算并返回两个数的乘积. (b) 写一段代码调用这个函数, 并显示它的结果. def multi(a,b): return a * b result = mult ...
- Python核心编程 课后练习 第二章
2.4 使用raw_input()函数得到用户输入. (a) 创建一段脚本使用raw_input()函数从用户输入得到一个字符串, 然后显示这个用户杠杠输入的字符串. #coding = utf-8 ...
- python核心编程(第二版)习题
重新再看一遍python核心编程,把后面的习题都做一下.
- Python核心编程这本书的一些错误
<Python核心编程第二版>这本书比<Python基础教程第二版修订版>详细很多,丰富了很多细节,虽然它是一本经典的入门书,但我发现还是存在一些明显的错误.在面向对象编程这一 ...
- Python核心编程-描述符
python中,什么描述符.描述符就是实现了"__get__"."__set__"或"__delete__" 方法中至少一个的对象.什么是非 ...
随机推荐
- 【Cocos2d-x 3.x】内存管理机制与源码分析
侯捷先生说过这么一句话 : 源码之前,了无秘密. 要了解Cocos2d-x的内存管理机制,就得阅读源码. 接触Cocos2d-x时, Cocos2d-x的最新版本已经到了3.2的时代,在学习Coco ...
- ie浏览器 jsp中链接参数为中文的处理
在js中,使用 encodeURIComponent(encodeURIComponent("警情抽查"))来处理参数,例如: mini.get("khxmdm" ...
- 从DataTable获取Json数据
public string GetJson(DataTable dt){ JavaScriptSerializer jss=new JavaScriptSerializer(); jss.MaxJso ...
- DDoS
Distributed Denial of Service (DDoS) Attacks/tools https://staff.washington.edu/dittrich/misc/ddos/ ...
- HttpModule & HttpHandler
ASP.NET 处理请求的过程 inetinfo.exe:www 服务进程,IIS 服务 和 ASPNET_ISAPI.dll 都寄存在此进程中. ASPNET_ISAPI.dll:处理 .aspx ...
- ibm v3700
raid5总容量计算(n-1)*最小盘容量RAID0:N块盘组成,逻辑容量为N块盘容量之和:RAID1:两块盘组成,逻辑容量为一块盘容量:RAID3:N+1块盘组成,逻辑容量为N块盘容量之和:RAID ...
- python-语句
assert语句 用来声明某个条件是真的.例如,如果你非常确信某个你使用的列表中至少有一个元素,而你想要检验这一点,并且在它非真的时候引发一个错误,那么assert语句是应用在这种情形下的理想语句.当 ...
- selenium元素操作
1.文本框(text field or textarea) element.sendKeys("test");//在输入框中输入内容: element.clear(); //将输入 ...
- [转]编译安装libevent,memcache,以及php的memcached扩展
一 安装libevent 1.去官网http://libevent.org/ 下载最新源码,我用的是libevent-2.0.20-stable.tar.gz 2.解压到/usr/src目录 ,执行命 ...
- MyBatis入门学习教程-优化MyBatis配置文件中的配置
一.连接数据库的配置单独放在一个properties文件中 之前,我们是直接将数据库的连接配置信息写在了MyBatis的conf.xml文件中,如下: 1 <?xml version=" ...