#include<iostream>
#include<cmath>
#include<iomanip>
#include<algorithm>
using namespace std;
int main(){
    int t;
    cin>>t;
    while(t--){
        int n;
        cin>>n;
        int a[n];
        for(int i =0 ;i<n;i++){
            int c;
            cin>>c;
            a[i] = c;
        }
        for(int i=0;i<n;i++){
            for(int j=i;j<n;j++){
                int tem;
                if(a[i]>a[j]){
                   tem = a[j];
                   a[j]=a[i];
                   a[i]=tem;
                }
            }
        }
       for(int i =0 ;i<n;i++){
           cout<<a[i]<<endl;
       }   
   
    }

return 0;
}

#include<iostream>
#include<cmath>
#include<iomanip>
#include<algorithm>
using namespace std;
int main(){
 int t;
 cin>>t;
 while(t--){
  int n;
  cin>>n;
  int a[n];
     for(int i =0 ;i<n;i++){
   int c;
   cin>>c;
   a[i] = c;
  }
  sort( a,a+n, less<int>() );
  for(int i=0;i<n;i++){
          cout<<a[i]<<endl;
      } 
 
 }
 return 0;
}

1154. Easy sort的更多相关文章

  1. sicily 1154. Easy sort (tree sort& merge sort)

    Description You know sorting is very important. And this easy problem is: Given you an array with N ...

  2. [SOJ]Easy sort (归并排序)

    Description You know sorting is very important. And this easy problem is: Given you an array with N ...

  3. Sort Methods

    heyheyhey ~~ It has been a long time since i come here again...whatever today i will summerize some ...

  4. uva--11991 - Easy Problem from Rujia Liu?(sort+二分 map+vector vector)

    11991 - Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for e ...

  5. Codeforces Round #650 (Div. 3) F1. Flying Sort (Easy Version) (离散化,贪心)

    题意:有一组数,每次操作可以将某个数移到头部或者尾部,问最少操作多少次使得这组数非递减. 题解:先离散化将每个数映射为排序后所对应的位置,然后贪心,求最长连续子序列的长度,那么最少的操作次数一定为\( ...

  6. [leetcode] 905. Sort Array By Parity [easy]

    原题链接 很水的一道题,就是数组内部交换. 水题就想着减少复杂度嘛,于是学到一种交换写法. class Solution { public: vector<int> sortArrayBy ...

  7. 九度 题目1154:Jungle Roads

    题目描写叙述: The Head Elder of the tropical island of Lagrishan has a problem. A burst of foreign aid mon ...

  8. Sort with Swap(0, i)

    原题连接:https://pta.patest.cn/pta/test/16/exam/4/question/678 题目如下: Given any permutation of the number ...

  9. PAT 1067. Sort with Swap(0,*)

    1067. Sort with Swap(0,*) (25)   Given any permutation of the numbers {0, 1, 2,..., N-1}, it is easy ...

随机推荐

  1. fastcgi 性能初配 504 gateway time-out

    情况一:由于nginx默认的fastcgi进程响应缓冲区太小造成 这种情况下导致fastcgi进程被挂起,如果fastcgi服务队这个挂起处理不是很好的话,就可能提示"504 Gateway ...

  2. win7默认网关不可用怎么解决

    方法一:自动获取 1 有的电脑设置了固定的网关和IP地址.  设置方法: 进入"控制面板" , 然后点击"网络和Internet"!! 步骤阅读 2 然后点击& ...

  3. 转自pnljs 委托(Func<int,bool>)

    随笔- 147 文章- 0 评论- 16 Func的介绍   经常看到  Func<int, bool>...这样的写法,看到这样的就没有心思看下去了.我们学技术还是需要静下心来. 对Fu ...

  4. asp.net LINQ连接数据库SQL执行数据的增加、修改、删除、查询操作

    查询数据库中的数据 using System; using System.Collections.Generic; using System.Linq; using System.Web; using ...

  5. taiyi_interview(Introduction To Database Refactoring)

    Introduction To Database Refactoring 原文链接:by Scott W. Ambler:http://www.tdan.com/view-articles/5010/ ...

  6. maven项目报:An error occurred while filtering resources

    maven项目在problem中报: An error occurred while filtering resources   解决方法: 右键项目-maven-update project.. 

  7. button点击ajax异步无效的处理办法,以及实现“关注”“已关注”切换

    button并不是在只等于submit时草有提交功能,如果你用它触发ajax事件,你的ajax会失去他最大的优势:刷新局部数据! 但是你如果设置了他的return false;属性小伙伴你的ajax才 ...

  8. poj 3692 Kindergarten (最大独立集)

    Kindergarten Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4903   Accepted: 2387 Desc ...

  9. 纯JS实现中国行政区域上下联动选择地址

    一.实现目的: 如标题所述,通过JS来实现地址的选取,上一篇博客介绍的方式是通过java读取txt资源文件来实现地址的选择,通过ajax方式访问服务器实现省市区联动.此篇中将介绍如何使用JS实现相同功 ...

  10. ABP JTable如何手动刷新子表数据

    function getSubMaster() { _$masterTable.find('.jtable-child-table-container').jtable('reload'); }