PAT (Advanced Level) 1005. Spell It Right (20)
简单题。
#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdio>
#include<vector>
using namespace std; const int maxn=+;
char s[maxn];
int tmp[maxn],tot;
char ans[][]={
"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"
}; int main()
{
scanf("%s",s);
int num=; for(int i=;s[i];i++) num=num+s[i]-'';
if(num==)
{
printf("zero\n");
}
else{
tot=; while(num) tmp[tot++]=num%,num=num/;
for(int i=tot-;i>=;i--)
{
printf("%s",ans[tmp[i]]);
if(i>) printf(" ");
else printf("\n");
}
}
return ;
}
PAT (Advanced Level) 1005. Spell It Right (20)的更多相关文章
- PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642
PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642 题目描述: The task is really simple: ...
- PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642
PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642 题目描述: Shuffling is a procedure us ...
- PAT (Advanced Level) Practice 1041 Be Unique (20 分) 凌宸1642
PAT (Advanced Level) Practice 1041 Be Unique (20 分) 凌宸1642 题目描述: Being unique is so important to peo ...
- PAT (Advanced Level) Practice 1015 Reversible Primes (20 分) 凌宸1642
PAT (Advanced Level) Practice 1015 Reversible Primes (20 分) 凌宸1642 题目描述: A reversible prime in any n ...
- PTA (Advanced Level) 1005 Spell It Right
Spell It Right Given a non-negative integer N, your task is to compute the sum of all the digits of ...
- PAT (Advanced Level) Practice 1152 Google Recruitment (20 分)
In July 2004, Google posted on a giant billboard along Highway 101 in Silicon Valley (shown in the p ...
- PAT (Advanced Level) 1054. The Dominant Color (20)
简单题 #include<cstdio> #include<cstring> #include<cmath> #include<vector> #inc ...
- PAT (Advanced Level) 1027. Colors in Mars (20)
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> ...
- PAT (Advanced Level) 1019. General Palindromic Number (20)
简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> ...
随机推荐
- .htaccess文件url重写小记
.htaccess文件url重写 当上一条规则匹配 并转换后 符合下一条规则的 继续下一条的匹配转换 RewriteRule ^shangpin-([0-9a-zA-Z]+)/category-([0 ...
- POJ 3597 种类数 数学+递推
http://poj.org/problem?id=3597 题目大意:把一个正多边形分成数个三角形或者四边形,问有多少种方案. 思路:http://www.cnblogs.com/Ritchie/p ...
- 【多重背包】 poj 2392
转自:http://blog.csdn.net/wangjian8006 题目大意:有一头奶牛要上太空,他有很多种石头,每种石头的高度是hi,但是不能放到ai之上的高度,并且这种石头有ci个将这些石头 ...
- 【RMQ】 区间最值查询详解
1. 概述 RMQ(Range Minimum/Maximum Query),即区间最值查询,是指这样一个问题:对于长度为n的数列A,回答若干询问RMQ(A,i,j)(i,j<=n),返回数列A ...
- Timewarp 一种生成当中帧技术,异步时间扭曲(Asynchronous Timewarp)
翻译: https://www.oculus.com/blog/asynchronous-timewarp/ 异步时间扭曲(Asynchronous Timewarp 时间扭曲,即调整时长) 关 ...
- Spring Boot 系列教程14-动态修改定时任务cron参数
动态修改定时任务cron参数 不需要重启应用就可以动态的改变Cron表达式的值 不能使用@Scheduled(cron = "${jobs.cron}")实现 DynamicSch ...
- zend frameword 基本语法
#resources.frontController.moduleDirectory = APPLICATION_PATH "/modules"#resources.frontCo ...
- jquery 中 $('div','li')
要搞清楚$('div','li') 和 $('div , li') 和 $('div li') 区别$('div','li')是$(子,父),是从父节点里找子,而不是找li外面的div $('div ...
- 学习笔记——组合模式Composite
组合模式,典型的层次结构. 与装饰器类图相似. 区别在于:装饰器模式是为了在接口中增加方法,而组合模式在于层次元素的叠加. ConcreteComponent就是中间结点,可以包含更多的Concret ...
- Bootstrap学习 - JavaScript插件
模态框 <div class="modal" id="myModal" tabindex="-1" role="dialo ...