Codeforces Round #281 (Div. 2) B. Vasya and Wrestling 水题
B. Vasya and Wrestling
题目连接:
http://codeforces.com/contest/493/problem/B
Description
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of the awarded points coincide, the wrestler who performed the last technique wins. Your task is to determine which wrestler won.
Input
The first line contains number n — the number of techniques that the wrestlers have used (1 ≤ n ≤ 2·105).
The following n lines contain integer numbers ai (|ai| ≤ 109, ai ≠ 0). If ai is positive, that means that the first wrestler performed the technique that was awarded with ai points. And if ai is negative, that means that the second wrestler performed the technique that was awarded with ( - ai) points.
The techniques are given in chronological order.
Output
If the first wrestler wins, print string "first", otherwise print "second"
Sample Input
5
1
2
-3
-4
3
Sample Output
second
Hint
题意
有n个分数,然后输入,如果是正数,那么就属于第一个人,如果是负数,那么就属于第二个人。
谁分数大,谁胜利。
如果分数一样,那么看字典序大小。
如果字典序大小一样,看最后的那个数属于谁
题解:
读题比做题难……
模拟一下就好了
代码
#include<bits/stdc++.h>
using namespace std;
vector<int> a,b;
int judge()
{
for(int i=0;i<a.size()&&i<b.size();i++)
{
if(a[i]>b[i])return 1;
if(b[i]>a[i])return 2;
}
return 0;
}
int main()
{
int n;
long long sum1=0,sum2=0;
scanf("%d",&n);
int flag = 0;
for(int i=0;i<n;i++)
{
int x;scanf("%d",&x);
if(x>0)
{
a.push_back(x);
sum1+=x;
flag = 1;
}
else
{
b.push_back(-x);
sum2+=-x;
flag = 2;
}
}
if(sum1>sum2)return puts("first"),0;
if(sum2>sum1)return puts("second"),0;
if(judge()==1)return puts("first"),0;
else if(judge()==2)return puts("second"),0;
if(flag==1)return puts("first"),0;
else return puts("second"),0;
}
Codeforces Round #281 (Div. 2) B. Vasya and Wrestling 水题的更多相关文章
- Codeforces Round #322 (Div. 2) A. Vasya the Hipster 水题
A. Vasya the Hipster Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/581/p ...
- Codeforces Round #281 (Div. 2) D. Vasya and Chess 水
D. Vasya and Chess time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- Codeforces Round #297 (Div. 2)A. Vitaliy and Pie 水题
Codeforces Round #297 (Div. 2)A. Vitaliy and Pie Time Limit: 2 Sec Memory Limit: 256 MBSubmit: xxx ...
- Codeforces Round #290 (Div. 2) A. Fox And Snake 水题
A. Fox And Snake 题目连接: http://codeforces.com/contest/510/problem/A Description Fox Ciel starts to le ...
- Codeforces Round #373 (Div. 2) B. Anatoly and Cockroaches 水题
B. Anatoly and Cockroaches 题目连接: http://codeforces.com/contest/719/problem/B Description Anatoly liv ...
- Codeforces Round #368 (Div. 2) A. Brain's Photos 水题
A. Brain's Photos 题目连接: http://www.codeforces.com/contest/707/problem/A Description Small, but very ...
- Codeforces Round #359 (Div. 2) A. Free Ice Cream 水题
A. Free Ice Cream 题目连接: http://www.codeforces.com/contest/686/problem/A Description After their adve ...
- Codeforces Round #355 (Div. 2) A. Vanya and Fence 水题
A. Vanya and Fence 题目连接: http://www.codeforces.com/contest/677/problem/A Description Vanya and his f ...
- Codeforces Round #281 (Div. 2) C. Vasya and Basketball 二分
C. Vasya and Basketball time limit per test 2 seconds memory limit per test 256 megabytes input stan ...
随机推荐
- jq无缝滚动效果插件(之前的那个升级改造加强版)
scroll滚动插件 支持上下左右,淡入淡出,滚动时间设置,动画时间设置,鼠标经过是否停止设置 默认配置参数可修改 $(".content").easysroll({ //默认配置 ...
- Javascript - Vue - 指令
指令 v-cloak 解决闪烁,闪烁是指在网速较慢的情况下可能会出现插值表达式{{}}还没有填充数据时会把该表达式直接显示在页面上,如果不希望看到插值表达式则可以使用v-cloak指令,具体做法如下 ...
- 【SSH异常】InvalidDataAccessApiUsageException异常
今天在整合SSH的时候,一开始我再测试的时候service层添加了注解事务调用DAO可以正常的保存,在环境中我在XML中采用了spring的OpenSessionInViewFilter解决hiber ...
- SANS社区帐号邮件激活问题
注册时,密码需要数字,大写字母,小写字母,符号10位以上才能注册成功 吐槽:谁来爆破一下这种强度的密码,哈哈. 在我的文章中,有 计算机取证 分类,里面的一篇文章 Virtual Worksta ...
- shell-拷贝指定目录外其他全部目录
shopt -s extglob if [ ! -d "desdir" ]; then mkdir desdir fi cp -r Oozie/!(.svn*) desdir/
- SPListItem.UpdateOverwriteVersion()真的不会创建新版本吗?
根据msdn文档, SPListItem.UpdateOverwriteVersion(): Updates the item without creating another version of ...
- centos6.5环境通过rpm包安装mysql5.5.51数据库
centos6.5环境通过rpm包安装mysql5.5.51数据库 注意:此方法适用于单独安装数据库的需求,如果在该机器上还需要安装php环境,建议mysql通过编译或yum方式安装 1.查找已经安装 ...
- [转]如何取得当前正在执行的shell脚本的绝对路径?
来源:http://sexywp.com/bash-how-to-get-the-basepath-of-current-running-script.htm 如题,一般我们写Shell脚本的时候,都 ...
- CSS3实现各种表情
CSS3实现各种表情 效果图: 代码如下,复制即可使用: <!DOCTYPE html> <html> <head> <title></title ...
- [转]hadoop新手错误解决方法
解决Exception: org.apache.hadoop.io.nativeio.NativeIO$Windows.access0(Ljava/lang/String;I)Z 等一系列问题,lja ...