A. Kyoya and Photobooks(Codeforces Round #309 (Div. 2))
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described
as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so
he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
The first line of input will be a single string s (1 ≤ |s| ≤ 20).
String s consists only of lowercase English letters.
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
a
51
hi
76
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za',
and 'aa', producing a total of 51 distinct photo booklets.
#include <stdio.h>
#include <string.h> int main()
{
char str[100];
int len;
scanf("%s",str);
len = strlen(str);
printf("%d\n",26*(len+1)-len); return 0;
}
A. Kyoya and Photobooks(Codeforces Round #309 (Div. 2))的更多相关文章
- B. Ohana Cleans Up(Codeforces Round #309 (Div. 2))
B. Ohana Cleans Up Ohana Matsumae is trying to clean a room, which is divided up into an n by n gr ...
- 【CodeForces】841D. Leha and another game about graph(Codeforces Round #429 (Div. 2))
[题意]给定n个点和m条无向边(有重边无自环),每个点有权值di=-1,0,1,要求仅保留一些边使得所有点i满足:di=-1或degree%2=di,输出任意方案. [算法]数学+搜索 [题解] 最关 ...
- C. Kyoya and Colored Balls(Codeforces Round #309 (Div. 2))
C. Kyoya and Colored Balls Kyoya Ootori has a bag with n colored balls that are colored with k diffe ...
- B. The Number of Products(Codeforces Round #585 (Div. 2))
本题地址: https://codeforces.com/contest/1215/problem/B 本场比赛A题题解:https://www.cnblogs.com/liyexin/p/11535 ...
- 【CodeForces】841C. Leha and Function(Codeforces Round #429 (Div. 2))
[题意]定义函数F(n,k)为1~n的集合中选择k个数字,其中最小数字的期望. 给定两个数字集A,B,A中任意数字>=B中任意数字,要求重组A使得对于i=1~n,sigma(F(Ai,Bi))最 ...
- D. Zero Quantity Maximization ( Codeforces Round #544 (Div. 3) )
题目链接 参考题解 题意: 给你 整形数组a 和 整形数组b ,要你c[i] = d * a[i] + b[i], 求 在c[i]=0的时候 相同的d的数量 最多能有几个. 思路: 1. 首先打开 ...
- Vus the Cossack and Strings(Codeforces Round #571 (Div. 2))(大佬的位运算实在是太强了!)
C. Vus the Cossack and Strings Vus the Cossack has two binary strings, that is, strings that consist ...
- CodeForces 360E Levko and Game(Codeforces Round #210 (Div. 1))
题意:有一些无向边m条权值是给定的k条权值在[l,r]区间可以由你来定,一个点s1 出发一个从s2出发 问s1 出发的能不能先打到f 思路:最短路. 首先检测能不能赢 在更新的时候 如果对于一条边 ...
- 贪心+构造( Codeforces Round #344 (Div. 2))
题目:Report 题意:有两种操作: 1)t = 1,前r个数字按升序排列: 2)t = 2,前r个数字按降序排列: 求执行m次操作后的排列顺序. #include <iostream&g ...
随机推荐
- dubbo源码解析-spi(一)
前言 虽然标题是dubbo源码解析,但是本篇并不会出现dubbo的源码,本篇和之前的dubbo源码解析-简单原理.与spring融合一样,为dubbo源码解析专题的知识预热篇. 插播面试题 你是否了解 ...
- 6.2 dubbo在spring中自定义xml标签源码解析
在6.1 如何在spring中自定义xml标签中我们看到了在spring中自定义xml标签的方式.dubbo也是这样来实现的. 一 META_INF/dubbo.xsd 比较长,只列出<dubb ...
- 第二十七章 springboot + zipkin(brave-okhttp实现)
本文截取自:http://blog.csdn.net/liaokailin/article/details/52077620 一.前提 1.zipkin基本知识:附8 zipkin 2.启动zipki ...
- jquery实现上传文件大小类型的验证
<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content ...
- Letter Combinations of a Phone Number leetcode java
题目: Given a digit string, return all possible letter combinations that the number could represent. A ...
- 插件化 VirtualAPK 简介 体验 MD
Markdown版本笔记 我的GitHub首页 我的博客 我的微信 我的邮箱 MyAndroidBlogs baiqiantao baiqiantao bqt20094 baiqiantao@sina ...
- Ios开发之多线程编程——NSThread
IOS程序在运行的时候是通过主线程来进行UI视图的更新和响应屏幕触摸事件,但是,在视图更新的时候,会有一些非常耗时的工作,这样我们会出现系统出现卡顿的现象,这是因为主线程堵塞造成的,这样会使用户体验非 ...
- Android模仿三星手机系统滑动条滑动时滑块变大的特效
使用三星手机的过程中发现三星手机系统自带的滑动条有一个特效.比方调节亮度的滑动条.在滑动滑块的过程中,滑块会变大.功能非常小可是体验却非常好,于是决定做一个这种效果出来.好了废话不多说了,以下開始实现 ...
- Android -- AudioPlayer
AudioPlayer 主要是实现边录边播(AudioRecord+AudioTrack)以及对音频的实时处理(如会说话的汤姆猫.语音) 优点:语音的实时处理,可以用代码实现各种音频的封装 缺点:输出 ...
- iOS - 切换图片/clip subview/iCarousel
源代码:点击打开链接 这个图片展示的时候,我只想让它在蓝色的view上展示..就需要去设置view的一个属性clip subview..把这个属性打勾...view有个clip subview属性,选 ...