【VNCTF2022】Reverse wp
babymaze
反编译源码
pyc文件，uncompy6撸不出来，看字节码
import marshal, dis
fp = open(r"BabyMaze.pyc", 'rb')
fp.seek(16)
co = marshal.load(fp)
dis.dis(co)
使用脚本跑出字节码
发现花指令
去除花指令并修改字节码长度，使用uncompy6跑出源码
_map = [
[
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], [1, 5, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1], [1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1], [1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1], [1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1], [1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1], [1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1], [1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1], [1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1], [1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1], [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1], [1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1], [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1], [1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1], [1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1], [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1], [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1], [1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1], [1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1], [1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1], [1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1], [1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1], [1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1], [1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 7, 1], [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]] def maze():
x = 1
y = 1
step = input()
for i in range(len(step)):
if step[i] == 'w':
x -= 1
else:
if step[i] == 's':
x += 1
else:
if step[i] == 'a':
y -= 1
else:
if step[i] == 'd':
y += 1
else:
return False
if _map[x][y] == 1:
return False
if x == 29 and y == 29:
return True def main():
print('Welcome To VNCTF2022!!!')
print('Hello Mr. X, this time your mission is to get out of this maze this time.(FIND THAT 7!)')
print('you are still doing the mission alone, this tape will self-destruct in five seconds.')
if maze():
print('Congratulation! flag: VNCTF{md5(your input)}')
else:
print("Sorry, we won't acknowledge the existence of your squad.") if __name__ == '__main__':
main()
DFS算法
地图非常大，使用DFS算法
map1 = [[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1], [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0,
0, 0, 0, 0, 0, 1], [1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1,
1, 1, 1, 1, 1, 1, 0, 1], [1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0,
0, 1, 0, 1, 0, 0, 0, 1, 0, 1], [1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1,
1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1], [1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1], [1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0,
0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1], [1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1,
0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1], [1, 0, 0, 0, 0, 0, 1, 0, 1,
0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1], [1, 1, 1, 1, 1, 1, 1,
0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1], [1, 0, 0, 0, 0,
0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1], [1, 0, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1], [1,
0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0,
1], [1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1,
1, 1, 1], [1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 1], [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1,
1, 0, 1, 1, 1, 0, 1], [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0,
0, 0, 1, 0, 1, 0, 0, 0, 1], [1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0,
1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1], [1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0,
1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1], [1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1,
1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0,
0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 0, 0, 0, 1, 0, 1, 0,
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 1, 1, 1, 0, 1, 0,
1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1], [1, 0, 0, 0, 1, 0,
1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1], [1, 1, 1, 1,
1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1], [1, 0,
0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1],
[1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1,
0, 1], [1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0,
0, 0, 0, 1], [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1]]
flag = ""
map2 = [[0 for i in range(len(map1))] for i in range(len(map1)) ]
def DFS(x,y):
global flag
if x == len(map1) - 2 and y == len(map1) - 2: #判断边界
print(flag)
if map1[x+1][y] == 0 and map2[x+1][y] == 0:
map2[x][y] = 1
flag += 's'
DFS(x+1,y)
flag = flag[:-1]
map2[x][y] = 0
if map1[x-1][y] == 0 and map2[x-1][y] == 0:
map2[x][y] = 1
flag += 'w'
DFS(x-1,y)
flag = flag[:-1]
map2[x][y] = 0
if map1[x][y+1] == 0 and map2[x][y+1] == 0:
map2[x][y] = 1
flag += 'd'
DFS(x,y+1)
flag = flag[:-1]
map2[x][y] = 0
if map1[x][y-1] == 0 and map2[x][y-1] == 0:
map2[x][y] = 1
flag += 'a'
DFS(x,y-1)
flag = flag[:-1]
map2[x][y] = 0
y=1
x=1
DFS(x,y)
得出
ssssddssaassddddwwwwddwwddddddwwddddddssddwwddddddddssssaawwaassaassaassddssaassaawwwwwwaaaaaaaassaassddddwwddssddssssaassddssssaaaaaawwddwwaawwwwaassssssssssssddddssddssddddddddwwaaaaaawwwwddssddwwwwwwwwddssddssssssssddddss、
getflag
VNCTF{801f190737434100e7d2790bd5b0732e}
cm1
源码分析
APK文件，直接拖入GDA中查看
拖入GDA中查看main函数，先看导入库
发现Main$1、IHeihei及FileUtils等
安装之后查看，基本就是一个check界面
这里提示打开了asset目录下某个dex文件
这里使用FileUtils
发现调用了里面的Haha
跟入查看发现有异或，1024为一组
脚本处理
将cm1解压后进入到asset目录找到ooo
key = 'vn2022'
f = open('ooo','rb')
f = f.read()
with open('out','wb') as h:
for i in range(len(f)):
h.write((f[i]^ord(key[i % 1024 % len(key)])).to_bytes(1,byteorder='little',
signed=False)) print('ok')
写python脚本模拟
发现是个dex文件
使用dex2jar转换为jar文件进行分析
找到haha是一个xxtea加密，写xxtea脚本即可getflag
【VNCTF2022】Reverse wp的更多相关文章
- 【leetcode80】Reverse Vowels of a String（元音字母倒叙）
题目描述: 写一个函数,实现输入一个字符串,然后把其中的元音字母倒叙 注意 元音字母包含大小写,元音字母有五个a,e,i,o,u 原文描述: Write a function that takes a ...
- 【leetcode】Reverse Nodes in k-Group
Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and ret ...
- 【leetcode】Reverse Linked List II
Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. F ...
- 【leetcode】Reverse Nodes in k-Group （hard）☆
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If ...
- 【leetcode】Reverse Linked List II （middle）
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example:Given 1-> ...
- 【leetcode】Reverse Linked List（easy）
Reverse a singly linked list. 思路:没啥好说的.秒... ListNode* reverseList(ListNode* head) { ListNode * rList ...
- 【leetcode】Reverse Bits（middle）
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in ...
- 【leetcode】Reverse Words in a String(hard)☆
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue& ...
- 【leetcode】Reverse Integer（middle）☆
Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 总结:处理整数溢出 ...
随机推荐
- Java NIO Selector 的使用
之前的文章已经把 Java 中 NIO 的 Buffer.Channel 讲解完了,不太了解的可以先回过头去看看.这篇文章我们就来聊聊 Selector -- 选择器. 首先 Selector 是用来 ...
- PentestBox在win10里打不开工具 显示无系统命令的解决方法
PentestBox详细安装过程:http://www.cnblogs.com/ESHLkangi/p/8336398.html 在使用PentestBox的时候出现了打不开工具的问题,最后看到一个大 ...
- [杂记]LeTeX模板——ppt
出处:ShareLeTeX应用模板:https://cn.sharelatex.com/project/5810ad8a07a1ab0f0f8c2ce4 代码如下: 1 % Copyright 200 ...
- [题解]Codeforces Round #254 (Div. 2) B - DZY Loves Chemistry
链接:http://codeforces.com/contest/445/problem/B 描述:n种药品,m个反应关系,按照一定顺序放进试管中.如果当前放入的药品与试管中的药品要反应,危险系数变为 ...
- 网络测试技术——802.1X原理
一.以太网优点缺点 1.以太网优点 (1)即插即用,简单快捷 (2)任何一台电脑只要接入网络便有访问网络资源的权限 2.以太网缺点 (1)缺乏安全认证机制(二层) (2)电脑接到交换机上就能访问网络 ...
- Go1.14版本vendor和gomodule冲突问题
Go1.14版本vendor和gomodule冲突问题 go1.14版本使用go mod tidy构建依赖时会出现问题(见链接), 这个问题在go1.12版本是不会出现的. https://githu ...
- Typora简单使用
Typora介绍 Typora是一款轻量级的Markdown编辑器,它没有采用传统编辑器那样源代码和预览双栏显示的方式,让你所见即所得,能够及时预览.目前Typora在IT领域的人气极高,这也致使原来 ...
- 1.分类维护-通过Java8 Stream API 获取商品三级分类数据
实体类 @Data @TableName("pms_category") public class CategoryEntity implements Serializable { ...
- 哈工大 计算机网络 实验四 利用 Wireshark 进行协议分析
计算机网络实验代码与文件可见github:计算机网络实验整理 实验名称 利用 Wireshark 进行协议分析 实验目的: 本次实验的主要目的. 熟悉并掌握Wireshark的基本操作,了解网络协议实 ...
- .net core项目搭建swagger接口实现简单增删改查
.net core搭建swagger 1,新建立.net core项目(这里不再细说) 2,引入NuGet程序包 3,建立项目之后在Startup类中配置swagger 这里我直接把代码贴出来: 在C ...