【LeetCode Weekly Contest 26 Q3】Friend Circles
【题目链接】:https://leetcode.com/contest/leetcode-weekly-contest-26/problems/friend-circles/
【题意】
告诉你任意两个人是不是朋友.
问你最后有多少个连通块;
【题解】
裸并查集。
【完整代码】
#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define ps push_back
#define fi first
#define se second
#define rei(x) scanf("%d",&x)
#define rel(x) scanf("%lld",&x)
#define ref(x) scanf("%lf",&x)
typedef pair<int, int> pii;
typedef pair<LL, LL> pll;
const int dx[9] = { 0,1,-1,0,0,-1,-1,1,1 };
const int dy[9] = { 0,0,0,-1,1,-1,1,-1,1 };
const double pi = acos(-1.0);
const int N = 250;
int f[N];
bool bo[N];
int ff(int x)
{
if (f[x] == x) return x;
else
return f[x] = ff(f[x]);
}
class Solution {
public:
int findCircleNum(vector<vector<int>>& M) {
memset(bo, false, sizeof bo);
int n = M.size();
rep1(i, 0, n - 1)
f[i] = i;
rep1(i,0,n-1)
rep1(j, 0, n - 1)
if (M[i][j])
{
int r1 = ff(i), r2 = ff(j);
if (r1 != r2)
{
f[r1] = r2;
}
}
int cnt = 0;
rep1(i, 0, n - 1)
{
int x = ff(i);
if (!bo[x])
{
bo[x] = true;
cnt++;
}
}
return cnt;
}
};
【LeetCode Weekly Contest 26 Q3】Friend Circles的更多相关文章
- 【LeetCode Weekly Contest 26 Q4】Split Array with Equal Sum
[题目链接]:https://leetcode.com/contest/leetcode-weekly-contest-26/problems/split-array-with-equal-sum/ ...
- 【LeetCode Weekly Contest 26 Q2】Longest Uncommon Subsequence II
[题目链接]:https://leetcode.com/contest/leetcode-weekly-contest-26/problems/longest-uncommon-subsequence ...
- 【LeetCode Weekly Contest 26 Q1】Longest Uncommon Subsequence I
[题目链接]:https://leetcode.com/contest/leetcode-weekly-contest-26/problems/longest-uncommon-subsequence ...
- LeetCode Weekly Contest 26
写的有点晚了. 我每次都是先看一下这里http://bookshadow.com/leetcode/的思路,然后再开始写我自己的. 1. 521. Longest Uncommon Subsequen ...
- LeetCode Weekly Contest 8
LeetCode Weekly Contest 8 415. Add Strings User Accepted: 765 User Tried: 822 Total Accepted: 789 To ...
- leetcode weekly contest 43
leetcode weekly contest 43 leetcode649. Dota2 Senate leetcode649.Dota2 Senate 思路: 模拟规则round by round ...
- LeetCode Weekly Contest 23
LeetCode Weekly Contest 23 1. Reverse String II Given a string and an integer k, you need to reverse ...
- Leetcode Weekly Contest 86
Weekly Contest 86 A:840. 矩阵中的幻方 3 x 3 的幻方是一个填充有从 1 到 9 的不同数字的 3 x 3 矩阵,其中每行,每列以及两条对角线上的各数之和都相等. 给定一个 ...
- LeetCode Weekly Contest
链接:https://leetcode.com/contest/leetcode-weekly-contest-33/ A.Longest Harmonious Subsequence 思路:hash ...
随机推荐
- python库学习笔记——Pandas数据索引:ix、loc、iloc区别
Different Choices for Indexing 1. loc--通过行标签索引行数据 1.1 loc[1]表示索引的是第1行(index 是整数) import pandas as pd ...
- JSP-Runoob:JSP 国际化
ylbtech-JSP-Runoob:JSP 国际化 1.返回顶部 1. JSP 国际化 在开始前,需要解释几个重要的概念: 国际化(i18n):表明一个页面根据访问者的语言或国家来呈现不同的翻译版本 ...
- 48.EXt.Data.JsonReader()
转自:https://blog.csdn.net/huoyanxueren/article/details/2662915?utm_source=blogxgwz6 extJs 2.1学习笔记(Ext ...
- Coursera Algorithms week4 基础标签表 练习测验:Inorder traversal with constant extra space
题目原文: Design an algorithm to perform an inorder traversal of a binary search tree using only a const ...
- WCF 通讯标准绑定
WCF 通讯标准绑定 一.预定义标准绑定 标准绑定 说明 BasicHttpBinding BasicHttpBinding 绑定用于最广泛的互交操作,针对第一代Web服务,所使用的传输协议是HTTP ...
- vue-video-player视频播放插件
安装依赖 npm install vue-video-player -S 引入配置 //main.js import 'video.js/dist/video-js.css' import 'vue- ...
- Lambda表达式怎么写SQL中的in?
ambda表达式查询没有IN这个方法,可以变通一下,in查询的数组是否包含在映射对象里面的集合里 直接贴代码吧,一看就懂了 class Program { static void Main(strin ...
- HTML--文本输入框、密码输入框
当用户要在表单中键入字母.数字等内容时,就会用到文本输入框.文本框也可以转化为密码输入框. 语法: <form> <input type="text/password&qu ...
- ansible剧本
yaml简介 YAML是"YAML Ain't a Markup Language"(YAML不是一种置标语言)的递归缩写,早先YAML的意思其实是:"Yet Anoth ...
- Kafka的3节点集群详细启动步骤(Zookeeper是外装)
首先,声明,kafka集群是搭建在hadoop1.hadoop2和hadoop3机器上. kafka_2.10-0.8.1.1.tgz的1或3节点集群的下载.安装和配置(图文详细教程)绝对干货 如下分 ...