题意:给定结点个数n和插入序列,判断构造的AVL树是否是完全二叉树?

思路:AVL树的建立很简单。而如何判断是不是完全二叉树呢?通过层序遍历进行判断:当一个结点的孩子结点为空时,则此后就不能有新的结点入队。若没有,则是完全二叉树,否则不是。

代码:

#include <cstdio>
#include <algorithm>
#include <iostream>
#include <vector>
#include <queue>
using namespace std; vector<int> layer; struct Node {
int v, height;
Node *lchild, *rchild;
}; Node* newNode(int v) {
Node* pNode = new Node;
pNode->v = v;
pNode->height = ;
pNode->lchild = pNode->rchild = NULL;
return pNode;
} int getHeight(Node* root){ if(root==NULL) return ;
return root->height;
}
void updateHeight(Node* root) {
root->height = max(getHeight(root->lchild), getHeight(root->rchild))+;
} int getBalanceFactor(Node* root) {
return getHeight(root->lchild)- getHeight(root->rchild);
} void L(Node* &root) { Node* temp = root->rchild;
root->rchild = temp->lchild;
temp->lchild = root;
updateHeight(root);
updateHeight(temp);
root = temp;
}
void R(Node* &root) {
Node* temp = root->lchild;
root->lchild = temp->rchild;
temp->rchild = root;
updateHeight(root);
updateHeight(temp);
root = temp;
} void insert(Node* &root, int v) {
if (root == NULL) {
root = newNode(v);
return;
} if (v < root->v) {
insert(root->lchild,v);
updateHeight(root);
if (getBalanceFactor(root) == ) {
if(getBalanceFactor(root->lchild)==){
R(root);
}else if(getBalanceFactor(root->lchild)==-){
L(root->lchild);
R(root);
} }
}
else {
insert(root->rchild,v);
updateHeight(root);
if (getBalanceFactor(root) == -) {
if(getBalanceFactor(root->rchild)==-){
L(root);
}
else if(getBalanceFactor(root->rchild)==){
R(root->rchild);
L(root);
}
}
}
}
bool isComplete =true;
int after=;
void layerOrder(Node* root){
queue<Node*> Q;
Q.push(root);
while(!Q.empty()){
Node* front=Q.front();
Q.pop();
layer.push_back(front->v); if(front->lchild!=NULL){
if(after==) isComplete=false;
Q.push(front->lchild);
}else{
after=;
} if(front->rchild!=NULL){
if(after==) isComplete=false;
Q.push(front->rchild);
}else{
after=;
}
} } //vector<int> insertOrder; int main()
{
int n,data;
scanf("%d",&n);
Node* root=NULL;
for(int i=;i<n;i++){
scanf("%d",&data);
insert(root,data);
}
layerOrder(root); for(int i=;i<layer.size()-;i++){
printf("%d ",layer[i]);
}
printf("%d\n",layer[n-]);
printf("%s\n",isComplete==true?"YES":"NO"); return ;
}

1123.(重、错)Is It a Complete AVL Tree的更多相关文章

  1. PAT甲级1123. Is It a Complete AVL Tree

    PAT甲级1123. Is It a Complete AVL Tree 题意: 在AVL树中,任何节点的两个子树的高度最多有一个;如果在任何时候它们不同于一个,则重新平衡来恢复此属性.图1-4说明了 ...

  2. 1123 Is It a Complete AVL Tree

    1123 Is It a Complete AVL Tree(30 分) An AVL tree is a self-balancing binary search tree. In an AVL t ...

  3. PAT_A1123#Is It a Complete AVL Tree

    Source: PAT A1123 Is It a Complete AVL Tree (30 分) Description: An AVL tree is a self-balancing bina ...

  4. 1123. Is It a Complete AVL Tree (30)

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

  5. 1123 Is It a Complete AVL Tree(30 分)

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

  6. PAT甲级——1123 Is It a Complete AVL Tree (完全AVL树的判断)

    嫌排版乱的话可以移步我的CSDN:https://blog.csdn.net/weixin_44385565/article/details/89390802 An AVL tree is a sel ...

  7. PAT 1123 Is It a Complete AVL Tree

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

  8. PAT Advanced 1123 Is It a Complete AVL Tree (30) [AVL树]

    题目 An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child ...

  9. A1123. Is It a Complete AVL Tree

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

  10. PAT A1123 Is It a Complete AVL Tree (30 分)——AVL平衡二叉树,完全二叉树

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

随机推荐

  1. Spring mvc:配置不拦截指定的路径

    <!-- 访问拦截 --> <mvc:interceptors> <mvc:interceptor> <mvc:mapping path="/**/ ...

  2. day python011函数的进阶

    形参: 1.位置传参  2. 默认值传参. 3.动态传参 一   动态传参(形参的一种): 之前我们说过了了传参, 如果我们需要给⼀一个函数传参, ⽽而参数⼜又是不确定的. 或者我给⼀一个函数传很多参 ...

  3. NYOJ 6:喷水装置(一)(贪心)

    6-喷水装置(一) 内存限制:64MB 时间限制:3000ms 特判: No 通过数:68 提交数:111 难度:3 题目描述: 现有一块草坪,长为20米,宽为2米,要在横中心线上放置半径为Ri的喷水 ...

  4. Tomcat介绍、安装jdk、安装Tomcat、配置Tomcat监听80端口

    1.Tomcat介绍 2.安装jdk下载:wget -c http://download.oracle.com/otn-pub/java/jdk/10.0.1+10/fb4372174a714e6b8 ...

  5. PTA——判断胖瘦

    PTA 7-40 到底是不是太胖了 #include<stdio.h> #include<math.h> int main() { ,N; scanf("%d&quo ...

  6. hdu3642 Get The Treasury 线段树--扫描线

    Jack knows that there is a great underground treasury in a secret region. And he has a special devic ...

  7. day28Spark

    PS:因为Spark是用内存运行 的,非常快 PS: 1.下面就是将conf的spark-env.template改变成spark-env.sh,并添加红色部分 2.修改slaves文件添加从设备 启 ...

  8. Singer 学习十 同步模式

    sync 模式是属于tap 的操作,同步模式下,tap 需要提交 schema. record .state message, singer 指南对于每种 类型有详细的说明 streams 每个str ...

  9. IAR intrinsic functions

    You can insert asm code example asm("NOP") into the c or c++ source code to get a good per ...

  10. Visual Studio不显示智能提示代码,快捷键Alt+→也不出现

    最近安装了Dev Express的控件,我的vs2017 Enterprise版的环境,智能提示补全代码的快捷键功能,好像被修改了,不能使用了. 我原来的时候,比如在代码中输入如下代码: Consol ...