POJ 2106 Boolean Expressions
- 总时间限制: 1000ms 内存限制: 65536kB
- 描述
- The objective of the program you are going to produce is to evaluate boolean expressions as the one shown next:
Expression:( V | V ) & F & ( F | V )
- where V is for True, and F is for False. The expressions may include the following operators: ! for not , & for and, | for or , the use of parenthesis for operations grouping is also allowed.
- To perform the evaluation of an expression, it will be considered the priority of the operators, the not having the highest, and the or the lowest. The program must yield V or F , as the result for each expression in the input file.
- 输入
- The expressions are of a variable length, although will never exceed 100 symbols. Symbols may be separated by any number of spaces or no spaces at all, therefore, the total length of an expression, as a number of characters, is unknown.
- The number of expressions in the input file is variable and will never be greater than 20. Each expression is presented in a new line, as shown below.
- 输出
- For each test expression, print "Expression " followed by its sequence number, ": ", and the resulting value of the corresponding test expression. Separate the output for consecutive test expressions with a new line.
- Use the same format as that shown in the sample output shown below.
- 样例输入
( V | V ) & F & ( F| V)
!V | V & V & !F & (F | V ) & (!F | F | !V & V)
(F&F|V|!V&!F&!(F|F&V))
样例输出
Expression : F
Expression : V
Expression : V
解题思路
一开始看到这题就觉得要用栈,毕竟是表达式求值问题,但是自己的中缀表达式求值也没练过,而且这次的课程作业又是练习递归,于是就尝试了递归解法。
但是入门太浅,还是搞不懂递归思路,很难从一个表达式中进行结构的分解,逻辑梳理能力太差。
下面是大佬的代码,真心膜拜,希望我的代码能力能越来越好。
#include<iostream>
using namespace std; bool f1();
bool f2(); char getc_() //读入一个非空格字符
{
char c;
while ((c = cin.get()) == ' ');
return c;
}
char peekc_()//读到第一个非空格字符前停止
{
char c;
while ((c = cin.peek()) == ' ')
{
cin.get();
}
return c;
} bool f2()//计算项
{
char c = peekc_();
if (c == '(')
{
getc_(); //拿走左括号
bool d = f1();
getc_(); //拿走右括号
return d;
}
else
{
getc_();
if (c == '!') return !f2();//运算符作用于下一个对象
if (c == 'V') return true;
if (c == 'F') return false;
}
} bool f1()//计算整个表达式
{
char c = peekc_();
if (c == '\n') return false;
bool a = f2();
while (true)
{
c = peekc_();
if (c == '|')
{
getc_();
bool b = f2();
a = a || b;
}
else if (c == '&')
{
getc_();
bool b = f2();
a = a && b;
}
else break;
}
return a;
}
int main()
{
int n = ;
while (cin.peek() != EOF) {
bool f = f1();
if (cin.peek() == '\n' || cin.peek() == EOF) {
cout << "Expression " << ++n << ": " << (f ? 'V' : 'F') << endl;
cin.get();//清理换行符和结束符
}
}
return ;
}
引用网址:
https://blog.csdn.net/chuxin126/article/details/55105076
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