PAT 1138 Postorder Traversal
Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and inorder traversal sequences, you are supposed to output the first number of the postorder traversal sequence of the corresponding binary tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 50,000), the total number of nodes in the binary tree. The second line gives the preorder sequence and the third line gives the inorder sequence. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in one line the first number of the postorder traversal sequence of the corresponding binary tree.
Sample Input:
7
1 2 3 4 5 6 7
2 3 1 5 4 7 6
Sample Output:
3
#include<iostream> //海星
#include<vector>
using namespace std;
vector<int> pre,in;
int flag=0;
void solve(int lb, int le, int rb, int re){
if(lb>le)
return ;
if(lb==le&&flag++==0)
cout<<pre[lb]<<endl;
int i=rb;
while(i<=re&&in[i]!=pre[lb]) i++;
solve(lb+1, lb+i-rb, rb, i-1);
solve(lb+i-rb+1, le, i+1, re);
}
int main(){
int n;
cin>>n;
pre.resize(n), in.resize(n);
for(int i=0; i<n; i++)
cin>>pre[i];
for(int i=0; i<n; i++)
cin>>in[i];
solve(0, n-1, 0, n-1);
return 0;
}
PAT 1138 Postorder Traversal的更多相关文章
- PAT 1138 Postorder Traversal [比较]
1138 Postorder Traversal (25 分) Suppose that all the keys in a binary tree are distinct positive int ...
- PAT 甲级 1138 Postorder Traversal
https://pintia.cn/problem-sets/994805342720868352/problems/994805345078067200 Suppose that all the k ...
- PAT Advanced 1138 Postorder Traversal (25) [树的遍历,前序中序转后序]
题目 Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and ...
- PAT A1138 Postorder Traversal (25 分)——大树的遍历
Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and in ...
- 1138. Postorder Traversal (25)
Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and in ...
- 1138 Postorder Traversal
题意:给出二叉树的前序序列后中序序列,输出其后序序列的第一个值. 思路:乍一看不就是前序+中序重建二叉树,然后后序遍历嘛!这么做当然不会有错,但是却没有真正领会本题的意图.本题并不是让我们输出后序序列 ...
- PAT_A1138#Postorder Traversal
Source: PAT A1138 Postorder Traversal (25 分) Description: Suppose that all the keys in a binary tree ...
- [LeetCode] Binary Tree Postorder Traversal 二叉树的后序遍历
Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary ...
- [LeetCode] Construct Binary Tree from Inorder and Postorder Traversal 由中序和后序遍历建立二叉树
Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume tha ...
随机推荐
- bzoj2957 楼房重建——线段树
题目:https://www.lydsy.com/JudgeOnline/problem.php?id=2957 线段树维护两个值:cnt 能看到的最多楼房数: mx 最大斜率数: 对于一段区间,从左 ...
- KeepAlived的实现示例
KeepAlived的实现示例 KeepAlived的实现 HA Cluster配置准备: 各节点时间必须同步 ntp(6), chrony(7) 1>在centos6上 ntpdate 172 ...
- 微服务下,使用ELK做日志收集及分析
一.使用背景 目前项目中,采用的是微服务框架,对于日志,采用的是logback的配置,每个微服务的日志,都是通过File的方式存储在部署的机器上,但是由于日志比较分散,想要检查各个微服务是否有报错信息 ...
- 13、git
安装Git 网上有很多Git安装教程,如果需要图形界面,windows下建议使用TortoiseGit,linux建议使用Git GUI或者GITK.(windows下载exe安装包,linux可以使 ...
- LN : leetcode 406 Queue Reconstruction by Height
lc 406 Queue Reconstruction by Height 406 Queue Reconstruction by Height Suppose you have a random l ...
- 重新学习Java——对象和类(二)
上一节回归了如何以面向对象的思想去使用一些Java中的公共类,也设计了一些自己的类并介绍了设计类的基本方法和技巧,这一节我们将继续回顾这些内容,并争取从中获得新的体验和感受. 1. 静态域与静态方法 ...
- 重新学习Java——Java基本的程序设计结构(二)
上一节简单回顾了Java基本的一些程序设计的知识,这一节将继续根据<Java核心技术>这本书,进行这方面知识的复习与探索. 1. 字符串 Java字符串实际上就是Unicode字符序列.例 ...
- Android 仿淘宝头条竖直跑马灯式新闻标题及“分页思想
在淘宝App的首页中间位置,有一块小小的地方在不知疲倦地循坏滚动着头条标题(见下图的红框区域),这样的设计无疑能够在有限的手机屏幕上展示更丰富的内容.而实现这一功能需要用到的控件就是我在上一篇文章中提 ...
- 我的DBDA类
<?php class DBDA { public $host="localhost"; public $uid="root"; public $pwd= ...
- mongo 3.4分片集群系列之六:详解配置数据库
这个系列大致想跟大家分享以下篇章: 1.mongo 3.4分片集群系列之一:浅谈分片集群 2.mongo 3.4分片集群系列之二:搭建分片集群--哈希分片 3.mongo 3.4分片集群系列之三:搭建 ...