Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and inorder traversal sequences, you are supposed to output the first number of the postorder traversal sequence of the corresponding binary tree.

Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 50,000), the total number of nodes in the binary tree. The second line gives the preorder sequence and the third line gives the inorder sequence. All the numbers in a line are separated by a space.

Output Specification:
For each test case, print in one line the first number of the postorder traversal sequence of the corresponding binary tree.

Sample Input:

7
1 2 3 4 5 6 7
2 3 1 5 4 7 6

Sample Output:

3

#include<iostream> //海星
#include<vector>
using namespace std;
vector<int> pre,in;
int flag=0;
void solve(int lb, int le, int rb, int re){
if(lb>le)
return ;
if(lb==le&&flag++==0)
cout<<pre[lb]<<endl;
int i=rb;
while(i<=re&&in[i]!=pre[lb]) i++;
solve(lb+1, lb+i-rb, rb, i-1);
solve(lb+i-rb+1, le, i+1, re);
}
int main(){
int n;
cin>>n;
pre.resize(n), in.resize(n);
for(int i=0; i<n; i++)
cin>>pre[i];
for(int i=0; i<n; i++)
cin>>in[i];
solve(0, n-1, 0, n-1);
return 0;
}

PAT 1138 Postorder Traversal的更多相关文章

  1. PAT 1138 Postorder Traversal [比较]

    1138 Postorder Traversal (25 分) Suppose that all the keys in a binary tree are distinct positive int ...

  2. PAT 甲级 1138 Postorder Traversal

    https://pintia.cn/problem-sets/994805342720868352/problems/994805345078067200 Suppose that all the k ...

  3. PAT Advanced 1138 Postorder Traversal (25) [树的遍历,前序中序转后序]

    题目 Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and ...

  4. PAT A1138 Postorder Traversal (25 分)——大树的遍历

    Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and in ...

  5. 1138. Postorder Traversal (25)

    Suppose that all the keys in a binary tree are distinct positive integers. Given the preorder and in ...

  6. 1138 Postorder Traversal

    题意:给出二叉树的前序序列后中序序列,输出其后序序列的第一个值. 思路:乍一看不就是前序+中序重建二叉树,然后后序遍历嘛!这么做当然不会有错,但是却没有真正领会本题的意图.本题并不是让我们输出后序序列 ...

  7. PAT_A1138#Postorder Traversal

    Source: PAT A1138 Postorder Traversal (25 分) Description: Suppose that all the keys in a binary tree ...

  8. [LeetCode] Binary Tree Postorder Traversal 二叉树的后序遍历

    Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary ...

  9. [LeetCode] Construct Binary Tree from Inorder and Postorder Traversal 由中序和后序遍历建立二叉树

    Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume tha ...

随机推荐

  1. linux centos7 安装mysql-5.7.17教程(图解)

    1系统约定安装文件下载目录:/data/softwareMysql目录安装位置:/usr/local/mysql数据库保存位置:/data/mysql日志保存位置:/data/log/mysql 2下 ...

  2. 02_cfork分叉进程

    fork函数.调用它就可以在当前的进程当中给它分叉出一个新的进程.分叉出的进程就可以看看它有什么特点?

  3. 使用IntelliJ IDEA 创建Maven项目(入门)

    一. 下载Maven 下载地址:http://maven.apache.org/download.cgi tar.gz压缩格式用于unix操作系统,而zip用于windows的操作系统,但在windo ...

  4. bzoj 1647: [Usaco2007 Open]Fliptile 翻格子游戏【dfs】

    这个可以用异或高斯消元,但是我不会呀我用的暴搜 2的m次方枚举第一行的翻转情况,然后后面的就定了,因为对于一个j位置,如果i-1的j位置需要翻,那么一定要翻i的j,因为这是i-1的j最后翻的机会 按字 ...

  5. [Swift通天遁地]一、超级工具-(8)地图视图MKMapView的常用代理方法

    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★➤微信公众号:山青咏芝(shanqingyongzhi)➤博客园地址:山青咏芝(https://www.cnblogs. ...

  6. Hexo 添加Live2D看板娘

    title: Hexo 添加 Live2D看板娘 二次元什么的最喜欢了[大好きです] 准备 项目地址 live2d模型 部分模型预览 开始 首先进入Hexo博客根目录安装live2d插件 $ npm ...

  7. 微信小程序setData的使用,通过[...]进行动态key赋值

    首先先介绍一下微信小程序Page.prototype.setData(Object data, Function callback)的讲解: setData函数用于将数据从逻辑层发送到视图层(异步), ...

  8. hdu 模拟 贪心 4550

    卡片游戏 Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Su ...

  9. ACM_求N^N的前5位数和后5位数(数论)

    NNNNN Time Limit: 2000/1000ms (Java/Others) Problem Description: 对于整数N,求N^N的前5位和后5位(1057题加强版) Input: ...

  10. 388 Longest Absolute File Path 最长的绝对文件路径

    详见:https://leetcode.com/problems/longest-absolute-file-path/description/ C++: class Solution { publi ...