Description

There is a famous railway station in PopPush City. Country there is incredibly hilly. The station was built in last century. Unfortunately, funds were extremely limited that time. It was possible to establish only a surface track. Moreover, it turned out that the station could be only a dead-end one (see picture) and due to lack of available space it could have only one track. 

The local tradition is that every train arriving from the direction A continues in the direction B with coaches reorganized in some way. Assume that the train arriving from the direction A has N <= 1000 coaches numbered in increasing order 1, 2, ..., N. The chief for train reorganizations must know whether it is possible to marshal coaches continuing in the direction B so that their order will be a1, a2, ..., aN. Help him and write a program that decides whether it is possible to get the required order of coaches. You can assume that single coaches can be disconnected from the train before they enter the station and that they can move themselves until they are on the track in the direction B. You can also suppose that at any time there can be located as many coaches as necessary in the station. But once a coach has entered the station it cannot return to the track in the direction A and also once it has left the station in the direction B it cannot return back to the station.

Input

The input consists of blocks of lines. Each block except the last describes one train and possibly more requirements for its reorganization. In the first line of the block there is the integer N described above. In each of the next lines of the block there is a permutation of 1, 2, ..., N. The last line of the block contains just 0.

The last block consists of just one line containing 0.

Output

The output contains the lines corresponding to the lines with permutations in the input. A line of the output contains Yes if it is possible to marshal the coaches in the order required on the corresponding line of the input. Otherwise it contains No. In addition, there is one empty line after the lines corresponding to one block of the input. There is no line in the output corresponding to the last ``null'' block of the input.

Sample Input

5
1 2 3 4 5
5 4 1 2 3
0
6
6 5 4 3 2 1
0
0

Sample Output

Yes
No Yes 先输入火车车厢数N,然后输入N个数代表车厢编号a[i],判断火车是否能按1~N或者N~1的顺序开出,a[0] = 0;代表车厢数为N的循环结束,N = 0;代表程序结束。
思路:    
先输入车厢编号,用数组a[i]保存,在从1~N依次输入栈st中,依次判断st.top()是否等于[i].
 #include<cstdio>
#include<stack>
using namespace std;
int main()
{
int n,a[],i,j;
while(scanf("%d",&n) && n)
{
stack<int>st;
while(scanf("%d",&a[]) && a[])
{
for( i = ; i < n ; i++)
{
scanf("%d",&a[i]);
}
for( i = , j = ; i <= n ; i++)
{
st.push(i);
while(st.top() == a[j])
{
j++;
st.pop();
if(st.empty()) //栈为空时结束循环
break;
}
}
if( j == n) printf("Yes\n");
else
printf("No\n");
}
printf("\n");
}
}

poj 1363 火车进站 (栈的应用)的更多相关文章

  1. POJ 1363 Rails(栈)

    题目代号:POJ 1363 题目链接:http://poj.org/problem?id=1363 题目原题: Rails Time Limit: 1000MS   Memory Limit: 100 ...

  2. poj 1363 Rails (【栈的应用】 刘汝佳的写法 *学习)

    Rails Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 25964   Accepted: 10199 Descripti ...

  3. 华为OJ:火车进站

    火车进站 给定一个正整数N代表火车数量,0<N<10,接下来输入火车入站的序列,一共N辆火车,每辆火车以数字1-9编号.要求以字典序排序输出火车出站的序列号. 输入描述: 有多组测试用例, ...

  4. C++ HOJ 火车进站

    [问题描写叙述] 给定一个正整数N代表火车数量.0<N<10,接下来输入火车入站的序列,一共N辆火车,每辆火车以数字1-9编号. 要求以字典序排序输出火车出站的序列号. 输入:   有多组 ...

  5. (hdu)1022 Train Problem I 火车进站问题

    题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1022 Problem Description As the new term comes, ...

  6. 【火车出栈】ZOJ - 2603 Railroad Sort

    好久没写递归了,怕手生再来练练手. 题意:车轨上有上图所示的n个中转栈,现有2n个列车,给出列车初始编号序列.列车从最右边驶入车轨,并且列车只能从右向左移动,要求给出列车中转操作序列,使列车经过这n个 ...

  7. 【讲●解】火车进出栈类问题 & 卡特兰数应用

    火车进出栈类问题详讲 & 卡特兰数应用 引题:火车进出栈问题 [题目大意] 给定 \(1\)~\(N\) 这\(N\)个整数和一个大小无限的栈,每个数都要进栈并出栈一次.如果进栈的顺序为 \( ...

  8. CodeVS3958 火车进站

    3958 火车进站 时间限制: 1 s 空间限制: 256000 KB 题目等级 : 大师 Master         题目描述 Description 火车站内往往设有一些主干线分叉出去的铁路支路 ...

  9. luogu P1044 火车进出栈问题(Catalan数)

    Catalan数就是魔法 火车进出栈问题即: 一个栈(无穷大)的进栈序列为 1,2,3,4,...,n 求有多少个不同的出栈序列? 将问题进行抽象, 假设'+'代表进栈, 则有'-'代表出栈 那么如果 ...

随机推荐

  1. ————————C语言中快速排序方法——————————————

    在对浮点型排序是一定要用三木运算符(三目运算符内容下去自己看),因为如果也是用整形那样的减法的时候如果是两个十分相近的数字 可能返回一个小数(自己一会去试试),冉冉他cmp返回值是int(试试别的)因 ...

  2. poj 1664 放苹果 递归

    题目链接: http://poj.org/problem?id=1664 题目描述: 有n个苹果,m个盒子,盒子和苹果都没有顺序,盒子可以为空,问:有多少种放置方式? 解题思路: 当前有n个苹果,m个 ...

  3. js插件之Ocupload

    使用方法: var myUpload = $(element).upload({ name: 'file', action: '', enctype: 'multipart/form-data', p ...

  4. php socket通信演示以及socket操作类

    准备做Java的课程设计,一个通讯录.采用C/S架构.客户端用java FX和Java,服务器端用php,采用socket通信. 下面来讲一讲php的socket通信: 讲之前,得先讲一下TCP/IP ...

  5. shell编写的多服务器自动互信脚本(安装ceph)

    相信大家都使用过分布式存储,而在分布式存储中较为出色的非ceph莫属了,但是这里就不深入聊ceph啦,我们只是聊聊安装ceph时遇到的问题. ceph需要多台主机进行ssh互信.三台还能忍受,但是当超 ...

  6. spring 整合struts

    1.例子:未被spring整合 struts.xml 的配置文件 <constant name="struts.enable.DynamicMethodInvocation" ...

  7. mybatis 返回值

    转载: 在使用ibatis插入数据进数据库的时候,会用到一些sequence的数据,有些情况下,在插入完成之后还需要将sequence的值返回,然后才能进行下一步的操作.      使用ibatis的 ...

  8. 浅谈2015新版 U-Boot

    过了挺长一断时间没有看U-BOOT了,这两天下载了新版的UBOOT源码(之前看的一些书都是基于早好多年的源码来讲述,总感觉心里有点不对劲,也许是我比较喜新的原因吧,不过小弟我并没有厌旧哈),好了不多扯 ...

  9. nodejs的学习

    nodejs 就是使用js来编写服务端的程序.它的特性是(单线程   速度快   耗内存多  异步   事件驱动) ( 一些技术的解决方案:默认情况下是 1.不支持多核,可以使用cluster 进行解 ...

  10. jquery 点击切换div

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/ ...