Educational Codeforces Round 4 A. The Text Splitting 水题

A. The Text Splitting

题目连接：

http://www.codeforces.com/contest/612/problem/A

Description

You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.

For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".

Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).

Input

The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).

The second line contains the string s consists of lowercase and uppercase latin letters and digits.

Output

If it's impossible to split the string s to the strings of length p and q print the only number "-1".

Otherwise in the first line print integer k — the number of strings in partition of s.

Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.

If there are several solutions print any of them.

Sample Input

5 2 3

Hello

Sample Output

2

He

llo

Hint

题意

给你一个字符串，让你分割成长度为p，或者长度为q的串

问你如何分割

题解：

数据范围很小，所以直接暴力枚举就好了

代码

#include<bits/stdc++.h>
using namespace std;

string s;
int main()
{
    int n,p,q;
    cin>>n>>p>>q;
    cin>>s;
    for(int i=0;i<150;i++)
    {
        for(int j=0;j<150;j++)
        {
            if(i*p+j*q==s.size())
            {
                cout<<i+j<<endl;
                for(int k=0;k<i;k++)
                {
                    for(int t=0;t<p;t++)
                        cout<<s[k*p+t];
                    cout<<endl;
                }
                for(int k=0;k<j;k++)
                {
                    for(int t=0;t<q;t++)
                        cout<<s[i*p+k*q+t];
                    cout<<endl;
                }
                return 0;
            }
        }
    }
    return puts("-1");
}