OpenJudge / Poj 1928 The Peanuts C++

链接地址：http://bailian.openjudge.cn/practice/1928

题目：

总时间限制:

1000ms

内存限制:

65536kB

描述

Mr. Robinson and his pet monkey Dodo love peanuts very much. One day while they were having a walk on a country road, Dodo found a sign by the road, pasted with a small piece of paper, saying "Free Peanuts Here! " You can imagine how happy Mr. Robinson and Dodo were.

There
was a peanut field on one side of the road. The peanuts were planted
on the intersecting points of a grid as shown in Figure-1. At each
point, there are either zero or more peanuts. For example, in Figure-2,
only four points have more than zero peanuts, and the numbers are 15,
13, 9 and 7 respectively. One could only walk from an intersection
point to one of the four adjacent points, taking one unit of time. It
also takes one unit of time to do one of the following: to walk from
the road to the field, to walk from the field to the road, or pick
peanuts on a point.

According
to Mr. Robinson's requirement, Dodo should go to the plant with the
most peanuts first. After picking them, he should then go to the next
plant with the most peanuts, and so on. Mr. Robinson was not so patient
as to wait for Dodo to pick all the peanuts and he asked Dodo to return
to the road in a certain period of time. For example, Dodo could pick
37 peanuts within 21 units of time in the situation given in Figure-2.

Your
task is, given the distribution of the peanuts and a certain period of
time, tell how many peanuts Dodo could pick. You can assume that each
point contains a different amount of peanuts, except 0, which may appear
more than once.

输入

The first line of input contains the test case number T (1 <= T
<= 20). For each test case, the first line contains three integers,
M, N and K (1 <= M, N <= 50, 0 <= K <= 20000). Each of the
following M lines contain N integers. None of the integers will exceed
3000. (M * N) describes the peanut field. The j-th integer X in the
i-th line means there are X peanuts on the point (i, j). K means Dodo
must return to the road in K units of time.

输出

For each test case, print one line containing the amount of peanuts Dodo can pick.

样例输入

2
6 7 21
0 0 0 0 0 0 0
0 0 0 0 13 0 0
0 0 0 0 0 0 7
0 15 0 0 0 0 0
0 0 0 9 0 0 0
0 0 0 0 0 0 0
6 7 20
0 0 0 0 0 0 0
0 0 0 0 13 0 0
0 0 0 0 0 0 7
0 15 0 0 0 0 0
0 0 0 9 0 0 0
0 0 0 0 0 0 0

样例输出

37
28

来源

Beijing 2004 Preliminary@POJ

思路：

每次采摘前计算是否能够采摘，模拟题

代码：

 #include <iostream>
 #include <cstdlib>
 using namespace std;

 int main()
 {
     int t;
     cin>>t;
     while(t--)
     {
         int m,n,k;
         cin>>m>>n>>k;
         int *arr = new int[m*n];
         for(int i = ; i < m; i++)
         {
             for(int j = ; j < n; j++)
             {
                 cin>>arr[i * n + j];
             }
         }
         int sum = ,ni=,nj;
         int max,maxi,maxj;
         k -= ;
         int flag = ;
         do
         {
             max = -;
             for(int i = ; i < m; i++)
             {
                 for(int j = ; j < n; j++)
                 {
                     if(max < arr[i * n + j])
                     {
                         max = arr[i * n + j];
                         maxi = i;
                         maxj = j;
                     }
                 }
             }
             if(flag) {nj = maxj;flag = ;}
             int step = abs(maxi - ni) + abs(maxj - nj) + ;
             if(step + maxi > k) break;
             else
             {
                 k -= step;
                 sum += max;
                 ni = maxi;
                 nj = maxj;
                 arr[maxi * n + maxj] = ;
             }

         }while();
         cout<<sum<<endl;
         delete [] arr;
     }
     return ;
 }