PAT (Advanced Level) 1103. Integer Factorization (30)
暴力搜索。
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<algorithm>
using namespace std; int n,k,p,top;
int path[];
int flag=;
int ans_path[],ans_num=,ans_len; void dfs(int x,int pre,int sum,int num)
{
if(sum>n) return;
if(x>k) return;
if(sum==n)
{
if(x!=k) return; flag=;
if(num>ans_num)
{
ans_num=num;
ans_len=x;
for(int i=;i<x;i++) ans_path[i]=path[i];
} return;
}
for(int i=pre;i>=;i--)
{
path[x]=i;
dfs(x+,i,sum+int(pow(i,p)+0.5),num+i);
}
}
int main()
{
scanf("%d%d%d",&n,&k,&p);
top=(int) (pow(1.0*n,1.0/p)+0.5);
top=min(top,n/k); //加这个剪枝速度还可以提高一些 dfs(,top,,);
if(flag==) printf("Impossible\n");
else
{
printf("%d = ",n); for(int i=;i<ans_len;i++)
{
printf("%d^%d",ans_path[i],p);
if(i!=ans_len-) printf(" + ");
}
}
return ;
}
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