输入一个正整数n (1<n<=10)，生成 1个 n*n 方阵 求出对角线之和

#define  _CRT_SECURE_NO_WARNINGS

#include <Windows.h>
#include <stdio.h>
#include <stdlib.h>

void main() {

    int n = ;
    scanf("%d", &n);

    int a[][] = {  };
    int result = ;
    for (int i = ; i < n * n; i++) {
        a[i / n][i % n] = i + ;
        if ((i % n) == ){
            result += a[i / n][i % n] + (i / n);
        }
    }
    for (int i = ; i < n; i++) {
        for (int j = ; j < n; j++)
        {
            printf("%-6d", a[i][j]);
        }
        printf("\n");
    }
    printf("result=%d", result);

    getchar();
    getchar();
}