216. Combination Sum III——本质DFS
Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
class Solution(object):
def combinationSum3(self, k, n):
"""
:type k: int
:type n: int
:rtype: List[List[int]]
"""
ans = []
path = []
if k<=0 or n<=0:
return ans
self.comb_helper(k, n, 1, path, ans)
return ans def comb_helper(self, k, n, start, path, ans):
if n<0:
return
if n==0 and k==0:
ans.append(list(path))
return
for i in xrange(start, 10):
path.append(i)
self.comb_helper(k-1, n-i, i+1, path, ans)
path.pop()
216. Combination Sum III——本质DFS的更多相关文章
- leetcode 39. Combination Sum 、40. Combination Sum II 、216. Combination Sum III
39. Combination Sum 依旧与subsets问题相似,每次选择这个数是否参加到求和中 因为是可以重复的,所以每次递归还是在i上,如果不能重复,就可以变成i+1 class Soluti ...
- [LeetCode] 216. Combination Sum III 组合之和 III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- 【LeetCode】216. Combination Sum III
Combination Sum III Find all possible combinations of k numbers that add up to a number n, given tha ...
- LC 216. Combination Sum III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- 【刷题-LeetCode】216. Combination Sum III
Combination Sum III Find all possible combinations of k numbers that add up to a number n, given tha ...
- Java for LeetCode 216 Combination Sum III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- 39. Combination Sum + 40. Combination Sum II + 216. Combination Sum III + 377. Combination Sum IV
▶ 给定一个数组 和一个目标值.从该数组中选出若干项(项数不定),使他们的和等于目标值. ▶ 36. 数组元素无重复 ● 代码,初版,19 ms .从底向上的动态规划,但是转移方程比较智障(将待求数分 ...
- Leetcode 216. Combination Sum III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- LeetCode Combination Sum III (DFS)
题意: 在1-9这9个数字中选择k个出来,若他们的和为n,则加入答案序列,注意升序. 思路: 用DFS的方式,每次决定一个数字,共决策k次.假设上个决策是第i位为5,那么i+1位的范围就是6-9. c ...
随机推荐
- LINQ 简单用法【1】
LINQ:Language INtegrated Query,语言集成查询. 以下内容演示如何利用LINQ进行增加,修改,删除和查询操作,针对数据库. 首先创建Linq Class. 添加数据库信息, ...
- FZU 2218 Simple String Problem(简单字符串问题)
Description 题目描述 Recently, you have found your interest in string theory. Here is an interesting que ...
- c 字符串常用函数
#include <iostream> #include <stdio.h> #include <vector> #include "string.h&q ...
- FileCopy
/*[入]指的是到内存里,[出]指的是到内存外*/ import java.io.*; public class MyReadFile{ public static void main(String[ ...
- linux终端下 编译c语言程序
linux终端下,编译C语言程序步骤为: 采用vi进行源代码编写,编写完成后,:wq存盘退出,如: vi test.c 在命令行下,运行gcc编译程序,生成执行码,如: gcc -o test te ...
- JavaWeb学习总结(十五)--过滤器的应用
一.解决全站字符乱码(post和get中文编码问题) 乱码问题: 获取请求参数中的乱码问题: POST请求:request.setCharacterEncoding("utf-8" ...
- number-of-segments-in-a-string
https://leetcode.com/problems/number-of-segments-in-a-string/ package com.company; class Solution { ...
- RTC框架
RPC是系统间的一种通信方式,系统间常用的通信方式还有http,webservice,rpc等,一般来讲rpc比http和webservice性能高一些,常见的RPC框架有:thrift,Finagl ...
- 青云的机房组网方案(简单+普通+困难)(虚树+树形DP+容斥)
题目链接 1.对于简单的版本n<=500, ai<=50 直接暴力枚举两个点x,y,dfs求x与y的距离. 2.对于普通难度n<=10000,ai<=500 普通难度解法挺多 ...
- 将spring管理的bean使用注解的方式注入到servlet中
Filter和Servlet中不能直接注解使用spring的bean,因为这两个都是servlet容器维护管理的,当然也有实现方法,如下: 1.创建一个AbstractServlet 抽象类,让你的所 ...