https://leetcode.com/problems/number-of-segments-in-a-string/

package com.company;

class Solution {
public int countSegments(String s) {
String[] strs = s.split(" ");
int count = ;
for (String str : strs) {
if (str.length() > ) {
count++;
}
}
return count;
}
} public class Main { public static void main(String[] args) throws InterruptedException { String s = "Hello, my name is John"; Solution solution = new Solution();
int ret = solution.countSegments(s); // Your Codec object will be instantiated and called as such:
System.out.printf("ret:%d\n", ret); System.out.println(); } }

number-of-segments-in-a-string的更多相关文章

  1. [LeetCode] Number of Segments in a String 字符串中的分段数量

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  2. Leetcode: Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  3. 每天一道LeetCode--434. Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  4. 【LeetCode】434. Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  5. [Swift]LeetCode434. 字符串中的单词数 | Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  6. 434. Number of Segments in a String

    原题: 434. Number of Segments in a String 解题: 刚看到题目时,觉得可以通过统计空格个数,但想想有可能会有多个空格的情况 思路: 一:遍历字符,if条件碰到非空格 ...

  7. 434. Number of Segments in a String 字符串中的单词个数

    [抄题]: Count the number of segments in a string, where a segment is defined to be a contiguous sequen ...

  8. LeetCode_434. Number of Segments in a String

    434. Number of Segments in a String Easy Count the number of segments in a string, where a segment i ...

  9. [LC] 434. Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  10. C#LeetCode刷题之#434-字符串中的单词数​​​​​​​(Number of Segments in a String)

    问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3941 访问. 统计字符串中的单词个数,这里的单词指的是连续的不是 ...

随机推荐

  1. javaWEB国际化:DateFormat,NumberFormat,MessageFormat,ResourceBundle的使用

    DateFormat:格式化日期的工具类,本身是一个抽象类: NumberFormat:格式化 数字 到 数字字符串,或货币字符串的字符类; MessageFormat: 可以格式化模式字符串,模式字 ...

  2. Google Analytics Premium VS Adobe Analytics

    在很久以前的互联网年代,Google收购了一家名为Urchin的公司,进而演化诞生了Google Analytics.当Goochin(Google / Urchin)首次亮相时,它被所有人称为“新的 ...

  3. Apache Commons-pool实现对象池(包括带key对象池)

    Commons-pool是一个apache开源组织下的众多项目的一个.其被广泛地整合到众多需要对象池功能的项目中. 官网:http://commons.apache.org/proper/common ...

  4. 对table的tr使用display:block显示colspan失效问题的解决

    qqqq <table> <tr> <td id="qqq" colspan="3" style="display:no ...

  5. 2016年10月15日 星期六 --出埃及记 Exodus 18:26

    2016年10月15日 星期六 --出埃及记 Exodus 18:26 They served as judges for the people at all times. The difficult ...

  6. zookeeper系列之十一—zookeeper会话超时

    1.会话概述 在Zookeeper中,客户端和服务端建立连接后,会话随之建立,生成一个全局唯一的会话ID(Session ID).服务器和客户端之间维持的是一个长连接,在SEESSION_TIMEOU ...

  7. svn转移版本库

    1.导出 svnadmin dump命令语法svnadmin dump REPOS_PATH [-r LOWER[:UPPER]] [--incremental] 示例:svnadmin dump E ...

  8. .Net面試4套

    一 1. 面向对象的思想主要包括什么? 答: 继承,多态,封装,类,对象,接口,聚集,聚合,泛化 2. 什么是ASP.net中的用户控件 答: 用户控件就是使用.ascx作为扩展名的文件,其将多种服务 ...

  9. CodeForces 219B Special Offer! Super Price 999 Bourles!

    Special Offer! Super Price 999 Bourles! Time Limit:1000MS     Memory Limit:262144KB     64bit IO For ...

  10. Linux 新手非常有用的命令

    http://www.cnblogs.com/felix-/p/4341773.html Linux 新手非常有用的命令 你打算从Windows换到Linux上来,还是你刚好换到Linux上来?哎哟! ...