216. Combination Sum III——本质DFS
Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
class Solution(object):
def combinationSum3(self, k, n):
"""
:type k: int
:type n: int
:rtype: List[List[int]]
"""
ans = []
path = []
if k<=0 or n<=0:
return ans
self.comb_helper(k, n, 1, path, ans)
return ans def comb_helper(self, k, n, start, path, ans):
if n<0:
return
if n==0 and k==0:
ans.append(list(path))
return
for i in xrange(start, 10):
path.append(i)
self.comb_helper(k-1, n-i, i+1, path, ans)
path.pop()
216. Combination Sum III——本质DFS的更多相关文章
- leetcode 39. Combination Sum 、40. Combination Sum II 、216. Combination Sum III
39. Combination Sum 依旧与subsets问题相似,每次选择这个数是否参加到求和中 因为是可以重复的,所以每次递归还是在i上,如果不能重复,就可以变成i+1 class Soluti ...
- [LeetCode] 216. Combination Sum III 组合之和 III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- 【LeetCode】216. Combination Sum III
Combination Sum III Find all possible combinations of k numbers that add up to a number n, given tha ...
- LC 216. Combination Sum III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- 【刷题-LeetCode】216. Combination Sum III
Combination Sum III Find all possible combinations of k numbers that add up to a number n, given tha ...
- Java for LeetCode 216 Combination Sum III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- 39. Combination Sum + 40. Combination Sum II + 216. Combination Sum III + 377. Combination Sum IV
▶ 给定一个数组 和一个目标值.从该数组中选出若干项(项数不定),使他们的和等于目标值. ▶ 36. 数组元素无重复 ● 代码,初版,19 ms .从底向上的动态规划,但是转移方程比较智障(将待求数分 ...
- Leetcode 216. Combination Sum III
Find all possible combinations of k numbers that add up to a number n, given that only numbers from ...
- LeetCode Combination Sum III (DFS)
题意: 在1-9这9个数字中选择k个出来,若他们的和为n,则加入答案序列,注意升序. 思路: 用DFS的方式,每次决定一个数字,共决策k次.假设上个决策是第i位为5,那么i+1位的范围就是6-9. c ...
随机推荐
- JS——ajax login test
1.新建一个webproject,我用的是myeclipse10,建立如下的LoginServlet.java文件 2.编写java文件 import java.io.IOException; imp ...
- Codeforces Round #382 (Div. 2) C. Tennis Championship 斐波那契
C. Tennis Championship time limit per test 2 seconds memory limit per test 256 megabytes input stand ...
- hdu 2196 Computer 树的直径
Computer Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem ...
- JSP学习——语法(二)
1:JSP运行原理和九大隐式对象: 每个JSP 页面在第一次被访问时,WEB容器都会把请求交给JSP引擎(即一个Java程序)去处理.JSP引擎先将JSP翻译成一个_jspServlet(实质上也是一 ...
- SAP 关于标准成本、计划成本、目标成本、实际成本
SAP 关于标准成本.计划成本.目标成本.实际成本 <A style="MARGIN-RIGHT: 10px" target=_blank data-ext="{v ...
- [转载] HTTP请求的TCP瓶颈分析
原文: http://bhsc881114.github.io/2015/06/23/HTTP%E8%AF%B7%E6%B1%82%E7%9A%84TCP%E7%93%B6%E9%A2%88%E5%8 ...
- default(T)的含义
default(T)是泛型中初始化的用法.因为对于泛型T你不知道是值类型还是引用类型,所以传参数是可能会出错.这里就要用到default(T). T t=default(T),就是初始化,值类型的话, ...
- Docker-网络基础配置
从外部访问容器 指定容器端口随机映射主机端口 [root@wls12c /]$ docker run -p -d --name web tomcat /bin/bash -c /root/apache ...
- linux登录mysql
mysql -u 用户名 -p密码 mysql -u root -psqj888
- unsigned char 无符号整形 减法运算
对于一个字节来说: unsigned char : 0 ~ 255 0000 0000 ~ 1111 1111 char :-128 ~ 127 ...