题目描述:Fire Net
 
Suppose that we have a square city with straight streets. A map of a city is a square board with n rows and n columns, each representing a street or a piece of wall. A blockhouse is a small castle that has four openings through which to shoot. The four openings are facing North, East, South, and West, respectively. There will be one machine gun shooting through each opening. Here we assume that a bullet is so powerful that it can run across any distance and destroy a blockhouse on its way. On the other hand, a wall is so strongly built that can stop the bullets. The goal is to place as many blockhouses in a city as possible so that no two can destroy each other. A configuration of blockhouses is legal provided that no two blockhouses are on the same horizontal row or vertical column in a map unless there is at least one wall separating them. In this problem we will consider small square cities (at most 4x4) that contain walls through which bullets cannot run through. The following image shows five pictures of the same board. The first picture is the empty board, the second and third pictures show legal configurations, and the fourth and fifth pictures show illegal configurations. For this board, the maximum number of blockhouses in a legal configuration is 5; the second picture shows one way to do it, but there are several other ways.  Your task is to write a program that, given a description of a map, calculates the maximum number of blockhouses that can be placed in the city in a legal configuration.

输入

The input file contains one or more map descriptions, followed by a line containing the number 0 that signals the end of the file. Each map description begins with a line containing a positive integer n that is the size of the city; n will be at most 4. The next n lines each describe one row of the map, with a '.' indicating an open space and an uppercase 'X' indicating a wall. There are no spaces in the input file.

输出

For each test case, output one line containing the maximum number of blockhouses that can be placed in the city in a legal configuration.

样例输入

4
.X..
....
XX..
....
2
XX
.X
3
.X.
X.X
.X.
3
...
.XX
.XX
4
....
....
....
....
0

样例输出

5
1
5
2
4
 

这道题看着麻烦,实际就是讲了棋盘放位置的策略。总体和n皇后问题很类似。

// Fire Net.cpp : 定义控制台应用程序的入口点。
// //解题思路:
//1.类似n皇后问题,上下左右不能有重复,只检测上方和左方即可,下面的没有放到,不需要检查。
//2.走斜角坐标,x = pos/n,y = pos % n
//3.每个坐标存在能放和不能放两种情况 #include "stdafx.h" #include <stdio.h>
#include <string.h> #define M 10
int n,ans;
char map[M][M]; int check(int x, int y)
{
if (map[x][y] == 'X') return ; //左方
for (int col = y - ; col >= ; col--)
{
if (map[x][col] == 'X')
break;
if (map[x][col] == '#')
return ;
} //上方
for (int row = x - ; row >= ; row--)
{
if (map[row][y] == 'X')
break;
if (map[row][y] == '#')
return ;
} return ; } void DFS(int pos, int sum)
{
int x = pos / n, y = pos % n;//x,y 的位置
if (pos == n * n)
{
ans = ans > sum? ans:sum;
return;
}
if (check(x, y))
{
map[x][y] = '#';
DFS(pos + , sum + );
map[x][y] = '.';
} DFS(pos + , sum);
} int main()
{
while (~scanf("%d", &n) && n)
{
memset(map, '\0', sizeof(map)); for (int i = ; i < n; i++)
scanf("%s", &map[i]); ans = ;
DFS(,);
printf("%d\n", ans); }
return ;
}

ACM-Fire Net的更多相关文章

  1. ACM: FZU 2150 Fire Game - DFS+BFS+枝剪 或者 纯BFS+枝剪

    FZU 2150 Fire Game Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u ...

  2. 【Acm】算法之美—Fire Net

    题目概述:Fire Net Suppose  that we have a square city with straight streets. A map of a city is a square ...

  3. [acm 1002] 浙大 Fire Net

    已转战浙大 题目 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=2 浙大acm 1002 #include <iostre ...

  4. 杭电ACM分类

    杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze ...

  5. HDU1045 Fire Net(DFS)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit: 2000/1000 MS (Java/Others)  ...

  6. ACM -二分图题目小结

    暂时只包括与最大匹配相关的问题. 求最大独立集,最小路径覆盖等等大多数题目都可以转化为求最大匹配用匈牙利算法解决. 1.最大匹配(边集) 此类问题最直接,直接用匈牙利算法即可. HDU 2063  过 ...

  7. hdu 1045 Fire Net(最小覆盖点+构图(缩点))

    http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit:1000MS     Memory Limit:32768KB   ...

  8. zoj 3820 Building Fire Stations 树的中心

    Building Fire Stations Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.zju.edu.cn/onlinejudge ...

  9. HDU-1045 Fire Net

    http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit: 2000/1000 MS (Java/Others)    Me ...

  10. (FZU 2150) Fire Game (bfs)

    题目链接:http://acm.fzu.edu.cn/problem.php?pid=2150 Problem Description Fat brother and Maze are playing ...

随机推荐

  1. Intent的常用属性action和category

    设置隐式跳转 首先在我们按钮监听器中添加 Intent i=new Intent(); //参数为字符串,可以添加包名.活动名 i.setAction("com.example.aaaaa. ...

  2. 如何知道某个ACTIVITY是否在前台?

    本文链接:http://zengrong.net/post/1680.htm 有一个Android应用包含包含一个后台程序,该程序会定期连接服务器来实现自定义信息的推送.但是,当这个应用处于前台的时候 ...

  3. JavaScript之bind方法实现代码分析

    我们来分析一下bind方法的实现代码,下图的bind方法的实现为MDN(开发者社区)中的代码. 由上图可得:bind方法实现了两个功能:绑定this和科里化.

  4. tcp/ip协议学习笔记一

    一. 简述 以前在学校学习计算机网络的时候学习多是网络7层模型OSI,了解了一些基本的计算机网络概念和协议通信格式,但是一直没弄明白其中的原理,包括各层之间的关系,应用,还有一些常见的令牌环网到底是什 ...

  5. saveToken介绍二

      Struts的Token(令牌)机制能够很好的解决表单重复提交的问题,基本原理是:服务器端在处理到达的请求之前,会将请求中包含的令牌值与保存在当前用户会话中的令牌值进行比较,看是否匹配.在处理完该 ...

  6. MQTT v5 (MQTT 5.0) 新特性介绍

    https://blog.csdn.net/mrpre/article/details/87267400 背景 MQTT v3.1.1 作为一个经典的版本,一般能够满足大部分需求:为了避免落后,我们也 ...

  7. 蓝桥杯 能量项链 (区间dp)

    问题描述 在Mars星球上,每个Mars人都随身佩带着一串能量项链.在项链上有N颗能量珠.能量珠是一颗有头标记与尾标记的珠子,这些标记对应着某个正整数.并且,对于相邻的两颗珠子,前一颗珠子的尾标记一定 ...

  8. Oracle 的DBA考证

    转自 :https://www.cnblogs.com/chunge2050/archive/2013/04/16/3023730.html 详细的了解了几天之后,总结起来就是oracle为DBA认证 ...

  9. springboot官网->application.properties文件

    springboot application.properties 2.1.6.RELEASE

  10. word中图片的导出

    楼上说到的方法都是可行的,其实还有个更方便快捷的保存方式,特别是看到一篇word文档里有很多好看的图片想以图片格式单独保存下来观赏,用作其它,如QQ表情等,此方法更见优势:打开文档——文件——另存为— ...