/*
* Winner.cpp
*
* Created on: 2013-10-13
* Author: wangzhu
*/ /**
* 先找出所有选手的分数和中最大的分数和,之后在所有选手的分数和中看有几个是和最大的分数和相等,
* 1)、若有多个,则比较谁在比赛结束钱分数先达到最大分数和,则是赢家;
* 2)、若只有一个,则直接输出。
*/
#include<cstdio>
#include<iostream>
#include<map>
#include<string.h>
using namespace std;
#define NMAX 1010
struct Node {
int index, val;
char name[];
};
Node node[NMAX];
map<string, int> myMap;
map<string, int> myMap1;
map<string, int>::iterator mapIterator; void find(int n, int nmax) {
int m;
for (int i = ; i < n; i++) {
for (mapIterator = myMap1.begin(); mapIterator != myMap1.end();
mapIterator++) {
if ( == strcmp(node[i].name, mapIterator->first.c_str())) {
// printf("%d %d %s\n", node[i].index, node[i].val, node[i].name);
m = myMap1[mapIterator->first];
m += node[i].val;
myMap1[mapIterator->first] = m;
if (m >= nmax) {
printf("%s\n", node[i].name);
return;
}
}
}
}
} int main() {
freopen("data.in", "r", stdin);
int n, m,nmax;
string nmaxStr;
while (~scanf("%d", &n)) {
myMap.clear();
myMap1.clear(); for (int i = ; i < n; i++) {
scanf("%s%d", node[i].name, &node[i].val);
node[i].index = i;
myMap[node[i].name] +=node[i].val;
}
nmax = -;
for(mapIterator = myMap.begin();mapIterator!=myMap.end();mapIterator++){
if(nmax < mapIterator->second){
nmax = mapIterator->second;
}
}
m = ;
for(mapIterator = myMap.begin();mapIterator!=myMap.end();mapIterator++){
if(nmax == mapIterator->second){
nmaxStr = mapIterator->first;
myMap1[mapIterator->first] = ;
m ++;
}
}
//printf("%d %d\n",m,nmax);
if(m != ){
find(n,nmax);
}else{
printf("%s\n",nmaxStr.c_str());
}
}
return ;
}

codeforces Winner的更多相关文章

  1. codeforces 2A Winner (好好学习英语)

    Winner 题目链接:http://codeforces.com/contest/2/problem/A ——每天在线,欢迎留言谈论. 题目大意: 最后结果的最高分 maxscore.在最后分数都为 ...

  2. CodeForces 2A - Winner(模拟)

    题目链接:http://codeforces.com/problemset/problem/2/A A. Winner time limit per test 1 second memory limi ...

  3. CodeForces 2A Winner

    Winner Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Statu ...

  4. Codeforces Beta Round #2 A. Winner 水题

    A. Winner 题目连接: http://www.codeforces.com/contest/2/problem/A Description The winner of the card gam ...

  5. Codeforces 2A :winner

    A. Winner time limit per test 1 second memory limit per test 64 megabytes input standard input outpu ...

  6. Codeforces Beta Round #2 A. Winner

    A. Winner time limit per test 1 second memory limit per test 64 megabytes input standard input outpu ...

  7. Codeforces Gym100952 A.Who is the winner? (2015 HIAST Collegiate Programming Contest)

      A. Who is the winner?   time limit per test 1 second memory limit per test 64 megabytes input stan ...

  8. Codeforces Round #603 (Div. 2) C. Everyone is a Winner! 二分

    C. Everyone is a Winner! On the well-known testing system MathForces, a draw of n rating units is ar ...

  9. Codeforces Round #603 (Div. 2) C. Everyone is a Winner! (数学)

    链接: https://codeforces.com/contest/1263/problem/C 题意: On the well-known testing system MathForces, a ...

随机推荐

  1. 你hack那么多啊,该怎么办

    当我们通过javascript来操作css样式的时候,假如我们停留在css2的阶段,会发现操作起来并不是很困难.虽然存在一些浏览器兼容的问题,但我们通过封装自己的函数,不仅可以设置样式还能够获取样式. ...

  2. java面板

    import java.awt.Color; import java.awt.Container; import javax.swing.JFrame; import javax.swing.JLab ...

  3. JAXB - Validate Document before It is Unmarshalled

    Validation A considerable part of the XML Schema language deals with facets, enabling the programmer ...

  4. 【JQuery基础教程(第三版)图灵】笔记

    第1章 jQuery入门 1.jQuery官方网站:http://jquery.com   2.开发工具:Firebug         第2章 选择元素 1.属性选择符:属性选择符通过HTML元素的 ...

  5. 通过Workbook类 生成Excel导出数据

    需求: 实现错误信息生成Excel保存到本地让用户查看. 刚开始使用了微软自带的Microsoft.Office.Interop.Excel类库. Microsoft.Office.Interop.E ...

  6. activity调用finish方法理解

    /** * Call this when your activity is done and should be closed. The * ActivityResult is propagated ...

  7. partial与sorted

    import functools sorted_ignore_case = functools.partial(sorted,cmp=lambda s1, s2: cmp(s1.upper(), s2 ...

  8. IIS6.0、IIS7中的站点、应用程序和虚拟目录详细介绍

    这里说的不是如何解决路径重写或者如何配置的问题,而是阐述一下站点(site),应用程序(application)和虚拟目录 (virtual directory)概念与作用,已及这三个东西在IIS6与 ...

  9. 牵扯较多属性和方法的类题目,很简单的题目本来不想发的,如果有同学学到这个题目感觉太长不愿敲代码,copy走我的即可~不过还是建议自己打一打

    /* 3.设计一个"学生"类 1> 属性 * 姓名 * 生日 * 年龄 * 身高(单位是m) * 体重(单位是kg) * 性别 * C语言成绩 * OC成绩 * iOS成绩 ...

  10. Java实战之03Spring-05Spring中的事务控制(基于AOP)

    五.Spring中的事务控制(基于AOP) 1.Spring中事务有关的接口 1.1.明确: JavaEE体系进行分层开发,事务处理位于业务层,Spring提供了分层设计业务层的事务处理解决方案 1. ...