LeetCode OJ：Reverse Bits（旋转bit位）

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).

注意应该做到平台无关性，需要做到这样的话应该声明一个uint32量然后一直向左移，知道得到 0 就可以得到uint32的位数大小 ：

 class Solution {
 public:
     uint32_t reverseBits(uint32_t n) {
         uint32_t result = ;
         for(uint32_t i = ; i != ; i <<= ){
             result <<= ;
             result |= (n & );
             n >>= ;
         }
         return result;
     }
 };