HDOJ-2054

A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 88211    Accepted Submission(s): 13922

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

Input

each test case contains two numbers A and B.

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

Sample Input

1 2
2 2
3 3
4 3

 

Sample Output

NO
YES
YES
NO

 

本以为是一道水题，没想到处处坑点，被坑了一发。。

数组尽量开大一点，注意小数后无意义的0

AC代码：

 #include<iostream>
 #include<cstdio>
 #include<cstring>
 using namespace std;

 const int MAX=;
 char a[MAX]={},b[MAX]={};

 int main(){

     while(scanf("%s %s",&a,&b)!=EOF){
         int i=;
         if(strchr(a,'.')){//a中是否含小数点
             for(i=strlen(a)-;a[i]=='';i--)
                 a[i]='\0';//消掉末尾的0
                 if(a[i]='.')
                 a[i]='\0';//消掉无意义的小数点
         }
         if(strchr(b,'.')){
             for(i=strlen(b)-;b[i]=='';i--)
                 b[i]='\0';
                 if(b[i]='.')
                  b[i]='\0';
         }
         printf(strcmp(a,b)?"NO\n":"YES\n");//strcmp函数当a，b相等时返回值为0
     }
     return ;
 }