如何正确使用@Bulider与<T>返回数据

@Data
@ToString
@Builder
@AllArgsConstructor
public class PageResult<T> implements Serializable {
    private List<T>items;
    private long counts;
    private long page;
    private long pageSize;
}

上述为一个简单的实体类，接下来我们需要通过建造者模式构建他

PageResult pageResult1=PageResult.builder()
                .items(courseBaseIPage.getRecords())
                .counts(courseBaseIPage.getTotal())
                .page(courseBaseIPage.getPages())
                .pageSize(courseBaseIPage.getSize())
                .build();

按照提示修改完成之后

PageResult pageResult1=PageResult.builder()
                .items(Collections.singletonList(courseBaseIPage.getRecords()))
                .counts(courseBaseIPage.getTotal())
                .page(courseBaseIPage.getPages())
                .pageSize(courseBaseIPage.getSize())
                .build();

通过上述做法会使records再加上一层[ ]，即本来是item= [ ]，而现在则是item=[ [ ] ]，那么如何保持item=[ ]?

使用T的正确做法

PageResult pageResult1=PageResult.<CourseBase>builder()
                .items(courseBaseIPage.getRecords())
                .counts(courseBaseIPage.getTotal())
                .page(courseBaseIPage.getPages())
                .pageSize(courseBaseIPage.getSize())
                .build();