leetcode-263-丑数一

题目描述：

方法一：递归

class Solution:
    def isUgly(self, num: int) -> bool:
        if num == 0: return False
        if num == 1:return True
        if num % 2 == 0: return self.isUgly(num // 2)
        if num % 3 == 0: return self.isUgly(num // 3)
        if num % 5 == 0: return self.isUgly(num // 5)
        return False

方法二：迭代

class Solution:
    def isUgly(self, num: int) -> bool:
        for p in 2, 3, 5:
            while num % p == 0 < num:
                num //= p
        return num == 1