Paint the Wall ZOJ - 2747

点数很多，坐标值很大，然后离散化一下用一个点表示一小块的面积对应的颜色，然后更新的时候一块一块更新，查询的时候一块一块查询

#include<map>
#include<set>
#include<ctime>
#include<cmath>
#include<stack>
#include<queue>
#include<string>
#include<vector>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<algorithm>
#define lowbit(x) (x & (-x))

typedef unsigned long long int ull;
typedef long long int ll;
const double pi = 4.0*atan(1.0);
const int inf = 0x3f3f3f3f;
const int maxn = ;
const int maxm = ;
const int mod = 1e9+;
using namespace std;

int n, m;
int T, tol;
struct Node {
    int x1, y1;
    int x2, y2;
    int w;
};
Node node[maxn];
int X[maxn];
int Y[maxn];
int maps[maxn][maxn];
int ans[maxn];

void init() {
    memset(X, , sizeof X);
    memset(Y, , sizeof Y);
    memset(ans, , sizeof ans);
    memset(node, , sizeof node);
    memset(maps, , sizeof maps);
}

int main() {
    int cas = ;
    while(scanf("%d%d", &n, &m), n||m) {
        if(cas != )    printf("\n");
        init();
        int q;
        scanf("%d", &q);
        int cx = , cy = ;
        int x1, y1, x2, y2, w;
        int mw = ;
        for(int i=; i<=q; i++) {
            scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &w);
            X[cx++] = x1, Y[cy++] = y1;
            X[cx++] = x2, Y[cy++] = y2;
            node[i].x1 = x1, node[i].y1 = y1;
            node[i].x2 = x2, node[i].y2 = y2;
            node[i].w = w;
            mw = max(mw, w);
        }
        sort(X, X+cx);
        sort(Y, Y+cy);
        cx = unique(X, X+cx) - X;
        cy = unique(Y, Y+cy) - Y;
//        for(int i=0; i<cx; i++)    printf("%d%c", X[i], i==cx-1 ? '\n' : ' ');
//        for(int i=0; i<cy; i++)    printf("%d%c", Y[i], i==cy-1 ? '\n' : ' ');
//        printf("\n");
        for(int i=; i<=q; i++) {
            x1 = lower_bound(X, X+cx, node[i].x1) - X;
            x2 = lower_bound(X, X+cx, node[i].x2) - X;
            y1 = lower_bound(Y, Y+cy, node[i].y1) - Y;
            y2 = lower_bound(Y, Y+cy, node[i].y2) - Y;
//            printf("%d %d %d %d\n", x1, y1, x2, y2);
            for(int x=x1; x<x2; x++) {
                for(int y=y1; y<y2; y++) {
                    maps[x][y] = node[i].w;
                }
            }
        }
//        printf("\n");
//        for(int i=0; i<cx; i++)    for(int j=0; j<cy; j++)    printf("%d%c", maps[i][j], j==cy-1 ? '\n' : ' ');
        for(int i=; i<cx; i++) {
            for(int j=; j<cy; j++) {
                if(!maps[i][j])    continue;
                w = maps[i][j];
                int area = (X[i+] - X[i]) * (Y[j+] - Y[j]);
                ans[w] += area;
            }
        }
        tol = ;
        printf("Case %d:\n", cas++);
        for(int i=; i<=mw; i++) {
            if(ans[i]) {
                printf("%d %d\n", i, ans[i]);
                tol++;
            }
        }
        if(tol <= )    printf("There is %d color left on the wall.\n", tol);
        else    printf("There are %d colors left on the wall.\n", tol);
    }
    return ;
}