2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework
Danang and Darto are classmates. They are given homework to create a permutation of N integers from 1 to N. Danang has completed the homework and created a permutation A of N integers. Darto wants to copy Danang's homework, but Danang asks Darto to change it up a bit so it does not look obvious that Darto copied.
The difference of two permutations of N integers A and B, denoted by diff(A,B), is the sum of the absolute difference of Ai and Bi for all i. In other words, diff(A,B)=ΣNi=1|Ai−Bi|. Darto would like to create a permutation of N integers that maximizes its difference with A. Formally, he wants to find a permutation of N integers Bmax such that diff(A,Bmax)≥diff(A,B′) for all permutation of N integers B′.
Darto needs your help! Since the teacher giving the homework is lenient, any permutation of N integers B is considered different with A if the difference of A and B is at least N. Therefore, you are allowed to return any permutation of N integers B such that diff(A,B)≥N.
Of course, you can still return Bmax if you want, since it can be proven that diff(A,Bmax)≥N for any permutation A and N>1. This also proves that there exists a solution for any permutation of N integers A. If there is more than one valid solution, you can output any of them.
Input
Input begins with a line containing an integer: N (2≤N≤100000) representing the size of Danang's permutation. The next line contains N integers: Ai (1≤Ai≤N) representing Danang's permutation. It is guaranteed that all elements in A are distinct.
Output
Output in a line N integers (each separated by a single space) representing the permutation of N integers B such that diff(A,B)≥N. As a reminder, all elements in the permutation must be between 1 to N and distinct.
Examples
input
4
1 3 2 4
output
4 2 3 1
input
2
2 1
output
1 2
Note
Explanation for the sample input/output #1
With A=[1,3,2,4] and B=[4,2,3,1], diff(A,B)=|1−4|+|3−2|+|2−3|+|4−1|=3+1+1+3=8. Since 8≥4, [4,2,3,1] is one of the valid output for this sample.
解题思路j:题目要求的是将数组元素重新排列,使得对应位置上的元素相减和的绝对值最大,即保证最大程度每一位上的元素都不同,将第一位对应最后一位,第二位对应倒数第二位,...。
AC代码:
#include <iostream>
using namespace std;
int main()
{
int n,a;
while(cin>>n)
{
for(int i=;i<=n;i++)
{
cin>>a;
cout<<n-a+<<" ";
}
cout<<endl;
}
return ;
}
2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework的更多相关文章
- 2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework (思维)
Danang and Darto are classmates. They are given homework to create a permutation of N integers from ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest (Online Mirror, ICPC Rules, Teams Preferred)
2019-2020 ICPC, Asia Jakarta Regional Contest (Online Mirror, ICPC Rules, Teams Preferred) easy: ACE ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest
目录 Contest Info Solutions A. Copying Homework C. Even Path E. Songwriter G. Performance Review H. Tw ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest H. Twin Buildings
As you might already know, space has always been a problem in ICPC Jakarta. To cope with this, ICPC ...
- 2018 ICPC Asia Jakarta Regional Contest
题目传送门 题号 A B C D E F G H I J K L 状态 Ο . . Ο . . Ø Ø Ø Ø . Ο Ο:当场 Ø:已补 . : 待补 A. Edit Distance Thin ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest C. Even Path
Pathfinding is a task of finding a route between two points. It often appears in many problems. For ...
- 模拟赛小结:2019-2020 ICPC, Asia Jakarta Regional Contest
比赛链接:传送门 离金最近的一次?,lh大佬carry场. Problem A. Copying Homework 00:17(+) Solved by Dancepted 签到,读题有点慢了.而且配 ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest C. Even Path(思维)
Pathfinding is a task of finding a route between two points. It often appears in many problems. For ...
- Asia Jakarta Regional Contest 2019 I - Mission Possible
cf的地址 因为校强, "咕咕十段"队获得了EC-final的参赛资格 因为我弱, "咕咕十段"队现在银面很大 于是咕咕十段决定进行训练. 周末vp了一场, 这 ...
随机推荐
- C#主菜单动态添加子菜单并设置触发事件
我所使用的是devxepress中的主菜单栏时barsubitem控件,想的是在其能够动态添加子菜单栏并能点击触发事件: /// <summary> /// 创建主按钮的子按钮 /// & ...
- Git 命令行解决冲突
git add filename 将本地工作区文件加入缓存区 git commit filename -m '提交文件注释' git status 查看当前工作区状态 git fetch ori ...
- Python3-元祖
# Tuple(元组) # 元组(tuple)与列表类似,不同之处在于元组的元素不能修改.元组写在小括号(())里,元素之间用逗号隔开. # 元组中的元素类型也可以不相同 tuple = ('abcd ...
- [2019牛客多校第二场][G. Polygons]
题目链接:https://ac.nowcoder.com/acm/contest/882/G 题目大意:有\(n\)条直线将平面分成若干个区域,要求处理\(m\)次询问:求第\(q\)大的区域面积.保 ...
- BZOJ 2013 : [Ceoi2010]A huge tower / Luogu SP6950 CTOI10D3 - A HUGE TOWER
传送门 菜鸡.jpg CODE #include <bits/stdc++.h> using namespace std; const int MAXN = 620005; int n, ...
- MFC 画字体DrawText()或TextOut(),CFont字体样式类
新建单个文档的MFC应用程序,类视图——View项的属性——消息,WM_PAINT,创建OnPaint()函数 void CMFCApplication27View::OnPaint() { CPai ...
- MSMQ介绍
最近的项目中用到了MSMQ,简单的使用到了它,现总结下.有些是网上的资料有些是自己的笔记. MSMQ理解 Message Queue(微软消息队列)是在多个不同的应用之间实现相互通信的一种异步传输模式 ...
- python控制窗口移动(轨迹为圆)
需先打开一个无标题记事本, import win32con import win32gui import time import math notepad = win32gui.FindWindow( ...
- codeforces#1108E2. Array and Segments (线段树+扫描线)
题目链接: http://codeforces.com/contest/1108/problem/E2 题意: 给出$n$个数和$m$个操作 每个操作是下标为$l$到$r$的数减一 选出某些操作,使$ ...
- IDEA Method definition shorthands are not supported by current JavaScript version
sentinel-dashboard前端用到了AngularJS v1.4.8,在IDEA里修改js,触发js验证时有一些js文件会出现红色波浪线. 在代码行里鼠标一上去提示信息:Method def ...