2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework
Danang and Darto are classmates. They are given homework to create a permutation of N integers from 1 to N. Danang has completed the homework and created a permutation A of N integers. Darto wants to copy Danang's homework, but Danang asks Darto to change it up a bit so it does not look obvious that Darto copied.
The difference of two permutations of N integers A and B, denoted by diff(A,B), is the sum of the absolute difference of Ai and Bi for all i. In other words, diff(A,B)=ΣNi=1|Ai−Bi|. Darto would like to create a permutation of N integers that maximizes its difference with A. Formally, he wants to find a permutation of N integers Bmax such that diff(A,Bmax)≥diff(A,B′) for all permutation of N integers B′.
Darto needs your help! Since the teacher giving the homework is lenient, any permutation of N integers B is considered different with A if the difference of A and B is at least N. Therefore, you are allowed to return any permutation of N integers B such that diff(A,B)≥N.
Of course, you can still return Bmax if you want, since it can be proven that diff(A,Bmax)≥N for any permutation A and N>1. This also proves that there exists a solution for any permutation of N integers A. If there is more than one valid solution, you can output any of them.
Input
Input begins with a line containing an integer: N (2≤N≤100000) representing the size of Danang's permutation. The next line contains N integers: Ai (1≤Ai≤N) representing Danang's permutation. It is guaranteed that all elements in A are distinct.
Output
Output in a line N integers (each separated by a single space) representing the permutation of N integers B such that diff(A,B)≥N. As a reminder, all elements in the permutation must be between 1 to N and distinct.
Examples
input
4
1 3 2 4
output
4 2 3 1
input
2
2 1
output
1 2
Note
Explanation for the sample input/output #1
With A=[1,3,2,4] and B=[4,2,3,1], diff(A,B)=|1−4|+|3−2|+|2−3|+|4−1|=3+1+1+3=8. Since 8≥4, [4,2,3,1] is one of the valid output for this sample.
解题思路j:题目要求的是将数组元素重新排列,使得对应位置上的元素相减和的绝对值最大,即保证最大程度每一位上的元素都不同,将第一位对应最后一位,第二位对应倒数第二位,...。
AC代码:
#include <iostream>
using namespace std;
int main()
{
int n,a;
while(cin>>n)
{
for(int i=;i<=n;i++)
{
cin>>a;
cout<<n-a+<<" ";
}
cout<<endl;
}
return ;
}
2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework的更多相关文章
- 2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework (思维)
Danang and Darto are classmates. They are given homework to create a permutation of N integers from ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest (Online Mirror, ICPC Rules, Teams Preferred)
2019-2020 ICPC, Asia Jakarta Regional Contest (Online Mirror, ICPC Rules, Teams Preferred) easy: ACE ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest
目录 Contest Info Solutions A. Copying Homework C. Even Path E. Songwriter G. Performance Review H. Tw ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest H. Twin Buildings
As you might already know, space has always been a problem in ICPC Jakarta. To cope with this, ICPC ...
- 2018 ICPC Asia Jakarta Regional Contest
题目传送门 题号 A B C D E F G H I J K L 状态 Ο . . Ο . . Ø Ø Ø Ø . Ο Ο:当场 Ø:已补 . : 待补 A. Edit Distance Thin ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest C. Even Path
Pathfinding is a task of finding a route between two points. It often appears in many problems. For ...
- 模拟赛小结:2019-2020 ICPC, Asia Jakarta Regional Contest
比赛链接:传送门 离金最近的一次?,lh大佬carry场. Problem A. Copying Homework 00:17(+) Solved by Dancepted 签到,读题有点慢了.而且配 ...
- 2019-2020 ICPC, Asia Jakarta Regional Contest C. Even Path(思维)
Pathfinding is a task of finding a route between two points. It often appears in many problems. For ...
- Asia Jakarta Regional Contest 2019 I - Mission Possible
cf的地址 因为校强, "咕咕十段"队获得了EC-final的参赛资格 因为我弱, "咕咕十段"队现在银面很大 于是咕咕十段决定进行训练. 周末vp了一场, 这 ...
随机推荐
- 在laravel5.8中集成swoole组件----初步测试
铺垫 前提是先安装swoole组件,我采用从pecl-----php扩展组件网下载swoole扩展包,然后切入到解压缩的扩展包中运行phpize命令, phpize是一种编译命令,可以在安装文件中生成 ...
- Java中的集合Collection、Iterator和Foreach用法(一)
1.Java集合概述 在编程中,常常需要集中存放多个数据.当然我们可以使用数组来保存多个对象.但数组长度不可变化,一旦在初始化时指定了数组长度,则这个数组长度是不可变的,如果需要保存个数变化的数据,数 ...
- .net core Areas区域
//使用MVC app.UseMvc(routes => { routes.MapRoute( name: "areas", template: "{area:ex ...
- Xilinx的IP核接口命名说明
s_axis中的s表示:slave(从); m_axis中的m表示:master(主). axis表示AXI(一种总线协议) Signal.
- Comet OJ - Contest #11 B 背包dp
Code: #include <bits/stdc++.h> #define N 1005 #define M 2000 #define setIO(s) freopen(s". ...
- 小米oj 有多少个等差数列(动态规划)
有多少个等差数列? 序号:#20难度:困难时间限制:500ms内存限制:10M 描述 等差数列是常见数列的一种,如果一个数列从第二项起,每一项与它的前一项的差等于同一个常数,这个数列就叫做等差数列, ...
- php-m 与 phpinfo 不一致的解决办法
1.查看PHP当前加载的php.ini文件地址,在控制台输入以下命令: 1 php -i | grep php.ini 2.控制台返回的信息 1 2 Configuration File (php.i ...
- JavaWeb_(SSH)三大框架整合struts+hibernate+spring_Demo
三大框架整合 一.SSH导包 二.书写Spring 三.书写Struts 四.整合Spring与Struts 五.书写(与整合)Hibernate.引入c3p0连接池并使用hibernate模板 六. ...
- ARTS打卡计划第十二周
Algorithms: https://leetcode-cn.com/problems/balanced-binary-tree/ 平衡二叉树. Review: “What I Learned i ...
- Java 标准 IO 流编程一览笔录( 下 )
8.回推流:PushbackInputStream与PushbackReader PushbackInputStream/PushbackReader 用于解析InputStream/Reader内的 ...