mysql学习第一天select

emp、dept表

DROP TABLE IF EXISTS `dept`;

CREATE TABLE `dept` (

`DEPTNO` int(2) NOT NULL,

`DNAME` varchar(14) DEFAULT NULL,

`LOC` varchar(13) DEFAULT NULL,

PRIMARY KEY (`DEPTNO`)

) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------

-- Records of dept

-- ----------------------------

INSERT INTO `dept` VALUES ('10', 'ACCOUNTING', 'NEW YORK');

INSERT INTO `dept` VALUES ('20', 'RESEARCH', 'DALLAS');

INSERT INTO `dept` VALUES ('30', 'SALES', 'CHICAGO');

INSERT INTO `dept` VALUES ('40', 'OPERATIONS', 'BOSTON');

-- ----------------------------

-- Table structure for `emp`

-- ----------------------------

DROP TABLE IF EXISTS `emp`;

CREATE TABLE `emp` (

`EMPNO` int(4) NOT NULL,

`ENAME` varchar(10) DEFAULT NULL,

`JOB` varchar(9) DEFAULT NULL,

`MGR` int(4) DEFAULT NULL,

`HIREDATE` date DEFAULT NULL,

`SAL` int(7) DEFAULT NULL,

`COMM` int(7) DEFAULT NULL,

`DEPTNO` int(2) DEFAULT NULL,

PRIMARY KEY (`EMPNO`),

KEY `FK_DEPTNO` (`DEPTNO`),

CONSTRAINT `FK_DEPTNO` FOREIGN KEY (`DEPTNO`) REFERENCES `dept` (`DEPTNO`)

) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------

-- Records of emp

-- ----------------------------

INSERT INTO `emp` VALUES ('7369', 'SMITH', 'CLERK', '7902', '1980-12-17', '800', null, '20');

INSERT INTO `emp` VALUES ('7499', 'ALLEN', 'SALESMAN', '7698', '1981-02-20', '1600', '300', '30');

INSERT INTO `emp` VALUES ('7521', 'WARD', 'SALESMAN', '7698', '1981-02-22', '1250', '500', '30');

INSERT INTO `emp` VALUES ('7566', 'JONES', 'MANAGER', '7839', '1981-04-02', '2975', null, '20');

INSERT INTO `emp` VALUES ('7654', 'MARTIN', 'SALESMAN', '7698', '1981-09-28', '1250', '1400', '30');

INSERT INTO `emp` VALUES ('7698', 'BLAKE', 'MANAGER', '7839', '1981-05-01', '2850', null, '30');

INSERT INTO `emp` VALUES ('7782', 'CLARK', 'MANAGER', '7839', '1981-06-09', '2450', null, '10');

INSERT INTO `emp` VALUES ('7788', 'SCOTT', 'ANALYST', '7566', '1987-04-19', '3000', null, '20');

INSERT INTO `emp` VALUES ('7839', 'KING', 'PRESIDENT', null, '1981-11-17', '5000', null, '10');

INSERT INTO `emp` VALUES ('7844', 'TURNER', 'SALESMAN',

'7698', '1981-09-08', '1500', '0', '30');

INSERT INTO `emp` VALUES ('7876', 'ADAMS', 'CLERK', '7788', '1987-05-23', '1100', null, '20');

INSERT INTO `emp` VALUES ('7900', 'JAMES', 'CLERK', '7698', '1981-12-03', '950', null, '30');

INSERT INTO `emp` VALUES ('7902', 'FORD', 'ANALYST', '7566', '1981-12-03', '3000', null, '20');

INSERT INTO `emp` VALUES ('7934', 'MILLER', 'CLERK', '7782', '1982-01-23', '1300', null, '10');

-- 第一章
-- 查询所有员工编号
SELECT EMPNO
FROM emp;
-- 第二章
-- SELECT empno,ename,deptno
-- FROM emp;

-- SELECT *
-- FROM emp;

-- 练习1
SELECT empno,ename,job,sal,deptno
FROM emp;

-- 2.查询员工工资增加100元后的情况
SELECT sal + 100,sal -100,sal*2,sal/3
FROM emp;

-- 3.查询员工一年工资再加上100的结果
SELECT sal*2+100
FROM emp;

-- 4.查询员工每个月提高100元后的年工资收入
SELECT 12*(sal+100)
FROM emp;

-- 练习2
-- 1.员工转正后，月薪上调20%，请查询出所有员工转正后的月薪。
SELECT sal*1.2
FROM emp;
-- 2.员工试用6个月，转正后的月薪上调20%，
-- 请查询出所有员工工作一年的年薪所得（不考虑奖金部分，年薪的使用期为6个月的月薪+转正后6个月的月薪）
SELECT sal*6+SAL*6*1.2
FROM emp;

-- 5.求员工月收入
SELECT sal + COALESCE(comm,0)总收入
FROM emp;

-- 练习3
-- 员工试用期6个月，转正后月薪上调20%，请查询出所有员工工作第一年的所有收入（需考虑奖金部分），要求显示列标题为员工姓名、工资收入、奖金收入、总收入
SELECT ename 员工姓名,sal*6+sal*6*1.2 工资收入,COALESCE(comm,0)*6 奖金收入,sal*6+sal*1.2*6+COALESCE(comm,0)*12
FROM emp;
-- 6.从emp表中查询有哪些部门
SELECT DISTINCT deptno
FROM emp;

-- 练习4
-- 1.查询员工表中一共有哪几种岗位类型
SELECT DISTINCT job
FROM emp;

-- 练习5
-- 查看表结构

DESC emp;

-- 查询在20部门工作的员工信息
SELECT *
FROM emp
where deptno = 20;

-- 8.查询职位是CLERK的员工信息
SELECT *
FROM emp
where job = 'CLERK';

-- 9、查询入职日期在1980年1月1日以后入职的员工信息
SELECT *
FROM emp
where HIREDATE > '1980-01-01';

-- 练习6
-- 查询职位为SALESMAN的员工编号、职位、入职日期
SELECT EMPNO,JOB,HIREDATE
FROM emp
WHERE JOB = 'SALESMAN';
-- 2、查询1985年12月31日之前入职的员工姓名及入职日期
SELECT ename,hiredate
FROM emp
where hiredate <= '1985-12-31';
-- 3、查询部门编号不在10部门的员工姓名、部门编号
SELECT ENAME,DEPTNO
FROM emp
WHERE DEPTNO <> 10;

-- 10、查询工资在1000到1500之间的员工信息
SELECT *
FROM emp
where SAL BETWEEN 1000 AND 1500;

-- 查询7902、7566、7788所管理的员工信息
SELECT *
FROM emp
WHERE MGR in(7902,7566,7788);

-- 练习7
-- 1、查询入职日期在82年至85年的员工姓名、员工日期
SELECT ENAME,HIREDATE
FROM emp
WHERE HIREDATE BETWEEN '1982-01-01' AND '1985-12-31';
-- 2、查询月薪在3000到5000的员工姓名、月薪
SELECT ENAME,SAL
FROM emp
WHERE SAL BETWEEN 3000 AND 5000;

-- 3、查询部门编号为10或者20的员工姓名、部门编号
SELECT ENAME,DEPTNO
FROM emp
WHERE DEPTNO in(10,20);
-- 4、查询经理编号为7902、7566、7788的员工姓名、经理编号
SELECT ENAME,MGR
FROM emp
WHERE MGR IN(7902,7566,7788);

-- 12、查询姓名中以S开头的员工信息
SELECT *
FROM emp
where ENAME LIKE 'S%';
-- 13、查询姓名中第二个字母是L的员工信息
SELECT *
FROM emp
WHERE ENAME LIKE '_L%';

-- 查询姓名中包含S的员工信息
SELECT *
FROM emp
WHERE ENAME LIKE '%S%';

-- 15、查询职位以MAN_开头的雇员信息
SELECT *
FROM emp
WHERE JOB LIKE 'MAN@_%' ESCAPE '@';