CF1101E Polycarp's New Job

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<string>
#include<cmath>
#include<map>
#include<set>
#include<vector>
#include<queue>
#include<bitset>
#include<ctime>
#include<deque>
#include<stack>
#include<functional>
#include<sstream>
//#include<cctype>
//#pragma GCC optimize(2)
using namespace std;
#define maxn 100005
#define inf 0x7fffffff
//#define INF 1e18
#define rdint(x) scanf("%d",&x)
#define rdllt(x) scanf("%lld",&x)
#define rdult(x) scanf("%lu",&x)
#define rdlf(x) scanf("%lf",&x)
#define rdstr(x) scanf("%s",x)
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int U;
#define ms(x) memset((x),0,sizeof(x))
const long long int mod = 1e9 + 7;
#define Mod 1000000000
#define sq(x) (x)*(x)
#define eps 1e-4
typedef pair<int, int> pii;
#define pi acos(-1.0)
//const int N = 1005;
#define REP(i,n) for(int i=0;i<(n);i++)
typedef pair<int, int> pii;
inline ll rd() {
ll x = 0;
char c = getchar();
bool f = false;
while (!isdigit(c)) {
if (c == '-') f = true;
c = getchar();
}
while (isdigit(c)) {
x = (x << 1) + (x << 3) + (c ^ 48);
c = getchar();
}
return f ? -x : x;
} ll gcd(ll a, ll b) {
return b == 0 ? a : gcd(b, a%b);
}
int sqr(int x) { return x * x; } /*ll ans;
ll exgcd(ll a, ll b, ll &x, ll &y) {
if (!b) {
x = 1; y = 0; return a;
}
ans = exgcd(b, a%b, x, y);
ll t = x; x = y; y = t - a / b * y;
return ans;
}
*/ priority_queue<int>q;
priority_queue<int>q2; int main() {
//ios::sync_with_stdio(0);
int n;
rdint(n);
for (int i = 1; i <= n; i++) {
char op; cin >> op;
if (op == '+') {
int x, y; rdint(x); rdint(y);
if (x > y)swap(x, y);
q.push(x); q2.push(y);
}
else {
int u, w; rdint(u); rdint(w);
bool fg = false;
if (q.top() <= u && q2.top() <= w)fg = true;
if (q.top() <= w && q2.top() <= u)fg = true;
if (fg) {
cout << "YES" << endl;
}
else cout << "NO" << endl;
}
}
return 0;
}
CF1101E Polycarp's New Job的更多相关文章
- cf723c Polycarp at the Radio
Polycarp is a music editor at the radio station. He received a playlist for tomorrow, that can be re ...
- codeforces 723C : Polycarp at the Radio
Description Polycarp is a music editor at the radio station. He received a playlist for tomorrow, th ...
- Codeforces 723C. Polycarp at the Radio 模拟
C. Polycarp at the Radio time limit per test: 2 seconds memory limit per test: 256 megabytes input: ...
- Codeforces Round #375 (Div. 2) C. Polycarp at the Radio 贪心
C. Polycarp at the Radio time limit per test 2 seconds memory limit per test 256 megabytes input sta ...
- Codeforces Round #346 (Div. 2) F. Polycarp and Hay 并查集
题目链接: 题目 F. Polycarp and Hay time limit per test: 4 seconds memory limit per test: 512 megabytes inp ...
- Polycarp's problems
Polycarp's problems time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- Codeforce B. Polycarp and Letters
B. Polycarp and Letters time limit per test 2 seconds memory limit per test 256 megabytes input stan ...
- [Codeforces 864B]Polycarp and Letters
Description Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string s con ...
- 贪心 C - Polycarp's New Job
Polycarp has recently got himself a new job. He now earns so much that his old wallet can't even sto ...
随机推荐
- leetcode559
class Solution { public: int maxDepth(Node* root) { ; if (root != NULL) { queue<Node> Q; Q.pus ...
- Linux reboot后数据库无法自动启动
需将以下由N改为Y orcl:/data/oracle_db/product/13.2.0/db_1:Y Last login: Thu Aug 27 16:36:19 2015 from 10.10 ...
- windows下单机版的伪分布式solrCloud环境搭建Tomcat+solr+zookeeper
原文出自:http://sbp810050504.blog.51cto.com/2799422/1408322 按照该方法,伪分布式solr部署成功 ...
- 详解CSS display:inline-block的应用(转)
详解CSS display:inline-block的应用 阅读目录 基础知识 inline-block的问题 inline-block的应用 总结 本文详细描述了display:inline-b ...
- mongodb 降序
降序排序 db.mycol.find({},{,_id:}).sort({})// 1用于升序排列,而-1用于降序. 示例代码: var user = await Kitten.find({ type ...
- 2018 - Start Up
转眼2017已经过去,从大四下学期出来实习,到现在工作一年多了,很遗憾没有经营好自己博客园&CSDN. 献上一篇鼓励工程师写blog的博客:https://kb.cnblogs.com/pag ...
- Python 网络爬虫 005 (编程) 如何编写一个可以 下载(或叫:爬取)一个网页 的网络爬虫
如何编写一个可以 下载(或叫:爬取)一个网页 的网络爬虫 使用的系统:Windows 10 64位 Python 语言版本:Python 2.7.10 V 使用的编程 Python 的集成开发环境:P ...
- Java-马士兵设计模式学习笔记-迭代器模式-模仿Collectin ArrayList LinckedList
Java Iterator模式 Java Iterator模式, 模仿Collectin ArrayList LinckedList 一.有如下几个类 1.接口Collection.java 2.接口 ...
- Android studio中ShredPreferences 的简单使用
ShredPreferences是一个轻量级的数据存储方式,只能存取字符串了整型数据这一类的数据,如果要存储复杂的数据这个存储方式就不再适用 首先是要新建一个ShredPreferences的对象 p ...
- 1027C Minimum Value Rectangle
传送门 题目大意 有n个木棍,让你选4根使得组成的矩形的周长的平方除以面积最小. 分析 这个题看起来就是一个需要证明的贪心,下面我们来证明一下: 所以我们只需要枚举一边所有的a的可能值,然后b就是比a ...