UVA1610 PartyGame 聚会游戏（细节题）

给出一组字符串D，要找一个字符串S使得D中一半小于等于S，另外一半大于S。输入保证一定有解。长度要尽量短，在此基础上字典序尽量小。

分类谈论，细节挺多的，比如'Z'。

其实直接暴就过了，没分类辣么麻烦。

#include<bits/stdc++.h>
using namespace std;

vector<string> vec;

int main()
{
   // freopen("in.txt","r",stdin);
    int n;
    char s[];
    while(scanf("%d",&n),n){
        vec.resize(n);
        for(int i = ; i < n; i++){
            scanf("%s",s);
            vec[i] = s;
        }
        sort(vec.begin(),vec.end());
        int mid = n>>;
        string &a = vec[mid-] ,&b = vec[mid];
        int i;
        int len1 = a.size()-, len2 = b.size()-;
        if(len1 < len2){
            for(i = ; i < len1; i++){
                if(b[i] != a[i]) { s[i] = a[i]+; s[i+] = '\0'; break; }
                s[i] = a[i];
            }
            if(i == len1) {
                s[i] = a[i]; s[i+] = '\0';
            }
        }else if(len1>len2){
            for(i = ; i < len2; i++){
                if(b[i] != a[i]) { s[i] = a[i]+; s[i+] = '\0'; break; }
                s[i] = a[i];
            }
            if(i == len2) {
                if(b[i] != a[i]+) { s[i] = a[i]+; s[i+] = '\0'; }
                else {
                    s[i] = a[i];
                    for(i++; i < len1; i++){
                        if(a[i] != 'Z'){
                            s[i] = a[i] + ; s[i+] = '\0'; break;
                        }
                        s[i] = a[i];
                    }
                    if(i == len1) { s[i] = a[i]; s[i+] = '\0'; }
                }
            }
        }else {
            for(i = ; i < len2; i++) {
                if(b[i] != a[i]) { s[i] = a[i]+; s[i+] = '\0'; break; }
                s[i] = a[i];
            }
            if(i == len2) { s[i] = a[i]; s[i+] = '\0';  }
        }
        printf("%s\n",s);
    }
    return ;
}