poj Fishnet
http://poj.org/problem?id=1408
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define maxn 1000
using namespace std; const double eps=1e-;
const double pi=acos(-1.0); int cmp(double x)
{
if(fabs(x)<eps) return ;
if(x>) return ;
return -;
} struct point
{
double x,y;
point(){}
point(double a,double b):x(a),y(b) {}
friend point operator -(const point &a,const point &b){
return point(a.x-b.x,a.y-b.y);
}
friend point operator * (const point &a,const double b)
{
return point (a.x*b,a.y*b);
}
friend point operator / (const point &a,const double b)
{
return point(a.x/b,a.y/b);
}
};
struct line
{
point a,b;
line(){}
line(point x,point y):a(x),b(y){}
};
inline double sqr(double x)
{
return x*x;
}
double det(point a,point b)
{
return a.x*b.y-a.y*b.x;
}
double dot(point a,point b)
{
return a.x*b.x+a.y*b.y;
}
double dist(point a,point b)
{
return sqrt(sqr(a.x-b.x)+sqr(a.y-b.y));
}
double area(point a[])
{
double sum=;
a[]=a[];
for(int i=; i<; i++)
{
sum+=det(a[i+],a[i]);
}
return sum/;
} bool parallel (line a,line b)
{
return !cmp(det(a.a-a.b,b.a-b.b));
} bool line_make_point(line a,line b,point &res)
{
if(parallel(a,b)) return false;
double s1=det(a.a-b.a,b.b-b.a);
double s2=det(a.b-b.a,b.b-b.a);
res=(a.b*s1-a.a*s2)/(s1-s2);
return true;
} int main()
{
int n;
double a[maxn],b[maxn],c[maxn],d[maxn];
point m[][];
line l[][];
while(scanf("%d",&n)&&n){
double max1=eps;
for(int i=; i<=n; i++){
scanf("%lf",&a[i]);
m[][i].x=a[i];
m[][i].y=; }
m[][].x=;
m[][].y=;
m[][n+].x=;
m[][n+].y=;
for(int j=; j<=n; j++){
scanf("%lf",&b[j]);
m[n+][j].x=b[j];
m[n+][j].y=;
}
m[n+][].x=;
m[n+][].y=;
m[n+][n+].x=;
m[n+][n+].y=;
for(int k=; k<=n; k++){
scanf("%lf",&c[k]);
m[k][].y=c[k];
m[k][].x=;
}
for(int t= ; t<=n; t++){
scanf("%lf",&d[t]);
m[t][n+].x=;
m[t][n+].y=d[t];
}
for(int i=; i<=n; i++)
{
l[i][].a=m[][i];
l[i][].b=m[n+][i];
}
for(int i=; i<=n; i++)
{
l[][i].a=m[i][];
l[][i].b=m[i][n+];
}
for(int i=; i<=n; i++)
{
for(int j=; j<=n; j++)
{
point res;
line_make_point(l[][i],l[j][],res);
m[i][j]=res;
}
}
for(int i=; i<=n+; i++)
{
for(int j=; j<=n+; j++)
{
point s[];
s[]=m[i-][j-];
s[]=m[i-][j];
s[]=m[i][j];
s[]=m[i][j-];
max1=max(max1,area(s));
//printf("%.6lf ",area(s));
}
//printf("\n");
}
printf("%.6lf\n",max1);
}
return ;
}
poj Fishnet的更多相关文章
- POJ 1408 Fishnet【枚举+线段相交+叉积求面积】
题目: http://poj.org/problem?id=1408 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22013#probl ...
- Fishnet(暴力POJ 1408)
Fishnet Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 1911 Accepted: 1227 Descripti ...
- POJ 1408:Fishnet
Fishnet Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 1921 Accepted: 1234 Descripti ...
- POJ 3370. Halloween treats 抽屉原理 / 鸽巢原理
Halloween treats Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 7644 Accepted: 2798 ...
- POJ 2356. Find a multiple 抽屉原理 / 鸽巢原理
Find a multiple Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7192 Accepted: 3138 ...
- POJ 2965. The Pilots Brothers' refrigerator 枚举or爆搜or分治
The Pilots Brothers' refrigerator Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 22286 ...
- POJ 1753. Flip Game 枚举or爆搜+位压缩,或者高斯消元法
Flip Game Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 37427 Accepted: 16288 Descr ...
- POJ 3254. Corn Fields 状态压缩DP (入门级)
Corn Fields Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 9806 Accepted: 5185 Descr ...
- POJ 2739. Sum of Consecutive Prime Numbers
Sum of Consecutive Prime Numbers Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20050 ...
随机推荐
- SpringBoot 配置文件 application.properties
转:http://www.qiyadeng.com/post/spring-boot-application-properties #########COMMON SPRING BOOT PROPER ...
- python字符串连接的三种方法及其效率、适用场景详解
python字符串连接的方法,一般有以下三种:方法1:直接通过加号(+)操作符连接website=& 39;python& 39;+& 39;tab& 39;+& ...
- HDU 3018 Ant Trip
九野的博客,转载请注明出处: http://blog.csdn.net/acmmmm/article/details/10858065 题意:n个点m条边的无向图,求用几笔可以把所有边画完(画过的边 ...
- [PWA] 14. Loop cursor
import idb from 'idb'; var dbPromise = idb.open('test-db', 4, function (upgradeDb) { switch (upgrade ...
- Eclipse混淆文件导入Android Studio Gradle编译报input jar file is specified twice
Eclipse项目中的混淆配置文件 复制到AS中 在混淆的过程中提示如下错误 Error:Execution failed for task ':app:proguardDemoRelease ...
- System.Web.HttpContext.Current.Session获取值出错
在自定义类库CS文件里使用System.Web.HttpContext.Current.Session获取Session时提示错误:未将对象引用设置到对象的实例. 一般情况下通过这种方式获取Sessi ...
- (转)PHP函数spl_autoload_register()用法和__autoload()介绍
转--http://www.jb51.net/article/29624.htm 又是框架冲突导致__autoload()失效,用spl_autoload_register()重构一下,问题解决 ...
- java中的IO一
一.IO操作的目标 IO的流向 二.IO的分类方法 1.第一种分法:输入流.输出流 2.第二种分法:字节流.字符流 3.第三种分法:节点流.处理流 三.IO当中的核心类 核心类中的核心方法 Input ...
- Oracle解析 xml 记录一下(未完待续)
Oracle解析 xml 记录一下. SQL> desc xmlparser; PROCEDURE FREEPARSER Argument Name Type ...
- Swift - 31 - 常量参数, 变量参数和inout参数
//: Playground - noun: a place where people can play import UIKit // swift中默认情况下, 传入的参数是不可以修改的, 也就是l ...