TEX Quotes(字符串,水)
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 9674 | Accepted: 5073 |
Description
If the source contained "To be or not to be," quoth the bard, "that is the question." then the typeset document produced by TEX would not contain the desired form: "To be or not to be," quoth the bard, "that is the question." In order to produce the desired form, the source file must contain the sequence: ``To be or not to be,'' quoth the bard, ``that is the question.'' You are to write a program which converts text containing double-quote (") characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote (") characters should be replaced appropriately by either `` if the " opens a quotation and by '' if the " closes a quotation. Notice that the question of nested quotations does not arise: The first " must be replaced by ``, the next by '', the next by ``, the next by '', the next by ``, the next by '', and so on.
Input
Output
- the first " in each pair is replaced by two ` characters: `` and
- the second " in each pair is replaced by two ' characters: ''.
Sample Input
"To be or not to be," quoth the Bard, "that
is the question".
The programming contestant replied: "I must disagree.
To `C' or not to `C', that is The Question!"
Sample Output
``To be or not to be,'' quoth the Bard, ``that
is the question''.
The programming contestant replied: ``I must disagree.
To `C' or not to `C', that is The Question!''
题解:要输入一行再输出一行,这样比较好,另外"竟然是两个''无语,错了半天。。。。
代码:
#include<iostream>
#include<cstring>
#include<cstdio>
#include<cmath>
#include<vector>
#include<map>
#include<algorithm>
using namespace std;
#define mem(x,y) memset(x,y,sizeof(x))
#define SI(x) scanf("%d",&x)
#define SL(x) scanf("%lld",&x)
#define PI(x) printf("%d",x)
#define PL(x) printf("%lld",x)
#define P_ printf(" ")
#define T_T while(T--)
typedef long long LL;
const int INF=0x3f3f3f3f;
char s[1000010];
int main(){
int cnt=0;
while(gets(s)){
int len=strlen(s);
for(int k=0;k<len;k++){
if(s[k]=='"'){
cnt++;
if(cnt&1)printf("``");
else printf("''");
}
else printf("%c",s[k]);
}
printf("\n");
}
return 0;
}
TEX Quotes(字符串,水)的更多相关文章
- UVa 272 Tex Quotes --- 水题
题目大意:在TeX中,左引号是 ``,右引号是 ''.输入一篇包含双引号的文章,你的任务是把他转成TeX的格式 解题思路:水题,定义一个变量标记是左引号还是右引号即可 /* UVa 272 Tex Q ...
- POJ 1488 Tex Quotes --- 水题
POJ 1488 题目大意:给定一篇文章,将它的左引号转成 ``(1的左边),右引号转成 ''(两个 ' ) 解题思路:水题,设置一个bool变量标记是左引号还是右引号即可 /* POJ 1488 T ...
- Uva272.TEX Quotes
题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem& ...
- UVA 272 TEX Quotes
TEX Quotes 题意: 变引号. 题解: 要想进步,真的要看一本好书,紫书P45 代码: #include<stdio.h> int main() { int c,q=1; whil ...
- 【UVA272】TEX Quotes
A - TEX Quotes Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Submitcid=80 ...
- 1222: FJ的字符串 [水题]
1222: FJ的字符串 [水题] 时间限制: 1 Sec 内存限制: 128 MB 提交: 92 解决: 20 统计 题目描述 FJ在沙盘上写了这样一些字符串: A1 = “A” A2 = ...
- 1001 字符串“水”题(二进制,map,哈希)
1001: 字符串“水”题 时间限制: 1 Sec 内存限制: 128 MB提交: 210 解决: 39[提交][状态][讨论版] 题目描述 给出一个长度为 n 的字符串(1<=n<= ...
- poj--1488--TEX Quotes(水题)
TEX Quotes Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 9672 Accepted: 5071 Descri ...
- UVA 272 TEX Quotes【字符串】
https://vjudge.net/problem/UVA-272 [分析]:标记一下. [代码]: #include <bits/stdc++.h> using namespace s ...
随机推荐
- 关于Python网络爬虫实战笔记①
python网络爬虫项目实战笔记①如何下载韩寒的博客文章 python网络爬虫项目实战笔记①如何下载韩寒的博客文章 1. 打开韩寒博客列表页面 http://blog.sina.com.cn/s/ar ...
- c++读取文件内容并保存到二维数组
每行数据最后需要Tab处理 #include <iostream> #include <fstream> #include <string> using names ...
- POSIX扩展正则表达式函数
1.ereg()函数和eregi()函数 函数语法: bool ereg/eregi ( string pattern, string string [, array regs] ) 函数功能: 在字 ...
- HDU 5893 List wants to travel(树链剖分)
[题目链接]http://acm.hdu.edu.cn/showproblem.php?pid=5893 [题目大意] 给出一棵树,每条边上都有一个边权,现在有两个操作,操作一要求将x到y路径上所有边 ...
- DOM ISO - get current element's XPATH
DOM ISO - get current element's XPATH DOM ISO - get current element's XPATH
- iOS 按钮倒计时功能
iOS 按钮倒计时功能, 建议把按钮换成label,这样会避免读秒时闪烁 __block ; __block UIButton *verifybutton = _GetverificationBtn; ...
- 标准C函数库的使用方法
本篇介绍若干经常使用的标准C函数的使用方法,主要介绍stdio(标准输入输出).math(数字函数库).time(时间函数库).stdlib(标准函数库)string(标准字符串函数)等. 最后更新 ...
- linux下emacs安装
1.下载地址:http://ftp.gnu.org/pub/gnu/emacs/ 下载文件:emacs-24.2.tar.gz 步骤: 一.安装依赖文件: (先进入root:终端中输入 su -) ...
- Matlab中的取整-floor,ceil,fix,round
FLOOR Round towards minus infinity. FLOOR(X) rounds the elements of X to the nearest integers toward ...
- 浅谈JSP(二)
一.EL表达式 作用:从作用域(pageContext,request,session,application)中取值,并显示在页面中. 本质:用于替换输出脚本(<%= %>). 1.从作 ...