JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-009Polymorphic collections(@OneToMany(mappedBy = "user")、@ManyToOne、)
一、代码
1.
package org.jpwh.model.inheritance.associations.onetomany; import org.jpwh.model.Constants; import javax.persistence.*;
import javax.validation.constraints.NotNull; // Can not be @MappedSuperclass when it's a target class in associations!
@Entity
@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
public abstract class BillingDetails { @Id
@GeneratedValue(generator = Constants.ID_GENERATOR)
protected Long id; @ManyToOne(fetch = FetchType.LAZY)
protected User user; @NotNull
protected String owner; protected BillingDetails() {
} protected BillingDetails(String owner) {
this.owner = owner;
} public Long getId() {
return id;
} public String getOwner() {
return owner;
} public void setOwner(String owner) {
this.owner = owner;
} public User getUser() {
return user;
} public void setUser(User user) {
this.user = user;
} public void pay(int amount) {
// NOOP
} // ...
}
2.
package org.jpwh.model.inheritance.associations.onetomany; import javax.persistence.Entity;
import javax.validation.constraints.NotNull; @Entity
public class BankAccount extends BillingDetails { @NotNull
protected String account; @NotNull
protected String bankname; @NotNull
protected String swift; public BankAccount() {
super();
} public BankAccount(String owner, String account, String bankname, String swift) {
super(owner);
this.account = account;
this.bankname = bankname;
this.swift = swift;
} public String getAccount() {
return account;
} public void setAccount(String account) {
this.account = account;
} public String getBankname() {
return bankname;
} public void setBankname(String bankname) {
this.bankname = bankname;
} public String getSwift() {
return swift;
} public void setSwift(String swift) {
this.swift = swift;
}
}
3.
package org.jpwh.model.inheritance.associations.onetomany; import javax.persistence.Entity;
import javax.validation.constraints.NotNull; @Entity
public class CreditCard extends BillingDetails { @NotNull
protected String cardNumber; @NotNull
protected String expMonth; @NotNull
protected String expYear; public CreditCard() {
super();
} public CreditCard(String owner, String cardNumber, String expMonth, String expYear) {
super(owner);
this.cardNumber = cardNumber;
this.expMonth = expMonth;
this.expYear = expYear;
} public String getCardNumber() {
return cardNumber;
} public void setCardNumber(String cardNumber) {
this.cardNumber = cardNumber;
} public String getExpMonth() {
return expMonth;
} public void setExpMonth(String expMonth) {
this.expMonth = expMonth;
} public String getExpYear() {
return expYear;
} public void setExpYear(String expYear) {
this.expYear = expYear;
} }
4.
package org.jpwh.model.inheritance.associations.onetomany; import org.jpwh.model.Constants; import javax.persistence.*;
import javax.validation.constraints.NotNull;
import java.util.HashSet;
import java.util.Set; @Entity
@Table(name = "USERS")
public class User { @Id
@GeneratedValue(generator = Constants.ID_GENERATOR)
protected Long id; @NotNull
protected String username; @OneToMany(mappedBy = "user")
protected Set<BillingDetails> billingDetails = new HashSet<>(); public User() {
} public User(String username) {
this.username = username;
} public Long getId() {
return id;
} public String getUsername() {
return username;
} public void setUsername(String username) {
this.username = username;
} public Set<BillingDetails> getBillingDetails() {
return billingDetails;
} public void setBillingDetails(Set<BillingDetails> billingDetails) {
this.billingDetails = billingDetails;
} // ...
}
5.测试
package org.jpwh.test.inheritance; import org.jpwh.env.JPATest;
import org.jpwh.model.inheritance.associations.onetomany.BankAccount;
import org.jpwh.model.inheritance.associations.onetomany.BillingDetails;
import org.jpwh.model.inheritance.associations.onetomany.CreditCard;
import org.jpwh.model.inheritance.associations.onetomany.User;
import org.testng.annotations.BeforeClass;
import org.testng.annotations.Test; import javax.persistence.EntityManager;
import javax.transaction.UserTransaction; import static org.testng.Assert.assertEquals; public class PolymorphicOneToMany extends JPATest { @Override
public void configurePersistenceUnit() throws Exception {
configurePersistenceUnit("PolymorphicOneToManyPU");
} @Test
public void storeAndLoadItemBids() throws Exception {
UserTransaction tx = TM.getUserTransaction();
try {
tx.begin();
EntityManager em = JPA.createEntityManager(); BankAccount ba = new BankAccount(
"Jane Roe", "445566", "One Percent Bank Inc.", "999"
);
CreditCard cc = new CreditCard(
"John Doe", "1234123412341234", "06", "2015"
);
User johndoe = new User("johndoe"); johndoe.getBillingDetails().add(ba);
ba.setUser(johndoe); johndoe.getBillingDetails().add(cc);
cc.setUser(johndoe); em.persist(ba);
em.persist(cc);
em.persist(johndoe); tx.commit();
em.close(); Long USER_ID = johndoe.getId(); tx.begin();
em = JPA.createEntityManager();
{
User user = em.find(User.class, USER_ID); for (BillingDetails billingDetails : user.getBillingDetails()) {
billingDetails.pay(123);
}
assertEquals(user.getBillingDetails().size(), 2);
} tx.commit();
em.close(); } finally {
TM.rollback();
}
} }
JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-009Polymorphic collections(@OneToMany(mappedBy = "user")、@ManyToOne、)的更多相关文章
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-003Table per concrete class with unions(@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)、<union-subclass>)
一.代码 1. package org.jpwh.model.inheritance.tableperclass; import org.jpwh.model.Constants; import ja ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-002Table per concrete class with implicit polymorphism(@MappedSuperclass、@AttributeOverride)
一.结构 二.代码 1. package org.jpwh.model.inheritance.mappedsuperclass; import javax.persistence.MappedSup ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-006Mixing inheritance strategies(@SecondaryTable、@PrimaryKeyJoinColumn、<join fetch="select">)
一.结构 For example, you can map a class hierarchy to a single table, but, for a particular subclass, s ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-005Table per subclass with joins(@Inheritance(strategy = InheritanceType.JOINED)、@PrimaryKeyJoinColumn、)
一.结构 The fourth option is to represent inheritance relationships as SQL foreign key associations. Ev ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-004Table per class hierarchy(@Inheritance..SINGLE_TABLE)、@DiscriminatorColumn、@DiscriminatorValue、@DiscriminatorFormula)
一.结构 You can map an entire class hierarchy to a single table. This table includes columns for all pr ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-001Hibernate映射继承的方法
There are four different strategies for representing an inheritance hierarchy: Use one table per co ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-008Polymorphic many-to-one associations(@ManyToOne、@Inheritance、)
一.结构 二.代码 1. package org.jpwh.model.inheritance.associations.manytoone; import org.jpwh.model.Consta ...
- JavaPersistenceWithHibernate第二版笔记-第六章-Mapping inheritance-007Inheritance of embeddable classes(@MappedSuperclass、@Embeddable、@AttributeOverrides、、)
一.结构 二.代码 1. package org.jpwh.model.inheritance.embeddable; import javax.persistence.MappedSuperclas ...
- JavaPersistenceWithHibernate第二版笔记-第五章-Mapping value types-007UserTypes的用法(@org.hibernate.annotations.Type、@org.hibernate.annotations.TypeDefs、CompositeUserType、DynamicParameterizedType、、、)
一.结构 二.Hibernate支持的UserTypes接口 UserType —You can transform values by interacting with the plain JD ...
随机推荐
- LeetCode OJ:Sort List(排序链表)
Sort a linked list in O(n log n) time using constant space complexity. 题目要求在常数控件内以O(nlogn)的事件复杂度来排序链 ...
- Mac 下 Mosquitto 安装和配置 (Mosquitto为开源的mqtt服务器)
官网:http://mosquitto.org/download/ 官网的介绍简单明了 Mac 下一个命令“brew install mosquitto” 安装成功了,还学会了brew 安装目录:/u ...
- Smarty的模板中不允许PHP的代码?
/****************************************************************************** * Smarty的模板中不允许PHP的代 ...
- CodeForces - 138C: Mushroom Gnomes - 2 (线段树&概率&排序)
One day Natalia was walking in the woods when she met a little mushroom gnome. The gnome told her th ...
- 3143 codevs 二叉树的序遍历
题目描述 Description 求一棵二叉树的前序遍历,中序遍历和后序遍历 输入描述 Input Description 第一行一个整数n,表示这棵树的节点个数. 接下来n行每行2个整数L和R.第i ...
- RabbitMQ集群 Docker一键部署
以下内容来自网络转载 步骤1. 安装docker 以centos7为例,https://docs.docker.com/engine/installation/linux/centos/ 步骤2. 创 ...
- npm 安装参数中的 --save-dev 是什么意思
看到有些 node.js 的包安装的时候都加上 --save-dev 参数,不知道这参数是做什么的,加和不加有什么区别吗? $ npm install xxx --save-dev 当你为你的模块安装 ...
- 一、Jmeter的安装
一.首先安装Jmeter 1.安装java Jmeter是使用java实现的测试工具,在安装Java之前我们需要安装java. 到这里去下载相应的JDK:https://www.java.com/en ...
- MySQL的瑞士军刀(转)
这里主要讲mysql运维中的一些主要工具,这些工具可能大家都用过,特别是系统管理员或者做linux服务器维护的同学可能都知道这些小工具,这 里讲得会比较多一些,除了系统监控的小工具,还包括一些mysq ...
- WebDriver数据驱动模式
利用@dataprovider 在一个浏览器内多次登录不同的用户时,必须要每次完成一个登录后,都有一个退出登录的代码,以保持和初始登录页面一致,才不会报错并再次循环登录