2017ecjtu-summer training #4 CodeForces 731C
2 seconds
256 megabytes
standard input
standard output
Arseniy is already grown-up and independent. His mother decided to leave him alone for m days and left on a vacation. She have prepared a lot of food, left some money and washed all Arseniy's clothes.
Ten minutes before her leave she realized that it would be also useful to prepare instruction of which particular clothes to wear on each of the days she will be absent. Arseniy's family is a bit weird so all the clothes is enumerated. For example, each of Arseniy's n socks is assigned a unique integer from 1 to n. Thus, the only thing his mother had to do was to write down two integers li and ri for each of the days — the indices of socks to wear on the day i (obviously, li stands for the left foot and ri for the right). Each sock is painted in one of kcolors.
When mother already left Arseniy noticed that according to instruction he would wear the socks of different colors on some days. Of course, that is a terrible mistake cause by a rush. Arseniy is a smart boy, and, by some magical coincidence, he posses k jars with the paint — one for each of k colors.
Arseniy wants to repaint some of the socks in such a way, that for each of m days he can follow the mother's instructions and wear the socks of the same color. As he is going to be very busy these days he will have no time to change the colors of any socks so he has to finalize the colors now.
The new computer game Bota-3 was just realised and Arseniy can't wait to play it. What is the minimum number of socks that need their color to be changed in order to make it possible to follow mother's instructions and wear the socks of the same color during each of m days.
The first line of input contains three integers n, m and k (2 ≤ n ≤ 200 000, 0 ≤ m ≤ 200 000, 1 ≤ k ≤ 200 000) — the number of socks, the number of days and the number of available colors respectively.
The second line contain n integers c1, c2, ..., cn (1 ≤ ci ≤ k) — current colors of Arseniy's socks.
Each of the following m lines contains two integers li and ri (1 ≤ li, ri ≤ n, li ≠ ri) — indices of socks which Arseniy should wear during the i-th day.
Print one integer — the minimum number of socks that should have their colors changed in order to be able to obey the instructions and not make people laugh from watching the socks of different colors.
3 2 3
1 2 3
1 2
2 3
2
3 2 2
1 1 2
1 2
2 1
0
In the first sample, Arseniy can repaint the first and the third socks to the second color.
In the second sample, there is no need to change any colors.
题意:给出n只袜子的,最多k个颜色,m天,每天都要穿某两只袜子,不能让某一天穿不同颜色的袜子,问至少改变多少只袜子的颜色。
思路:把要在同一天穿的袜子用并查集放到一起,然后找出最多的那种颜色,size-max即为这堆袜子至少要改的次数。把每堆要改变的次数都加起来就是答案。
AC代码
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
#include <vector>
#include <stack>
#include <map>
using namespace std;
#define maxn 200010
int pre[maxn];
int c[maxn];
int num[maxn];
vector<int> f[maxn];
long long ans=;
int find(int x)
{
if(x!=pre[x])
pre[x]=find(pre[x]);
return pre[x];
}
void mix(int x,int y)
{
int x1=find(x),y1=find(y);
if(x1!=y1)
pre[x1]=y1;
}
int main()
{
int n,m,k;
int i,j;
cin>>n>>m>>k;
for(i=;i<=n;i++)
{
cin>>c[i];
pre[i]=i;
}
int a,b;
for(i=;i<m;i++)
{
cin>>a>>b;
mix(a,b);
}
int xu=;
for(i=; i<=n; i++)
{
if(pre[i]==i)
num[i]=++xu;
}
for(i=; i<=n; i++)
{
f[num[find(i)]].push_back(c[i]);
}
for(i=; i<=xu; i++)
{
int ma=;
int len=f[i].size();
map<int,int>x;
for(j=; j<len; j++)
{
x[f[i][j]]++;
ma=max(ma,x[f[i][j]]);
}
ans+=(len-ma);
}
cout<<ans<<endl;
return ;
}
2017ecjtu-summer training #4 CodeForces 731C的更多相关文章
- Codeforces 731C Socks 并查集
题目:http://codeforces.com/contest/731/problem/C 思路:并查集处理出哪几堆袜子是同一颜色的,对于每堆袜子求出出现最多颜色的次数,用这堆袜子的数目减去该值即为 ...
- Codeforces 731C:Socks(并查集)
http://codeforces.com/problemset/problem/731/C 题意:有n只袜子,m天,k个颜色,每个袜子有一个颜色,再给出m天,每天有两只袜子,每只袜子可能不同颜色,问 ...
- codeforces 731C(DFS)
题目链接:http://codeforces.com/contest/731/problem/C 题意:有n只袜子(1~n),k种颜色(1~k),在m天中,左脚穿下标为l,右脚穿下标为r的袜子,问最少 ...
- Codeforces 731C. Socks 联通块
C. Socks time limit per test: 2 seconds memory limit per test: 256 megabytes input: standard input o ...
- CodeForces 731C Socks
http://codeforces.com/problemset/problem/731/C 并查集+贪心 将要求颜色相同的袜子序号放入一个集合中 贪心:然后统计这个集合中出现次数最多但颜色 可以得到 ...
- HZNU 2019 Summer training 6 -CodeForces - 622
A - Infinite Sequence CodeForces - 622A 题目大意:给你一个这样的数列1,1,2,1,2,3,1,2,3,4,1,2,3,4,5....就是从1~n排列(n++ ...
- 2017ecjtu-summer training #2 CodeForces 608B
B. Hamming Distance Sum time limit per test 2 seconds memory limit per test 256 megabytes input stan ...
- CodeForces 731C C - Socks 并查集
Description Arseniy is already grown-up and independent. His mother decided to leave him alone for m ...
- CodeForces 731C Socks (DFS或并查集)
题意:有n只袜子,k种颜色,在m天中,问最少修改几只袜子的颜色,可以使每天穿的袜子左右两只都同颜色. 析:很明显,每个连通块都必须是同一种颜色,然后再统计最多颜色的就好了,即可以用并查集也可以用DFS ...
随机推荐
- iOS 控制器的跳转、页面四个方向的跳转
指定滑动方向的跳转 CATransition *transition = [CATransition animation]; transition.duration = 0.3f; transitio ...
- CET——4 常用短语
在网上看到的,先拔到自己这来,四级大大,求过!!!!
- 自定义bootstrap样式-9行样式自定义漂亮大气bootstrap导航栏
有人说前端发展太快,框架太多,各有所需,各有所长.看看这幅图,估计都知道这些框架,但是大部分公司中实际要用到的也就那么几个. 发展再快,框架再多.还是得回到原点,不就是Html+Css+JavaScr ...
- js功能代码大全
1.日期格式化 //化为2017-08-14 function formatDate (date) { var y = date.getFullYear(); var m = date.getMont ...
- 3、树莓派的配置:改静态IP、连接ssh、安装中文字体、安装谷歌输入法、增加USB电流、修改触摸屏分辨率、扩展sd卡空间、修复vi和vim乱码问题、安装配置远程桌面vnc
本博文仅作本人操作过程的记录,留作备忘.自强不息 QQ1222698 1.连接上HDMI线,插上触摸屏,插上键盘,鼠标,网线,启动.系统正常启动,但是一直闪烁,不停的黑屏,是由于触摸屏的usb口供电不 ...
- python (5分钟实现一个游戏的屏蔽敏感字系统,)
import datetime time=datetime.datetime.now() dirty= ['fuck','狗日的','犊子','麻批','仙人板板','R你妈','操你','草你',' ...
- 使用图片地图减少HTTP请求数量
前言 最近在看<高性能网站建设>,记录一下所学. 现在很多网站都是图片形式的导航,点击图片跳转到对应的链接.如果导航项目很多的话,图片的数量就会很多,每需要加载一张图片就会多一个HTTP请 ...
- Git详解之四:服务器上的Git
服务器上的 Git 到目前为止,你应该已经学会了使用 Git 来完成日常工作.然而,如果想与他人合作,还需要一个远程的 Git 仓库.尽管技术上可以从个人的仓库里推送和拉取修改内容,但我们不鼓励这样做 ...
- 测试库的接收到的数据是否完整(jrtplib为列)
最近使用jrtplib来接收RTP包,然后解码播放 发现解码出来的是绿屏,马赛克 于是开始排查 首先直接用wireshark抓进来的包,转为可以被vlc播放的文件 操作如下 http://blog.c ...
- Head First设计模式之生成器模式
一.定义 将一个复杂对象的构建与它的表示分离,使得同样的构建过程可以创建不同的表示.建造者模式是一种对象创建型模式. 二.结构 角色 Builder(抽象建造者):它为创建一个产品Product对象的 ...